Join a list of strings in python and wrap each string in quotation marks
PythonStringListPython Problem Overview
I've got:
words = ['hello', 'world', 'you', 'look', 'nice']
I want to have:
'"hello", "world", "you", "look", "nice"'
What's the easiest way to do this with Python?
Python Solutions
Solution 1 - Python
Update 2021: With f strings in Python3
>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> ', '.join(f'"{w}"' for w in words)
'"hello", "world", "you", "look", "nice"'
Original Answer (Supports Python 2.6+)
>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> ', '.join('"{0}"'.format(w) for w in words)
'"hello", "world", "you", "look", "nice"'
Solution 2 - Python
You can try this :
str(words)[1:-1]
Solution 3 - Python
you may also perform a single format
call
>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> '"{0}"'.format('", "'.join(words))
'"hello", "world", "you", "look", "nice"'
Update: Some benchmarking (performed on a 2009 mbp):
>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.32559704780578613
>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(words))""").timeit(1000)
0.018904924392700195
So it seems that format
is actually quite expensive
Update 2: following @JCode's comment, adding a map
to ensure that join
will work, Python 2.7.12
>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.08646488189697266
>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.04855608940124512
>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.17348504066467285
>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.06372308731079102
Solution 4 - Python
>>> ', '.join(['"%s"' % w for w in words])
Solution 5 - Python
An updated version of @jamylak answer with F Strings (for python 3.6+), I've used backticks for a string used for a SQL script.
keys = ['foo', 'bar' , 'omg']
', '.join(f'`{k}`' for k in keys)
# result: '`foo`, `bar`, `omg`'
Solution 6 - Python
find a faster way
'"' + '","'.join(words) + '"'
test in Python 2.7:
words = ['hello', 'world', 'you', 'look', 'nice']
print '"' + '","'.join(words) + '"'
print str(words)[1:-1]
print '"{0}"'.format('", "'.join(words))
t = time() * 1000
range10000 = range(100000)
for i in range10000:
'"' + '","'.join(words) + '"'
print time() * 1000 - t
t = time() * 1000
for i in range10000:
str(words)[1:-1]
print time() * 1000 - t
for i in range10000:
'"{0}"'.format('", "'.join(words))
print time() * 1000 - t
The resulting output is:
# "hello", "world", "you", "look", "nice"
# 'hello', 'world', 'you', 'look', 'nice'
# "hello", "world", "you", "look", "nice"
# 39.6000976562
# 166.892822266
# 220.110839844