Make error for ifeq: syntax error near unexpected token

Makefile

Makefile Problem Overview


I'm writing a Makefile that does string matching at one place, the code is like:

if test ...; \
    then \
    shell scripts... \
fi

ifeq ($(DIST_TYPE),nightly)
    shell scripts ...
endif

Here the first if is shell script, the second ifeq is GNU Make's conditional. However the following error generates:

> ifeq (nightly,nightly) > > /bin/sh: -c: line 0: syntax error near unexpected token nightly,nightly' > > /bin/sh: -c: line 0: ifeq (nightly,nightly)'

What's happening here? It seems that Make is trying to call the shell.

Makefile Solutions


Solution 1 - Makefile

I played around the code and found that the conditional statements should be written without indentation, and this solved my problem.

If there is no indentation, Make will treat it as a directive for itself; otherwise, it's regarded as a shell script.

Example code

Wrong:

target:
    ifeq (foo, bar)
        ...
    endif

Correct:

target:
ifeq (foo, bar)
    ...
endif

Solution 2 - Makefile

In addition, if the conditional statements is used in define functions, like:

define myFunc
ifeq (foo, bar)
    ...
endif
endef

In this case, Make will also treat it as a shell script.

This problem can be solved by using if-function instead:

define myFunc
    $(if condition,then-part[,else-part])
endef

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRyan LiView Question on Stackoverflow
Solution 1 - MakefileRyan LiView Answer on Stackoverflow
Solution 2 - MakefileSenZhangView Answer on Stackoverflow