Javascript return number of days,hours,minutes,seconds between two dates
JavascriptDatetimeJavascript Problem Overview
Does anyone can link me to some tutorial where I can find out how to return days , hours , minutes, seconds in javascript between 2 unix datetimes?
I have:
var date_now = unixtimestamp;
var date_future = unixtimestamp;
I would like to return (live) how many days,hours,minutes,seconds left from the date_now to the date_future.
Javascript Solutions
Solution 1 - Javascript
Just figure out the difference in seconds (don't forget JS timestamps are actually measured in milliseconds) and decompose that value:
// get total seconds between the times
var delta = Math.abs(date_future - date_now) / 1000;
// calculate (and subtract) whole days
var days = Math.floor(delta / 86400);
delta -= days * 86400;
// calculate (and subtract) whole hours
var hours = Math.floor(delta / 3600) % 24;
delta -= hours * 3600;
// calculate (and subtract) whole minutes
var minutes = Math.floor(delta / 60) % 60;
delta -= minutes * 60;
// what's left is seconds
var seconds = delta % 60; // in theory the modulus is not required
EDIT code adjusted because I just realised that the original code returned the total number of hours, etc, not the number of hours left after counting whole days.
Solution 2 - Javascript
Here's in javascript: (For example, the future date is New Year's Day)
DEMO (updates every second)
var dateFuture = new Date(new Date().getFullYear() +1, 0, 1);
var dateNow = new Date();
var seconds = Math.floor((dateFuture - (dateNow))/1000);
var minutes = Math.floor(seconds/60);
var hours = Math.floor(minutes/60);
var days = Math.floor(hours/24);
hours = hours-(days*24);
minutes = minutes-(days*24*60)-(hours*60);
seconds = seconds-(days*24*60*60)-(hours*60*60)-(minutes*60);
Solution 3 - Javascript
I call it the "snowman ☃ method" and I think it's a little more flexible when you need additional timespans like weeks, moths, years, centuries... and don't want too much repetitive code:
var d = Math.abs(date_future - date_now) / 1000; // delta
var r = {}; // result
var s = { // structure
year: 31536000,
month: 2592000,
week: 604800, // uncomment row to ignore
day: 86400, // feel free to add your own row
hour: 3600,
minute: 60,
second: 1
};
Object.keys(s).forEach(function(key){
r[key] = Math.floor(d / s[key]);
d -= r[key] * s[key];
});
// for example: {year:0,month:0,week:1,day:2,hour:34,minute:56,second:7}
console.log(r);
Have a FIDDLE / ES6 Version (2018) / TypeScript Version (2019)
Inspired by Alnitak's answer.
Solution 4 - Javascript
Please note that calculating only based on differences will not cover all cases: leap years and switching of "daylight savings time".
Javascript has poor built-in library for working with dates. I suggest you use a third party javascript library, e.g. MomentJS; you can see here the function you were looking for.
Solution 5 - Javascript
my solution is not as clear as that, but I put it as another example
console.log(duration('2019-07-17T18:35:25.235Z', '2019-07-20T00:37:28.839Z'));
function duration(t0, t1){
let d = (new Date(t1)) - (new Date(t0));
let weekdays = Math.floor(d/1000/60/60/24/7);
let days = Math.floor(d/1000/60/60/24 - weekdays*7);
let hours = Math.floor(d/1000/60/60 - weekdays*7*24 - days*24);
let minutes = Math.floor(d/1000/60 - weekdays*7*24*60 - days*24*60 - hours*60);
let seconds = Math.floor(d/1000 - weekdays*7*24*60*60 - days*24*60*60 - hours*60*60 - minutes*60);
let milliseconds = Math.floor(d - weekdays*7*24*60*60*1000 - days*24*60*60*1000 - hours*60*60*1000 - minutes*60*1000 - seconds*1000);
let t = {};
['weekdays', 'days', 'hours', 'minutes', 'seconds', 'milliseconds'].forEach(q=>{ if (eval(q)>0) { t[q] = eval(q); } });
return t;
}
Solution 6 - Javascript
A Little bit different flavour (maybe for some ppl more readable) it works in JavaScript and as little bonus it works in TypeScript as well.
