Javascript/jQuery: Set Values (Selection) in a multiple Select

JavascriptJqueryMultiple Select

Javascript Problem Overview


I have a multiple select:

<select name='strings' id="strings" multiple style="width:100px;">
    <option value="Test">Test</option>
    <option value="Prof">Prof</option>
    <option value="Live">Live</option>
    <option value="Off">Off</option>
    <option value="On">On</option>
</select>

I load data from my database. Then I have a string like this:

var values="Test,Prof,Off";

How can I set this Values in the multiple select? Already tried change the string in an array and put it as value in the multiple, but doesnt work...! Can someone help me with this? THANKS!!!

Javascript Solutions


Solution 1 - Javascript

Iterate through the loop using the value in a dynamic selector that utilizes the attribute selector.

var values="Test,Prof,Off";
$.each(values.split(","), function(i,e){
    $("#strings option[value='" + e + "']").prop("selected", true);
});

Working Example http://jsfiddle.net/McddQ/1/

Solution 2 - Javascript

in jQuery:

$("#strings").val(["Test", "Prof", "Off"]);

or in pure JavaScript:

var element = document.getElementById('strings');
var values = ["Test", "Prof", "Off"];
for (var i = 0; i < element.options.length; i++) {
    element.options[i].selected = values.indexOf(element.options[i].value) >= 0;
}

jQuery does significant abstraction here.

Solution 3 - Javascript

Just provide the jQuery val function with an array of values:

var values = "Test,Prof,Off";
$('#strings').val(values.split(','));

And to get the selected values in the same format:

values = $('#strings').val();

Solution 4 - Javascript

Pure JavaScript ES6 solution

  • Catch every option with a querySelectorAll function and split the values string.
  • Use Array#forEach to iterate over every element from the values array.
  • Use Array#find to find the option matching given value.
  • Set it's selected attribute to true.

Note: Array#from transforms an array-like object into an array and then you are able to use Array.prototype functions on it, like find or map.

var values = "Test,Prof,Off",
    options = Array.from(document.querySelectorAll('#strings option'));

values.split(',').forEach(function(v) {
  options.find(c => c.value == v).selected = true;
});

<select name='strings' id="strings" multiple style="width:100px;">
    <option value="Test">Test</option>
    <option value="Prof">Prof</option>
    <option value="Live">Live</option>
    <option value="Off">Off</option>
    <option value="On">On</option>
</select>

Solution 5 - Javascript

Basically do a values.split(',') and then loop through the resulting array and set the Select.

Solution 6 - Javascript

var groups = ["Test", "Prof","Off"];

    $('#fruits option').filter(function() {
      return groups.indexOf($(this).text()) > -1; //Options text exists in array
    }).prop('selected', true); //Set selected

Solution 7 - Javascript

Pure JavaScript ES5 solution

For some reason you don't use jQuery nor ES6? This might help you:

var values = "Test,Prof,Off";
var splitValues = values.split(',');
var multi = document.getElementById('strings');

multi.value = null; // Reset pre-selected options (just in case)
var multiLen = multi.options.length;
for (var i = 0; i < multiLen; i++) {
  if (splitValues.indexOf(multi.options[i].value) >= 0) {
    multi.options[i].selected = true;
  }
}

<select name='strings' id="strings" multiple style="width:100px;">
    <option value="Test">Test</option>
    <option value="Prof">Prof</option>
    <option value="Live">Live</option>
    <option value="Off">Off</option>
    <option value="On" selected>On</option>
</select>

Solution 8 - Javascript

this is error in some answers for replace |

var mystring = "this|is|a|test";
mystring = mystring.replace(/|/g, "");
alert(mystring);

this correction is correct but the | In the end it should look like this |

var mystring = "this|is|a|test";
mystring = mystring.replace(/\|/g, "");
alert(mystring);

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionZwen2012View Question on Stackoverflow
Solution 1 - JavascriptKevin BowersoxView Answer on Stackoverflow
Solution 2 - JavascriptŁukasz W.View Answer on Stackoverflow
Solution 3 - JavascriptPostureOfLearningView Answer on Stackoverflow
Solution 4 - Javascriptkind userView Answer on Stackoverflow
Solution 5 - JavascriptkashipaiView Answer on Stackoverflow
Solution 6 - JavascriptMember conView Answer on Stackoverflow
Solution 7 - JavascriptMariano DesanzeView Answer on Stackoverflow
Solution 8 - JavascriptXavier MorenoView Answer on Stackoverflow