json_decode to custom class

PhpJson

Php Problem Overview


Is it possible to decode a json string to an object other than stdClass?

Php Solutions


Solution 1 - Php

Not automatically. But you can do it the old fashioned route.

$data = json_decode($json, true);

$class = new Whatever();
foreach ($data as $key => $value) $class->{$key} = $value;

Or alternatively, you could make that more automatic:

class Whatever {
    public function set($data) {
        foreach ($data AS $key => $value) $this->{$key} = $value;
    }
}

$class = new Whatever();
$class->set($data);

Edit: getting a little fancier:

class JSONObject {
    public function __construct($json = false) {
        if ($json) $this->set(json_decode($json, true));
    }
    
    public function set($data) {
        foreach ($data AS $key => $value) {
            if (is_array($value)) {
                $sub = new JSONObject;
                $sub->set($value);
                $value = $sub;
            }
            $this->{$key} = $value;
        }
    }
}

// These next steps aren't necessary. I'm just prepping test data.
$data = array(
    "this" => "that",
    "what" => "who",
    "how" => "dy",
    "multi" => array(
        "more" => "stuff"
    )
);
$jsonString = json_encode($data);

// Here's the sweetness.
$class = new JSONObject($jsonString);
print_r($class);

Solution 2 - Php

We built JsonMapper to map JSON objects onto our own model classes automatically. It works fine with nested/child objects.

It only relies on docblock type information for mapping, which most class properties have anyway:

<?php
$mapper = new JsonMapper();
$contactObject = $mapper->map(
    json_decode(file_get_contents('http://example.org/contact.json')),
    new Contact()
);
?>

Solution 3 - Php

You can do it - it's a kludge but totally possible. We had to do when we started storing things in couchbase.

$stdobj = json_decode($json_encoded_myClassInstance);  //JSON to stdClass
$temp = serialize($stdobj);                   //stdClass to serialized

// Now we reach in and change the class of the serialized object
$temp = preg_replace('@^O:8:"stdClass":@','O:7:"MyClass":',$temp);

// Unserialize and walk away like nothing happend
$myClassInstance = unserialize($temp);   // Presto a php Class 

In our benchmarks this was way faster than trying to iterate through all the class variables.

Caveat: Won't work for nested objects other than stdClass

Edit: keep in mind the data source, it's strongly recommended that you don't do this withe untrusted data from users without a very carful analysis of the risks.

Solution 4 - Php

You could use Johannes Schmitt's Serializer library.

$serializer = JMS\Serializer\SerializerBuilder::create()->build();
$object = $serializer->deserialize($jsonData, 'MyNamespace\MyObject', 'json');

In the latest version of the JMS serializer the syntax is:

$serializer = SerializerBuilder::create()->build();
$object = $serializer->deserialize($jsonData, MyObject::class, 'json');

Solution 5 - Php

I'm surprised no one mentioned this, yet.

Use the Symfony Serializer component: https://symfony.com/doc/current/components/serializer.html

Serializing from Object to JSON:

use App\Model\Person;

$person = new Person();
$person->setName('foo');
$person->setAge(99);
$person->setSportsperson(false);

$jsonContent = $serializer->serialize($person, 'json');

// $jsonContent contains {"name":"foo","age":99,"sportsperson":false,"createdAt":null}

echo $jsonContent; // or return it in a Response

Deserializing from JSON to Object: (this example uses XML just to demonstrate the flexibility of formats)

use App\Model\Person;

$data = <<<EOF
<person>
    <name>foo</name>
    <age>99</age>
    <sportsperson>false</sportsperson>
</person>
EOF;

$person = $serializer->deserialize($data, Person::class, 'xml');

Solution 6 - Php

You can do it in below way ..

<?php
class CatalogProduct
{
    public $product_id;
    public $sku;
    public $name;
    public $set;
    public $type;
    public $category_ids;
    public $website_ids;

    function __construct(array $data) 
    {
        foreach($data as $key => $val)
        {
            if(property_exists(__CLASS__,$key))
            {
                $this->$key =  $val;
            }
        }
    }
}

?>

For more details visit create-custom-class-in-php-from-json-or-array

Solution 7 - Php

You can make a wrapper for your object and make the wrapper look like it is the object itself. And it will work with multilevel objects.

<?php
class Obj
{
	public $slave;
	
    public function __get($key) {
		return property_exists ( $this->slave ,  $key ) ? $this->slave->{$key} : null;
    }

    public function __construct(stdClass $slave)
	{
    	$this->slave = $slave;
	}
}

$std = json_decode('{"s3":{"s2":{"s1":777}}}');

$o = new Obj($std);

echo $o->s3->s2->s1; // you will have 777

Solution 8 - Php

No, this is not possible as of PHP 5.5.1.

The only thing possible is to have json_decode return associate arrays instead of the StdClass objects.

