Kotlin equivalent of Java's equalsIgnoreCase

What is the equivalent of Java equalsIgnoreCase in Kotlin to compare String values?

I have used equals but it's not case insensitive.

You can use equals but specify ignoreCase parameter:

"example".equals("EXAMPLE", ignoreCase = true)

As per the Kotlin Documentation :

fun String?.equals(
    other: String?, 
    ignoreCase: Boolean = false
): Boolean

> https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.text/equals.html

For Example:

> val name: String = "Hitesh" > when{ > name.equals("HITESH", true) -> { > // DO SOMETHING > } > }

@hluhovskyi's answer is correct, however to use it on EditText or TextView, use following -

etPassword.text.toString().equals(etConfirmPassword.text.toString(), ignoreCase = true)

Normally, you don't need to find alternatives since Kotlin reuses existing Java types like String. Actually, these types are mapped to Kotlin internal types. In the case of String it looks like this:

java.lang.String -> kotlin.String

Therefore, the desired method equalsIgnoreCase would only be available if it was also provided in kotlin.String, which isn’t. The Kotlin designers decided to provide a more generic equals function that let's you specify the case insensitivity with a boolean parameter.

You can use the Java String class at any time if that's really necessary (it's not recommended, IntelliJ will complain about this):

("hello" as java.lang.String).equalsIgnoreCase("Hello")

With the help of an extension function, we could even add the functionality to the kotlin.String class:

fun String.equalsIgnoreCase(other: String) = 
    (this as java.lang.String).equalsIgnoreCase(other)

In my case,

string1.contains(string2, ignoreCase = true)

This worked for me. Becase I'm using like a search function here.