Making RGB color in Xcode

I am using RGB values of a color from Photoshop and using the same in Xcode the values are.Color-R-160,G-97,B-5...the color in Photoshop appears yellowish but in Xcode when I used

myLabel.textColor = [UIColor colorWithRed:160 green:97 blue:5 alpha:1] ;

the color appears whitish.

Why this difference is happening?

Objective-C

You have to give the values between 0 and 1.0. So divide the RGB values by 255.

myLabel.textColor= [UIColor colorWithRed:(160/255.0) green:(97/255.0) blue:(5/255.0) alpha:1] ;

Update:

You can also use this macro

#define Rgb2UIColor(r, g, b)  [UIColor colorWithRed:((r) / 255.0) green:((g) / 255.0) blue:((b) / 255.0) alpha:1.0]

and you can call in any of your class like this

 myLabel.textColor = Rgb2UIColor(160, 97, 5);

Swift

This is the normal color synax

myLabel.textColor = UIColor(red: (160/255.0), green: (97/255.0), blue: (5/255.0), alpha: 1.0) 
//The values should be between 0 to 1

Swift is not much friendly with macros

> Complex macros are used in C and Objective-C but have no counterpart > in Swift. Complex macros are macros that do not define constants, > including parenthesized, function-like macros. You use complex macros > in C and Objective-C to avoid type-checking constraints or to avoid > retyping large amounts of boilerplate code. However, macros can make > debugging and refactoring difficult. In Swift, you can use functions > and generics to achieve the same results without any compromises. > Therefore, the complex macros that are in C and Objective-C source > files are not made available to your Swift code.

So we use extension for this

extension UIColor {
    convenience init(_ r: Double,_ g: Double,_ b: Double,_ a: Double) {
        self.init(red: r/255, green: g/255, blue: b/255, alpha: a)
    }
}

You can use it like

myLabel.textColor = UIColor(160.0, 97.0, 5.0, 1.0)

You already got the right answer, but if you dislike the UIColor interface like me, you can do this:

#import "UIColor+Helper.h"
// ...
myLabel.textColor = [UIColor colorWithRGBA:0xA06105FF];

UIColor+Helper.h:

#import <UIKit/UIKit.h>

@interface UIColor (Helper)
+ (UIColor *)colorWithRGBA:(NSUInteger)color;
@end

UIColor+Helper.m:

#import "UIColor+Helper.h"

@implementation UIColor (Helper)

+ (UIColor *)colorWithRGBA:(NSUInteger)color
{
	return [UIColor colorWithRed:((color >> 24) & 0xFF) / 255.0f
						   green:((color >> 16) & 0xFF) / 255.0f
							blue:((color >> 8) & 0xFF) / 255.0f
						   alpha:((color) & 0xFF) / 255.0f];
}

@end

Yeah.ios supports RGB valur to range between 0 and 1 only..its close Range [0,1]

Color picker plugin for Interface Builder

There's a nice color picker from Panic which works well with IB: http://panic.com/~wade/picker/

Xcode plugin

This one gives you a GUI for choosing colors: http://www.youtube.com/watch?v=eblRfDQM0Go

Objective-C

UIColor *color = [UIColor colorWithRed:(160/255.0) green:(97/255.0) blue:(5/255.0) alpha:1.0];

Swift

let color = UIColor(red: 160/255, green: 97/255, blue: 5/255, alpha: 1.0)

Pods and libraries

There's a nice pod named MPColorTools: https://github.com/marzapower/MPColorTools

The values are determined by the bit of the image. 8 bit 0 to 255

16 bit...some ridiculous number..0 to 65,000 approx.

32 bit are 0 to 1

I use .004 with 32 bit images...this gives 1.02 as a result when multiplied by 255