Solution 9 - Php

Use Reflection:

function json_decode_object(string $json, string $class)
{
	$reflection = new ReflectionClass($class);
	$instance = $reflection->newInstanceWithoutConstructor();
	$json = json_decode($json, true);
	$properties = $reflection->getProperties();
	foreach ($properties as $key => $property) {
		$property->setAccessible(true);
		$property->setValue($instance, $json[$property->getName()]);
	}
	return $instance;
}

Solution 10 - Php

I once created an abstract base class for this purpose. Let's call it JsonConvertible. It should serialize and deserialize the public members. This is possible using Reflection and late static binding.

abstract class JsonConvertible {
   static function fromJson($json) {
       $result = new static();
       $objJson = json_decode($json);
       $class = new \ReflectionClass($result);
       $publicProps = $class->getProperties(\ReflectionProperty::IS_PUBLIC);
       foreach ($publicProps as $prop) {
            $propName = $prop->name;
            if (isset($objJson->$propName) {
                $prop->setValue($result, $objJson->$propName);
            }
            else {
                $prop->setValue($result, null);
            }
       }
       return $result;
   }
   function toJson() {
      return json_encode($this);
   }
} 

class MyClass extends JsonConvertible {
   public $name;
   public $whatever;
}
$mine = MyClass::fromJson('{"name": "My Name", "whatever": "Whatever"}');
echo $mine->toJson();

Just from memory, so probably not flawless. You will also have to exclude static properties and may give derived classes the chance to make some properties ignored when serialized to/from json. I hope you get the idea, nonetheless.

Solution 11 - Php

As Gordon says is not possible. But if you are looking for a way to obtain a string that can be decoded as an instance of a give class you can use serialize and unserialize instead.

class Foo
{

    protected $bar = 'Hello World';

    function getBar() {
        return $this->bar;
    }

}

$string = serialize(new Foo);

$foo = unserialize($string);
echo $foo->getBar();

Solution 12 - Php

JSON is a simple protocol to transfer data between various programming languages (and it's also a subset of JavaScript) which supports just certain types: numbers, strings, arrays/lists, objects/dicts. Objects are just key=value maps and Arrays are ordered lists.

So there is no way to express custom objects in a generic way. The solution is defining a structure where your program(s) will know that it's a custom object.

Here's an example:

{ "cls": "MyClass", fields: { "a": 123, "foo": "bar" } }

This could be used to create an instance of MyClass and set the fields a and foo to 123 and "bar".

Solution 13 - Php

I went ahead and implemented John Petit's answer, as a function(gist):

function json_decode_to(string $json, string $class = stdClass::class, int $depth = 512, int $options = 0)
{
    $stdObj = json_decode($json, false, $depth, $options);
    if ($class === stdClass::class) return $stdObj;

    $count = strlen($class);
    $temp = serialize($stdObj);
    $temp = preg_replace("@^O:8:\"stdClass\":@", "O:$count:\"$class\":", $temp);
    return unserialize($temp);  
}

This worked perfectly for my use case. However Yevgeniy Afanasyev's response seems equally promising to me. It could be possible to have your class have an extra "constructor", like so:

public static function withJson(string $json) {
    $instance = new static();
    // Do your thing
    return $instance;
}

This is also inspired by this answer.

EDIT: I have been using karriereat/json-decoder for some time now, and I have had absolutely no trouble with it. It is lightweight and very easily extensible. Here's an example of a binding I wrote to deserialize JSON into a Carbon/CarbonImmutable object.

Solution 14 - Php

All this here inspired me to a generic function:

function loadJSON($Obj, $json)
{
     $dcod = json_decode($json);
     $prop = get_object_vars ( $dcod );
     foreach($prop as $key => $lock)
     {
	    if(property_exists ( $Obj ,  $key ))
	    {
		    if(is_object($dcod->$key))
		    {
			    loadJSON($Obj->$key, json_encode($dcod->$key));
		    }
		    else
		    {
			    $Obj->$key = $dcod->$key;
		    }
	    }
    }
}

to be called in class declaration:

class Bar{public $bar = " Boss";}
class Bas
{
    public $ber ;
    public $bas=" Boven"; 
    public function __construct() 
        {$this->ber = new Bar;}
}
class Baz
{
    public $bes ;
    public $baz=" Baaz";  
    public function __construct() 
        {$this->bes = new Bas;}
}

$Bazjson = '{"bes":{"ber":{"bar":"Baas"}}}';

$Bazobj = new Baz;

loadJSON($Bazobj, $Bazjson);
var_dump($Bazobj);

Solution 15 - Php

This worked for me, especially for if you don't have setters or named properties in the target class

function cast($jsonstring, $class)
{
   //$class is a string like 'User'

    $json= json_decode($jsonstring,true);  //array
   
    $reflection = new ReflectionClass($class);
    $instance = $reflection->newInstanceWithoutConstructor();
    $keys = array_keys($json);

    foreach ($keys  as $key => $property) {
        $instance->{$property} =$json[$property];
    }

   // print_r($instance);

    return $instance;
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTomView Question on Stackoverflow
Solution 1 - PhpMichael McTiernanView Answer on Stackoverflow
Solution 2 - PhpcweiskeView Answer on Stackoverflow
Solution 3 - PhpJohn PettittView Answer on Stackoverflow
Solution 4 - PhpMalachiView Answer on Stackoverflow
Solution 5 - PhpLucas BustamanteView Answer on Stackoverflow
Solution 6 - PhpjigarshahindiaView Answer on Stackoverflow
Solution 7 - PhpYevgeniy AfanasyevView Answer on Stackoverflow
Solution 8 - PhpGordonView Answer on Stackoverflow
Solution 9 - Phpluke23489View Answer on Stackoverflow
Solution 10 - PhpklawipoView Answer on Stackoverflow
Solution 11 - PhpFrancesco TerenzaniView Answer on Stackoverflow
Solution 12 - PhpThiefMasterView Answer on Stackoverflow
Solution 13 - PhpPeter LenjoView Answer on Stackoverflow
Solution 14 - PhpGreald HenstraView Answer on Stackoverflow
Solution 15 - PhpHenry NkukeView Answer on Stackoverflow