Linking to an external URL in Javadoc?

JavaUrlJavadocHyperlink

Java Problem Overview


Something like:

/**
 * See {@linktourl http://google.com}
 */

Java Solutions


Solution 1 - Java

This creates a "See Also" heading containing the link, i.e.:

/**
 * @see <a href="http://google.com">http://google.com</a>
 */

will render as:

> See Also:
>            http://google.com

whereas this:

/**
 * See <a href="http://google.com">http://google.com</a>
 */

will create an in-line link:

> See http://google.com

Solution 2 - Java

Taken from the javadoc spec

@see <a href="URL#value">label</a> : Adds a link as defined by URL#value. The URL#value is a relative or absolute URL. The Javadoc tool distinguishes this from other cases by looking for a less-than symbol (<) as the first character.

For example : @see <a href="http://www.google.com">Google</a>

Solution 3 - Java

Javadocs don't offer any special tools for external links, so you should just use standard html:

See <a href="http://groversmill.com/">Grover's Mill</a> for a history of the
Martian invasion.

or

@see <a href="http://groversmill.com/">Grover's Mill</a> for a history of 
the Martian invasion.

Don't use {@link ...} or {@linkplain ...} because these are for links to the javadocs of other classes and methods.

Solution 4 - Java

Hard to find a clear answer from the Oracle site. The following is from javax.ws.rs.core.HttpHeaders.java:

/**
 * See {@link <a href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec14.html#sec14.1">HTTP/1.1 documentation</a>}.
 */
public static final String ACCEPT = "Accept";

/**
 * See {@link <a href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec14.html#sec14.2">HTTP/1.1 documentation</a>}.
 */
public static final String ACCEPT_CHARSET = "Accept-Charset";

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionripper234View Question on Stackoverflow
Solution 1 - Javaaem999View Answer on Stackoverflow
Solution 2 - JavaAaronView Answer on Stackoverflow
Solution 3 - JavaOrlando DFreeView Answer on Stackoverflow
Solution 4 - JavaQiang LiView Answer on Stackoverflow