list Postgres ENUM type

The suggested query to list ENUM types is great. But, it merely lists of the schema and the typname. How do I list out the actual ENUM values? For example, in the linked answer above, I would want the following result

schema         type      values
-------------  --------  -------
communication  channels  'text_message','email','phone_call','broadcast'

select n.nspname as enum_schema,  
       t.typname as enum_name,  
       e.enumlabel as enum_value
from pg_type t 
   join pg_enum e on t.oid = e.enumtypid  
   join pg_catalog.pg_namespace n ON n.oid = t.typnamespace;

You can list the data type via

\dT+ channels

https://www.postgresql.org/docs/current/static/app-psql.html#APP-PSQL-META-COMMANDS

select enum_range(null::my_enum)

where my_enum is the enum type name.

Documentation: http://www.postgresql.org/docs/9.5/static/functions-enum.html

This: SELECT unnest(enum_range(NULL::myenum)) returns enum types as rows.

I always forget how to do this. As per the other answer and the comment, here it is a comma-separated list. I like copy-paste snippets. Thanks for the help:

select n.nspname as enum_schema,  
    t.typname as enum_name,
    string_agg(e.enumlabel, ', ') as enum_value
from pg_type t 
    join pg_enum e on t.oid = e.enumtypid  
    join pg_catalog.pg_namespace n ON n.oid = t.typnamespace
group by enum_schema, enum_name;

SELECT enum_range(NULL::myenum)

@dpb:

If you want to create a permanent easy access method for this, you could always create a view

CREATE OR REPLACE VIEW oublic.enumz AS 
 SELECT n.nspname AS enum_schema,
  t.typname AS enum_name,
  e.enumlabel AS enum_value
 FROM pg_type t
 JOIN pg_enum e ON t.oid = e.enumtypid
 JOIN pg_namespace n ON n.oid = t.typnamespace;

You could then create a trigger for the insert command.

The above will store this in the database for future reference purposes.

This lists all enum-typed columns and their potential values:

SELECT
  table_schema || '.' || table_name || '.' || column_name as field_name,
  pg_enum.enumlabel as value
FROM pg_type
  JOIN pg_enum ON pg_enum.enumtypid = pg_type.oid
  JOIN pg_namespace on pg_type.typnamespace = pg_namespace.oid
  JOIN information_schema.columns ON (information_schema.columns.udt_name = pg_type.typname AND information_schema.columns.udt_schema = pg_namespace.nspname)
WHERE pg_type.typtype = 'e'
ORDER BY field_name, pg_enum.enumsortorder;

Add order

SELECT
  n.nspname AS enum_schema,
  t.typname AS enum_name,
  e.enumlabel AS enum_value
FROM
  pg_type t
  JOIN pg_enum e ON t.oid = e.enumtypid
  JOIN pg_catalog.pg_namespace n ON n.oid = t.typnamespace
ORDER BY
  enum_name,
  e.enumsortorder;

If you have the table and column name, (but not the type name) use this:

SELECT pg_enum.enumlabel
FROM pg_type
 JOIN pg_enum ON pg_enum.enumtypid = pg_type.oid
 JOIN information_schema.columns ON information_schema.columns.udt_name =
                                    pg_type.typname
WHERE pg_type.typtype = 'e' AND
      table_name = $1 AND column_name = $2 ORDER BY pg_enum.enumsortorder

If you use enum_range on a column (in contrast to the other answers which used it on a type) it will return data for each row that exists, which is not what you want. So use the above query instead.