JavaScript exponents

JavascriptMath

Javascript Problem Overview


How do you do exponents in JavaScript?

Like how would you do 12^2?

Javascript Solutions


Solution 1 - Javascript

Math.pow():

js> Math.pow(12, 2)
144

Solution 2 - Javascript

There is an exponentiation operator, which is part of the ES7 final specification. It is supposed to work in a similar manner with python and matlab:

a**b // will rise a to the power b

Now it is already implemented in Edge14, Chrome52, and also it is available with traceur or babel.

Solution 3 - Javascript

Math.pow(base, exponent), for starters.

Example:

Math.pow(12, 2)

Solution 4 - Javascript

Math.pow(x, y) works fine for x^y and even evaluates the expression when y is not an integer. A piece of code not relying on Math.pow but that can only evaluate integer exponents is:

function exp(base, exponent) {
  exponent = Math.round(exponent);
  if (exponent == 0) {
    return 1;
  }
  if (exponent < 0) {
    return 1 / exp(base, -exponent);
  }
  if (exponent > 0) {
    return base * exp(base, exponent - 1)
  }
}

Solution 5 - Javascript

Working Example:

var a = 10;
var b = 4;

console.log("Using Math.pow():", Math.pow(a,b)); // 10x10x10x10
console.log("Using ** operator:", a**b);  // 10x10x10x10

You can use either Math.pow() or ** operator

Solution 6 - Javascript

How we perform exponents in JavaScript
According to MDN
The exponentiation operator returns the result of raising the first operand to the power second operand. That is, var1 var2, in the preceding statement, where var1 and var2 are variables. Exponentiation operator is right associative: a ** b ** c is equal to a ** (b ** c).
For example:
2**3 // here 2 will multiply 3 times by 2 and the result will be 8.
4**4 // here 4 will multiply 4 times by 4 and the result will be 256.

Solution 7 - Javascript

Math.pow function is deprecated

Math.pow(a,b)

So better to use the exponentiation assignment ** as:

a**b

Example:

const postMoneyValuationRevenue = Math.round(
      exitValueRevenue / (1 + returnRatePercentage / 100) ** exitYear,
    );

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMcKaylaView Question on Stackoverflow
Solution 1 - JavascriptIgnacio Vazquez-AbramsView Answer on Stackoverflow
Solution 2 - JavascriptSalvador DaliView Answer on Stackoverflow
Solution 3 - JavascriptTieson T.View Answer on Stackoverflow
Solution 4 - JavascriptAnon YmusView Answer on Stackoverflow
Solution 5 - JavascriptDeepu ReghunathView Answer on Stackoverflow
Solution 6 - JavascriptMayank_VKView Answer on Stackoverflow
Solution 7 - JavascriptJaspal SinghView Answer on Stackoverflow