Javascript get XPath of a node
JavascriptDomXpathJavascript Problem Overview
Is there anyway to return an XPath string of a DOM element in Javascript?
Javascript Solutions
Solution 1 - Javascript
I refactored this from another example. It will attempt to check or there is for sure a unique id and if so use that case to shorten the expression.
function createXPathFromElement(elm) {
var allNodes = document.getElementsByTagName('*');
for (var segs = []; elm && elm.nodeType == 1; elm = elm.parentNode)
{
if (elm.hasAttribute('id')) {
var uniqueIdCount = 0;
for (var n=0;n < allNodes.length;n++) {
if (allNodes[n].hasAttribute('id') && allNodes[n].id == elm.id) uniqueIdCount++;
if (uniqueIdCount > 1) break;
};
if ( uniqueIdCount == 1) {
segs.unshift('id("' + elm.getAttribute('id') + '")');
return segs.join('/');
} else {
segs.unshift(elm.localName.toLowerCase() + '[@id="' + elm.getAttribute('id') + '"]');
}
} else if (elm.hasAttribute('class')) {
segs.unshift(elm.localName.toLowerCase() + '[@class="' + elm.getAttribute('class') + '"]');
} else {
for (i = 1, sib = elm.previousSibling; sib; sib = sib.previousSibling) {
if (sib.localName == elm.localName) i++; };
segs.unshift(elm.localName.toLowerCase() + '[' + i + ']');
};
};
return segs.length ? '/' + segs.join('/') : null;
};
function lookupElementByXPath(path) {
var evaluator = new XPathEvaluator();
var result = evaluator.evaluate(path, document.documentElement, null,XPathResult.FIRST_ORDERED_NODE_TYPE, null);
return result.singleNodeValue;
}
Solution 2 - Javascript
There's not a unique XPath to a node, so you'll have to decide what's the most appropriate way of constructing a path. Use IDs where available? Numeral position in the document? Position relative to other elements?
See getPathTo()
in this answer for one possible approach.
Solution 3 - Javascript
Here is a functional programming style ES6 function for the job:
function getXPathForElement(element) {
const idx = (sib, name) => sib
? idx(sib.previousElementSibling, name||sib.localName) + (sib.localName == name)
: 1;
const segs = elm => !elm || elm.nodeType !== 1
? ['']
: elm.id && document.getElementById(elm.id) === elm
? [`id("${elm.id}")`]
: [...segs(elm.parentNode), `${elm.localName.toLowerCase()}[${idx(elm)}]`];
return segs(element).join('/');
}
function getElementByXPath(path) {
return (new XPathEvaluator())
.evaluate(path, document.documentElement, null,
XPathResult.FIRST_ORDERED_NODE_TYPE, null)
.singleNodeValue;
}
// Demo:
const li = document.querySelector('li:nth-child(2)');
const path = getXPathForElement(li);
console.log(path);
console.log(li === getElementByXPath(path)); // true
<div>
<table id="start"></table>
<div>
<ul><li>option</ul></ul>
<span>title</span>
<ul>
<li>abc</li>
<li>select this</li>
</ul>
</div>
</div>
It will use an id
selector, unless the element is not the first one with that id. Class selectors are not used, because in interactive web pages classes may change often.
Solution 4 - Javascript
I've adapted the algorithm Chromium uses to calculate the XPath from devtools below.
To use this as-written you'd call Elements.DOMPath.xPath(<some DOM node>, false)
. The last parameter controls whether you get the shorter "Copy XPath" (if true
) or "Copy full XPath".
// Copyright 2018 The Chromium Authors. All rights reserved.
// Use of this source code is governed by a BSD-style license that can be
// found in the LICENSE file.
Elements = {};
Elements.DOMPath = {};
/**
* @param {!Node} node
* @param {boolean=} optimized
* @return {string}
*/
Elements.DOMPath.xPath = function (node, optimized) {
if (node.nodeType === Node.DOCUMENT_NODE) {
return '/';
}
const steps = [];
let contextNode = node;
while (contextNode) {
const step = Elements.DOMPath._xPathValue(contextNode, optimized);
if (!step) {
break;
} // Error - bail out early.
steps.push(step);
if (step.optimized) {
break;
}
contextNode = contextNode.parentNode;
}
steps.reverse();
return (steps.length && steps[0].optimized ? '' : '/') + steps.join('/');
};
/**
* @param {!Node} node
* @param {boolean=} optimized
* @return {?Elements.DOMPath.Step}
*/
Elements.DOMPath._xPathValue = function (node, optimized) {
let ownValue;
const ownIndex = Elements.DOMPath._xPathIndex(node);
if (ownIndex === -1) {
return null;
} // Error.
switch (node.nodeType) {
case Node.ELEMENT_NODE:
if (optimized && node.getAttribute('id')) {
return new Elements.DOMPath.Step('//*[@id="' + node.getAttribute('id') + '"]', true);
}
ownValue = node.localName;
break;
case Node.ATTRIBUTE_NODE:
ownValue = '@' + node.nodeName;
break;
case Node.TEXT_NODE:
case Node.CDATA_SECTION_NODE:
ownValue = 'text()';
break;
case Node.PROCESSING_INSTRUCTION_NODE:
ownValue = 'processing-instruction()';
break;
case Node.COMMENT_NODE:
ownValue = 'comment()';
break;
case Node.DOCUMENT_NODE:
ownValue = '';
break;
default:
ownValue = '';
break;
}
if (ownIndex > 0) {
ownValue += '[' + ownIndex + ']';
}
return new Elements.DOMPath.Step(ownValue, node.nodeType === Node.DOCUMENT_NODE);
};
/**
* @param {!Node} node
* @return {number}
*/
Elements.DOMPath._xPathIndex = function (node) {
// Returns -1 in case of error, 0 if no siblings matching the same expression,
// <XPath index among the same expression-matching sibling nodes> otherwise.