If you make sure the first date is always greater than the second than you don't need the Math.abs() Also the round brackets around the modulo operation are unnecessary. I kept them for clearance.
let diffTime = Math.abs(new Date().valueOf() - new Date('2021-11-22T18:30:00').valueOf());
let days = diffTime / (24*60*60*1000);
let hours = (days % 1) * 24;
let minutes = (hours % 1) * 60;
let secs = (minutes % 1) * 60;
[days, hours, minutes, secs] = [Math.floor(days), Math.floor(hours), Math.floor(minutes), Math.floor(secs)]
console.log(days+'d', hours+'h', minutes+'m', secs+'s');
Solution 7 - Javascript
Here is a code example. I used simple calculations instead of using precalculations like 1 day is 86400 seconds. So you can follow the logic with ease.
// Calculate time between two dates:
var date1 = new Date('1110-01-01 11:10');
var date2 = new Date();
console.log('difference in ms', date1 - date2);
// Use Math.abs() so the order of the dates can be ignored and you won't
// end up with negative numbers when date1 is before date2.
console.log('difference in ms abs', Math.abs(date1 - date2));
console.log('difference in seconds', Math.abs(date1 - date2) / 1000);
var diffInSeconds = Math.abs(date1 - date2) / 1000;
var days = Math.floor(diffInSeconds / 60 / 60 / 24);
var hours = Math.floor(diffInSeconds / 60 / 60 % 24);
var minutes = Math.floor(diffInSeconds / 60 % 60);
var seconds = Math.floor(diffInSeconds % 60);
var milliseconds = Math.round((diffInSeconds - Math.floor(diffInSeconds)) * 1000);
console.log('days', days);
console.log('hours', ('0' + hours).slice(-2));
console.log('minutes', ('0' + minutes).slice(-2));
console.log('seconds', ('0' + seconds).slice(-2));
console.log('milliseconds', ('00' + milliseconds).slice(-3));
Solution 8 - Javascript
Short and flexible with support for negative values, although by using two comma expressions :)
function timeUnitsBetween(startDate, endDate) {
let delta = Math.abs(endDate - startDate) / 1000;
const isNegative = startDate > endDate ? -1 : 1;
return [
['days', 24 * 60 * 60],
['hours', 60 * 60],
['minutes', 60],
['seconds', 1]
].reduce((acc, [key, value]) => (acc[key] = Math.floor(delta / value) * isNegative, delta -= acc[key] * isNegative * value, acc), {});
}
Example:
timeUnitsBetween(new Date("2019-02-11T02:12:03+00:00"), new Date("2019-02-11T01:00:00+00:00"));
// { days: -0, hours: -1, minutes: -12, seconds: -3 }
Inspired by RienNeVaPlu͢s solution.
Solution 9 - Javascript
Use moment.js library, for example:
var time = date_future - date_now;
var seconds = moment.duration(time).seconds();
var minutes = moment.duration(time).minutes();
var hours = moment.duration(time).hours();
var days = moment.duration(time).days();
Solution 10 - Javascript
The best library that I know of for duration breakdown is countdown.js. It handles all the hard cases such as leap years and daylight savings as csg mentioned, and even allows you to specify fuzzy concepts such as months and weeks. Here's the code for your case:
//assuming these are in *seconds* (in case of MS don't multiply by 1000 below)
var date_now = 1218374;
var date_future = 29384744;
diff = countdown(date_now * 1000, date_future * 1000,
countdown.DAYS | countdown.HOURS | countdown.MINUTES | countdown.SECONDS);
alert("days: " + diff.days + " hours: " + diff.hours +
" minutes: " + diff.minutes + " seconds: " + diff.seconds);
//or even better
alert(diff.toString());
Here's a JSFiddle, but it would probably only work in FireFox or in Chrome with web security disabled, since countdown.js is hosted with a text/plain MIME type (you're supposed to serve the file, not link to countdownjs.org).
