jQuery get position of element relative to another element

So I have a div like:

<div class="uiGrid">

<div class="trigger"></div>

</div>

And I want to know the position of trigger to uiGrid and have tried both these:

$('.trigger').offset('.uiGrid');

$('.trigger').position('.uiGrid');

but neither get it. Offset is relative to the document and position is relative to the parent and not the specified element.

How would I do this? Thanks

just do the subtraction your self...

var relativeY = $("elementA").offset().top - $("elementB").offset().top;

what you can do here is basically, subtract parent property value from child property value.

var x = $('child-div').offset().top - $('parent-div').offset().top;

You're missing the point here....

Besides that, try:

myPosY = $('.trigger').offset().left - $('.uiGrid').offset().left;
myPosX = $('.trigger').offset().top - $('.uiGrid').offset().top;

The problem for me was the fact that I was in a div with a scrollbar and that I had to be able to take into account the hidden part down to the root element.

If I use ".offset()" it gave me wrong values, because it does not take into consideration the hide part of scrollbar as it is relative to the document.

However, I realized that the ".offsetTop" property relative to its first parent positioned (offsetParent) was always correct. So I made a loop to go recursively to the root element by additionning the values of ".offsetTop":

I did my own jquery function for that:

jQuery.fn.getOffsetTopFromRootParent = function () {
    let elem = this[0];
    let offset = 0;
    while (elem.offsetParent != null) {
        offset += elem.offsetTop;
        elem = $(elem.offsetParent)[0];
        if (elem.offsetParent === null) {
            offset += elem.offsetTop;
        }
    }
    return offset;
};

You can use the same with ".offsetLeft" I suppose...

If you want to get position of element relative to another element to answer the question:

let fromElem = $("#fromElemID")[0];
let offset = 0;
while (fromElem.id.toUpperCase() != "toElemID".toUpperCase()) {
    offset += fromElem.offsetTop;
    fromElem = $(fromElem.offsetParent)[0];
}
return offset;

> An element (offsetParent) is said to be positioned if it has a CSS > position attribute of relative, absolute, or fixed.