function areNodesSimilar(left, right) {
if (left === right) {
return true;
}
if (left.nodeType === Node.ELEMENT_NODE && right.nodeType === Node.ELEMENT_NODE) {
return left.localName === right.localName;
}
if (left.nodeType === right.nodeType) {
return true;
}
// XPath treats CDATA as text nodes.
const leftType = left.nodeType === Node.CDATA_SECTION_NODE ? Node.TEXT_NODE : left.nodeType;
const rightType = right.nodeType === Node.CDATA_SECTION_NODE ? Node.TEXT_NODE : right.nodeType;
return leftType === rightType;
}
const siblings = node.parentNode ? node.parentNode.children : null;
if (!siblings) {
return 0;
} // Root node - no siblings.
let hasSameNamedElements;
for (let i = 0; i < siblings.length; ++i) {
if (areNodesSimilar(node, siblings[i]) && siblings[i] !== node) {
hasSameNamedElements = true;
break;
}
}
if (!hasSameNamedElements) {
return 0;
}
let ownIndex = 1; // XPath indices start with 1.
for (let i = 0; i < siblings.length; ++i) {
if (areNodesSimilar(node, siblings[i])) {
if (siblings[i] === node) {
return ownIndex;
}
++ownIndex;
}
}
return -1; // An error occurred: |node| not found in parent's children.
};
/**
* @unrestricted
*/
Elements.DOMPath.Step = class {
/**
* @param {string} value
* @param {boolean} optimized
*/
constructor(value, optimized) {
this.value = value;
this.optimized = optimized || false;
}
/**
* @override
* @return {string}
*/
toString() {
return this.value;
}
};
Solution 5 - Javascript
A similar solution is given by the function getXPathForElement on the MDN:
function getXPathForElement(el, xml) {
var xpath = '';
var pos, tempitem2;
while(el !== xml.documentElement) {
pos = 0;
tempitem2 = el;
while(tempitem2) {
if (tempitem2.nodeType === 1 && tempitem2.nodeName === el.nodeName) { // If it is ELEMENT_NODE of the same name
pos += 1;
}
tempitem2 = tempitem2.previousSibling;
}
xpath = "*[name()='"+el.nodeName+"' and namespace-uri()='"+(el.namespaceURI===null?'':el.namespaceURI)+"']["+pos+']'+'/'+xpath;
el = el.parentNode;
}
xpath = '/*'+"[name()='"+xml.documentElement.nodeName+"' and namespace-uri()='"+(el.namespaceURI===null?'':el.namespaceURI)+"']"+'/'+xpath;
xpath = xpath.replace(/\/$/, '');
return xpath;
}
Also XMLSerializer might be worth a try.
Solution 6 - Javascript
function getElementXPath (element) {
if (!element) return null
if (element.id) {
return `//*[@id=${element.id}]`
} else if (element.tagName === 'BODY') {
return '/html/body'
} else {
const sameTagSiblings = Array.from(element.parentNode.childNodes)
.filter(e => e.nodeName === element.nodeName)
const idx = sameTagSiblings.indexOf(element)
return getElementXPath(element.parentNode) +
'/' +
element.tagName.toLowerCase() +
(sameTagSiblings.length > 1 ? `[${idx + 1}]` : '')
}
}
console.log(getElementXPath(document.querySelector('#a div')))
<div id="a">
<div>def</div>
</div>
Solution 7 - Javascript
I checked every solution provided here but none of them works with svg
elements (code getElementByXPath(getXPathForElement(elm)) === elm
returns false
for svg
or path
elements)
So I added the Touko's svg fix to the trincot's solution and got this code:
function getXPathForElement(element) {
const idx = (sib, name) => sib
? idx(sib.previousElementSibling, name||sib.localName) + (sib.localName == name)
: 1;
const segs = elm => !elm || elm.nodeType !== 1
? ['']
: elm.id && document.getElementById(elm.id) === elm
? [`id("${elm.id}")`]
: [...segs(elm.parentNode), elm instanceof HTMLElement
? `${elm.localName}[${idx(elm)}]`
: `*[local-name() = "${elm.localName}"][${idx(elm)}]`];
return segs(element).join('/');
}
The difference is it returns *[local-name() = "tag"][n]
instead of tag[n]
if element is not an instance of HTMLElement
(svgs are SVGElement
but I decided not to stick with checking only svg).
Example:
Before:
.../div[2]/div[2]/span[1]/svg[1]/path[1]
After:
.../div[2]/div[2]/span[1]/*[local-name() = "svg"][1]/*[local-name() = "path"][1]
Solution 8 - Javascript
Just pass the element in function getXPathOfElement
and you will get the Xpath
.
function getXPathOfElement(elt)
{
var path = "";
for (; elt && elt.nodeType == 1; elt = elt.parentNode)
{
idx = getElementIdx(elt);
xname = elt.tagName;
if (idx > 1) xname += "[" + idx + "]";
path = "/" + xname + path;
}
return path;
}
function getElementIdx(elt)
{
var count = 1;
for (var sib = elt.previousSibling; sib ; sib = sib.previousSibling)
{
if(sib.nodeType == 1 && sib.tagName == elt.tagName) count++
}
return count;
}