Solution 11 - Javascript
For those who wants only hours and minutes use this
const oldDate = new Date("2021-04-28T13:17:31.000Z")
const newDate = new Date("2021-04-28T22:08:07.000Z")
const msToTime = (ms) => ({
hours: Math.trunc(ms/3600000),
minutes: Math.trunc((ms/3600000 - Math.trunc(ms/3600000))*60) + ((ms/3600000 - Math.trunc(ms/3600000))*60 % 1 != 0 ? 1 : 0)
})
console.log(msToTime(Math.abs(newDate-oldDate)))
Solution 12 - Javascript
function update(datetime = "2017-01-01 05:11:58") {
var theevent = new Date(datetime);
now = new Date();
var sec_num = (theevent - now) / 1000;
var days = Math.floor(sec_num / (3600 * 24));
var hours = Math.floor((sec_num - (days * (3600 * 24)))/3600);
var minutes = Math.floor((sec_num - (days * (3600 * 24)) - (hours * 3600)) / 60);
var seconds = Math.floor(sec_num - (days * (3600 * 24)) - (hours * 3600) - (minutes * 60));
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return days+':'+ hours+':'+minutes+':'+seconds;
}
Solution 13 - Javascript
Because MomentJS is quite heavy and sub-optimized, people not afraid to use a module should probably look at date-fns instead, which provides an intervalToDuration method which does what you want:
const result = intervalToDuration({
start: new Date(dateNow),
end: new Date(dateFuture),
})
And which would return an object looking like so:
{
years: 39,
months: 2,
days: 20,
hours: 7,
minutes: 5,
seconds: 0,
}
Then you can even use formatDuration to display this object as a string using the parameters you prefer
Solution 14 - Javascript
MomentJS has a function to do that:
const start = moment(j.timings.start);
const end = moment(j.timings.end);
const elapsedMinutes = end.diff(start, "minutes");
Solution 15 - Javascript
Here's my take:
timeSince(123456) => "1 day, 10 hours, 17 minutes, 36 seconds"
And the code:
function timeSince(date, longText) {
let seconds = null;
let leadingText = null;
if (date instanceof Date) {
seconds = Math.floor((new Date() - date) / 1000);
if (seconds < 0) {
leadingText = " from now";
} else {
leadingText = " ago";
}
seconds = Math.abs(seconds);
} else {
seconds = date;
leadingText = "";
}
const intervals = [
[31536000, "year" ],
[ 2592000, "month" ],
[ 86400, "day" ],
[ 3600, "hour" ],
[ 60, "minute"],
[ 1, "second"],
];
let interval = seconds;
let intervalStrings = [];
for (let i = 0; i < intervals.length; i++) {
let divResult = Math.floor(interval / intervals[i][0]);
if (divResult > 0) {
intervalStrings.push(divResult + " " + intervals[i][1] + ((divResult > 1) ? "s" : ""));
interval = interval % intervals[i][0];
if (!longText) {
break;
}
}
}
let intStr = intervalStrings.join(", ");
return intStr + leadingText;
}
Solution 16 - Javascript
Easy Way
function diff_hours(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
diff /= (60 * 60);
return Math.abs(Math.round(diff));
}
function diff_minutes(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
diff /= (60);
return Math.abs(Math.round(diff));
}
function diff_seconds(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
return Math.abs(Math.round(diff));
}
function diff_miliseconds(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime());
return Math.abs(Math.round(diff));
}
dt1 = new Date(2014,10,2);
dt2 = new Date(2014,10,3);
console.log(diff_hours(dt1, dt2));
dt1 = new Date("October 13, 2014 08:11:00");
dt2 = new Date("October 14, 2014 11:13:00");
console.log(diff_hours(dt1, dt2));
console.log(diff_minutes(dt1, dt2));
console.log(diff_seconds(dt1, dt2));
console.log(diff_miliseconds(dt1, dt2));
Solution 17 - Javascript
function calculateExamRemainingTime(exam_end_at) {
$(function(){
const calcNewYear = setInterval(function(){
const exam_ending_at = new Date(exam_end_at);
const current_time = new Date();
const totalSeconds = Math.floor((exam_ending_at - (current_time))/1000);;
const totalMinutes = Math.floor(totalSeconds/60);
const totalHours = Math.floor(totalMinutes/60);
const totalDays = Math.floor(totalHours/24);
const hours = totalHours - ( totalDays * 24 );
const minutes = totalMinutes - ( totalDays * 24 * 60 ) - ( hours * 60 );
const seconds = totalSeconds - ( totalDays * 24 * 60 * 60 ) - ( hours * 60 * 60 ) - ( minutes * 60 );
const examRemainingHoursSection = document.querySelector('#remainingHours');
const examRemainingMinutesSection = document.querySelector('#remainingMinutes');
const examRemainingSecondsSection = document.querySelector('#remainingSeconds');
examRemainingHoursSection.innerHTML = hours.toString();
examRemainingMinutesSection.innerHTML = minutes.toString();
examRemainingSecondsSection.innerHTML = seconds.toString();
},1000);
});
}
calculateExamRemainingTime('2025-06-03 20:20:20');
Solution 18 - Javascript
const arrDiff = [
{
label: 'second',
value: 1000,
},
{
label: 'minute',
value: 1000 * 60,
},
{
label: 'hour',
value: 1000 * 60 * 60,
},
{
label: 'day',
value: 1000 * 60 * 60 * 24,
},
{
label: 'year',
value: 1000 * 60 * 60 * 24 * 365,
},
];
function diff(date) {
let result = { label: '', value: '' };
const value = Date.now() - date;
for (let obj of arrDiff) {
let temp = Math.round(value / obj.value);
if (temp === 0) {
break;
} else
result = {
value: temp,
label: obj.label,
};
}
return result;
}
const postDate = new Date('2020-12-17 23:50:00+0700');
console.log(diff(postDate));
Solution 19 - Javascript
here is an code to find difference between two dates in Days,Hours,Minutes,Seconds (assuming the future date is new year date).
