Javascript: what's the point of RegExp.compile()?
JavascriptRegexCompilationJavascript Problem Overview
I've got a situation where I want to get a regexp from the user and run it against a few thousand input strings. In the manual I found that the RegExp
object has a .compile()
method which is used to speed things up ins such cases. But why do I have to pass the regexp string to it again if I already passed them in the constructor? Perhaps constructor does the compile()
itself?
Javascript Solutions
Solution 1 - Javascript
The RegExp().compile()
method is deprecated. It's basically the same as the constructor, which I assume is why it was deprecated. You should only have to use the constructor nowadays.
In other words, you used to be able to do this:
var regexp = new RegExp("pattern");
regexp.compile("new pattern");
But nowadays it is not any different from simply calling:
var regexp = new RegExp("pattern");
regexp = new RegExp("new pattern");
Solution 2 - Javascript
And with Opera 11, running RegExp.compile()
will actually cause errors.
Evidently, when Opera "compiles" a regex, it wraps the re.source
string in forward slashes (e.g. re.source == "^(.)"
becomes "/^(.)/"
). If you manually compile the regex, Opera doesn't recognize this fact and goes ahead and compiles it again (re.source
becomes "//^(.)//"
). Each compile results in an extra set of forward slashes, which changes the meaning of the regular expression and results in errors.
Solution 3 - Javascript
You have to compile your regex first to use it if you are using /
, try this out:
var regex=new RegExp('/[a-zA-Z]/')
console.log("not compiled with escape /", regex.test("ciao") )
regex.compile()
console.log("compiled", regex.test("ciao") )
var regex=new RegExp('[a-zA-Z]')
console.log("not compiled, but no escape /", regex.test("ciao") )
Solution 4 - Javascript
As far as i can tell all RegExp.compile does is replace the underlying regular expression of a RegExp object. I think compile may have had value in the past, but all modern JS engines "compile" the regex on first call and cache that "compiled" version.