JPA Criteria Query API and order by two columns
JavaJpaSql Order-ByCriteria ApiJava Problem Overview
I'm stuck with a simple problem; struggling how to invoke order by
on a join
ed entity. Essentially I am trying to achieve the following with JPA Criteria
:
select distinct d from Department d
left join fetch d.children c
left join fetch c.appointments a
where d.parent is null
order by d.name, c.name
I have the following:
CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
CriteriaQuery<Department> c = cb.createQuery(Department.class);
Root<Department> root = c.from(Department.class);
Fetch<Department, Department> childrenFetch = root.fetch(
Department_.children, JoinType.LEFT);
childrenFetch.fetch(Department_.appointments, JoinType.LEFT);
c.orderBy(cb.asc(root.get(Department_.name)));
c.distinct(true);
c.select(root);
c.where(cb.isNull(root.get(Department_.parent)));
How to achieve order by d.name, c.name
with Criteria API
? I tried with Expression
Java Solutions
Solution 1 - Java
If you need to add couple of orders you can make something like (but for your query and different root objects)
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<Route> query = criteriaBuilder.createQuery(Route.class);
Root<Route> routeRoot = query.from(Route.class);
query.select(routeRoot);
List<Order> orderList = new ArrayList();
query.where(routeRoot.get("owner").in(user));
orderList.add(criteriaBuilder.desc(routeRoot.get("date")));
orderList.add(criteriaBuilder.desc(routeRoot.get("rating")));
query.orderBy(orderList);
Solution 2 - Java
I have the same problem with order by using Criteria API. I found this solution:
CriteriaQuery<Test> q = cb.createQuery(Test.class);
Root<Test> c = q.from(Test.class);
q.select(c);
q.orderBy(cb.asc(c.get("name")), cb.desc(c.get("prenom")));
Solution 3 - Java
I was having trouble doing the same, and I have found a solution on this page: http://www.objectdb.com/api/java/jpa/criteria/CriteriaQuery/orderBy_Order_
//javax.persistence.criteria.CriteriaQuery
//CriteriaQuery<T> orderBy(Order... o)
>Specify the ordering expressions that are used to order the query results. Replaces the previous ordering expressions, if any. If no ordering expressions are specified, the previous ordering, if any, is simply removed, and results will be returned in no particular order. The left-to-right sequence of the ordering expressions determines the precedence, whereby the leftmost has highest precedence. > >Parameters: > o - zero or more ordering expressions > >Returns: > the modified query > >Since: > JPA 2.0
Solution 4 - Java
The solucion that work for me is the following
session=HibernateUtil.getSessionJavaConfigFactory_report().openSession();
CriteriaBuilder builder = session.getCriteriaBuilder();
CriteriaQuery<Object[]> criteriaQuery = builder.createQuery(Object[].class);
List<Order> orderList = new ArrayList();
orderList.add(builder.desc(ejeRoot.get("name")));
criteriaQuery.orderBy(orderList);
Note: ejeRoot is the class object
Solution 5 - Java
categoryRepository.findAll(predicates, new Sort(Direction.ASC, "sortOrder", "name")) .forEach(categoryDtoList::add);