var one_day = 24*60*60*1000; // total milliseconds in one day
var today = new Date();
var new_year = new Date("01/01/2017"); // future date
var today_time = today.getTime(); // time in miliiseconds
var new_year_time = new_year.getTime();
var time_diff = Math.abs(new_year_time - today_time); //time diff in ms
var days = Math.floor(time_diff / one_day); // no of days
var remaining_time = time_diff - (days*one_day); // remaining ms
var hours = Math.floor(remaining_time/(60*60*1000));
remaining_time = remaining_time - (hours*60*60*1000);
var minutes = Math.floor(remaining_time/(60*1000));
remaining_time = remaining_time - (minutes * 60 * 1000);
var seconds = Math.ceil(remaining_time / 1000);
Solution 20 - Javascript
let delta = Math.floor(Math.abs(start.getTime() - end.getTime()) / 1000);
let hours = Math.floor(delta / 3600);
delta -= hours * 3600;
let minutes = Math.floor(delta / 60);
delta -= minutes * 60;
let seconds = delta;
if (hours.toString().length === 1) {
hours = `0${hours}`;
}
if (minutes.toString().length === 1) {
minutes = `0${minutes}`;
}
if (seconds.toString().length === 1) {
seconds = `0${seconds}`;
}
const recordingTime = `${hours}:${minutes}:${seconds}`;
Solution 21 - Javascript
We can do it by simple method
/*Declare the function */
function Clock(){
let d1 = new Date("1 Jan 2021");
let d2 = new Date();
let difference = Math.abs(d1 - d2); //to get absolute value
//calculate for each one
let Days = Math.floor(difference / ( 1000 * 60 * 60 * 24 ));
let Hours = Math.floor((difference / ( 1000 * 60 * 60 )) % 24);
let Mins = Math.floor((difference / ( 1000 * 60 )) % 60);
let Seconds = Math.floor((difference / ( 1000 )) % 60);
//getting nodes and change the text inside
let getday = document.querySelector(".big_text_days");
let gethour = document.querySelector(".big_text_hours");
let getmins = document.querySelector(".big_text_mins");
let getsec = document.querySelector(".big_text_sec");
getday.textContent = Check_Zero(Days);
gethour.textContent = Check_Zero(Hours);
getmins.textContent = Check_Zero(Mins)
getsec.textContent = Check_Zero(Seconds);
}
//call the funcion for every 1 second
setInterval(Clock , 1000);
//check and add zero in front, if it is lessthan 10
function Check_Zero(mytime){
return mytime < 10 ? "0"+mytime : mytime;
}
*{
padding: 0px;
margin: 0px;
box-sizing: border-box;
}
body{
max-width: 900px;
margin: 0px auto;
background-color:whitesmoke;
background-size: cover;
display: flex;
flex-direction: column;
align-items: center;
margin-top: 5rem;
}
.main_container{
display: flex;
flex-wrap: wrap;
justify-content: center;
}
h1{
font-size: 3rem;
color: #3D4B72;
}
.big_text_days , .big_text_hours , .big_text_mins , .big_text_sec{
font-size: 2rem;
font-weight: bold;
line-height: 2;
color: #AC7591;
text-align: center;
}
p{
padding: 20px 0px 20px 0px;
font-size: 3rem;
text-align: center;
}
.spantext{
color: #103c28;
margin: 0px 3rem;
font-size: 2rem;
font-style: italic;
}
.text_sec{
color : #005259;
}
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<meta name="description" content="Responsive site">
<meta name="keywords" content="HTML,CSS,JS">
<meta name="author" content="Ranjan">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Home</title>
<link href="https://fonts.googleapis.com/css?family=Alfa+Slab+One|Bree+Serif|Exo|Exo+2|Lato|Mansalva|Playfair+Display&display=swap" rel="stylesheet">
<link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.2.0/css/all.css" integrity="sha384-hWVjflwFxL6sNzntih27bfxkr27PmbbK/iSvJ+a4+0owXq79v+lsFkW54bOGbiDQ" crossorigin="anonymous">
</head>
<body>
<section>
<h1>CountDown Timer</h1>
</section>
<section>
<div class="main_container">
<div class="days_container">
<p class="big_text_days">1</p>
<span class="spantext spantextdays">Days</span>
</div>
<div class="hours_container">
<p class="big_text_hours">1</p>
<span class="spantext spantexthours">Hours</span>
</div>
<div class="mins_container">
<p class="big_text_mins">1</p>
<span class="spantext spantextmins">Minutes</span>
</div>
<div class="sec_container">
<p class="big_text_sec text_sec">1</p>
<span class="spantext spantextsec">Seconds</span>
</div>
</div>
</section>
</body>
</html>
Solution 22 - Javascript
2021 version
Inspired with Alnitak's and RienNeVaPlus's answers.
Calculates since and until automatically (see examples below).
const timeUnits = {
year: 31536e6,
month: 2592e6,
week: 6048e5,
day: 864e5,
hour: 36e5,
minute: 6e4,
second: 1e3,
};
const timeUnitsNamesShort = {
year: 'y',
month: 'm',
week: 'w',
day: 'd',
hour: 'h',
minute: 'm',
second: 's',
};
const isFuture = (date) => date > Date.now();
const dateDiffStructure = (date, units = timeUnits) => {
let delta = Math.abs(date - Date.now());
return Object.entries(units).reduce((acc, [key, value]) => {
acc[key] = Math.floor(delta / value);
delta -= acc[key] * value;
return acc;
}, {});
};
const dateDiffStructureToString = (date, diffStructure, values, short) => {
const diffStructureEntries = values
? Object.entries(diffStructure).filter(([key, value]) => values.includes(key) && value)
: Object.entries(diffStructure).filter(([, value]) => value);
if (!diffStructureEntries.length) return 'just now';
const suffix = isFuture(date) ? 'left' : 'ago';
const diffString = diffStructureEntries.reduce((acc, [key, value]) => {
const timeUnit = short
? timeUnitsNamesShort[key]
: value > 1
? ` ${key}s`
: ` ${key}`;
acc = acc ? `${acc} ` : '';
return `${acc}${value}${timeUnit}`;
}, '');
return `${diffString} ${suffix}`;
};
const getDateDiff = (date, values, short) => {
const diffStructure = dateDiffStructure(date);
return dateDiffStructureToString(date, diffStructure, values, short);
};
Tests and examples:
const timeUnits = {
year: 31536e6,
month: 2592e6,
week: 6048e5,
day: 864e5,
hour: 36e5,
minute: 6e4,
second: 1e3,
};
const timeUnitsNamesShort = {
year: 'y',
month: 'm',
week: 'w',
day: 'd',
hour: 'h',
minute: 'm',
second: 's',
};
const isFuture = (date) => date > Date.now();
const dateDiffStructure = (date, units = timeUnits) => {
let delta = Math.abs(date - Date.now());
return Object.entries(units).reduce((acc, [key, value]) => {
acc[key] = Math.floor(delta / value);
delta -= acc[key] * value;
return acc;
}, {});
};
const dateDiffStructureToString = (date, diffStructure, values, short) => {
const diffStructureEntries = values ?
Object.entries(diffStructure).filter(([key, value]) => values.includes(key) && value) :
Object.entries(diffStructure).filter(([, value]) => value);
if (!diffStructureEntries.length) return 'just now';
const suffix = isFuture(date) ? 'left' : 'ago';
const diffString = diffStructureEntries.reduce((acc, [key, value]) => {
const timeUnit = short ?
timeUnitsNamesShort[key] :
value > 1 ?
` ${key}s` :
` ${key}`;
acc = acc ? `${acc} ` : '';
return `${acc}${value}${timeUnit}`;
}, '');
return `${diffString} ${suffix}`;
};
const getDateDiff = (date, values, short) => {
const diffStructure = dateDiffStructure(date);
console.log(`dateDiffStructure(${JSON.stringify(date)}) //`, diffStructure);
return dateDiffStructureToString(date, diffStructure, values, short);
};
const tests = [
['After tomorrow', [new Date(Date.now() + 8.64e7 + 1e6)]],
['Yesterday', [new Date(Date.now() - 8.64e7)]],
['Past', [new Date(Date.now() * Math.random())]],
['Future short', [new Date(Date.now() * (Math.random() + 1)), ['year', 'month', 'day'], true]],
['Now', [Date.now()]]
];
tests.forEach(([text, args]) => {
console.log(`${text}:`);
console.group();
console.log(`getDateDiff(${args.map(item => JSON.stringify(item)).join(', ')}) //`, getDateDiff(...args));
console.groupEnd();
});