java.util.Date format SSSSSS: if not microseconds what are the last 3 digits?

JavaDateFormatTimestamp

Java Problem Overview


Just tested this code on both my Windows (8) workstation and an AIX:

	public static void main(String[] args) {
		System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS").format(new Date()));
		System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS").format(new Date()));
	}

and got something similar to this as a result:

2013-10-07 12:53:26.000905
2013-10-07 12:53:26.000906

Can someone please explain me what are the last digits, if not microseconds?

Note: I interact with a DB2 database in which chronological data is stored using timed columns as TIMESTAMP with 6 digits AFTER the seconds i.e. microseconds (IMO). But all those "timestamps" are created by requesting the following query:

SELECT current timestamp as currenttimestamp FROM Table ( values (1)) temp

I wonder if, given the above results, I couldn't just use in my code new Date() instead of selecting the current timestamp from the database.

Thanks.

PS: I searched but found no relevant (answered) questions, like: https://stackoverflow.com/questions/1712205/current-time-in-microseconds-in-java or https://stackoverflow.com/questions/8892769/get-time-with-hour-minute-second-millisecond-microsecond

Java Solutions


Solution 1 - Java

From the documentation of SimpleDateFormat:

Letter     Date or Time Component     Presentation     Examples  
S          Millisecond                Number           978 

So it is milliseconds, or 1/1000th of a second. You just format it with on 6 digits, so you add 3 extra leading zeroes...

You can check it this way:

    Date d =new Date();
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S").format(d));
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SS").format(d));
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS").format(d));
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSS").format(d));
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSS").format(d));
    System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS").format(d));

Output:

2013-10-07 12:13:27.132
2013-10-07 12:13:27.132
2013-10-07 12:13:27.132
2013-10-07 12:13:27.0132
2013-10-07 12:13:27.00132
2013-10-07 12:13:27.000132

(Ideone fiddle)

Solution 2 - Java

tl;dr

Instant.now()
       .toString() 

>2018-02-02T00:28:02.487114Z

Instant.parse(
    "2018-02-02T00:28:02.487114Z"
)

java.time

The accepted Answer by ppeterka is correct. Your abuse of the formatting pattern results in an erroneous display of data, while the internal value is always limited milliseconds.

The troublesome SimpleDateFormat and Date classes you are using are now legacy, supplanted by the java.time classes. The java.time classes handle nanoseconds resolution, much finer than the milliseconds limit of the legacy classes.

The equivalent to java.util.Date is java.time.Instant. You can even convert between them using new methods added to the old classes.

Instant instant = myJavaUtilDate.toInstant() ;

The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds (up to nine (9) digits of a decimal fraction).

Capture the current moment in UTC. Java 8 captures the current moment in milliseconds, while a new Clock implementation in Java 9 captures the moment in finer granularity, typically microseconds though it depends on the capabilities of your computer hardware clock & OS & JVM implementation.

Instant instant = Instant.now() ;

Generate a String in standard ISO 8601 format.

String output = instant.toString() ;

>2018-02-02T00:28:02.487114Z

To generate strings in other formats, search Stack Overflow for DateTimeFormatter, already covered many times.

To adjust into a time zone other than UTC, use ZonedDateTime.

ZonedDateTime zdt = instant.atZone( ZoneId.of( "Pacific/Auckland" ) ) ;

About java.time

The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.

The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.

To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.

Where to obtain the java.time classes?

The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.

Solution 3 - Java

I used yet another trick to format date with 6-digit precision (microseconds):

System.out.println(
    new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.").format(microseconds/1000)
    +String.format("%06d", microseconds%1000000));

This technique can be extended further, to nanoseconds and up.

Solution 4 - Java

Use java.sql.Timestamp.toString if you want to get fractional seconds in text representation. The difference betwen Timestamp from DB and Java Date is that DB precision is nanoseconds while Java Date precision is milliseconds.

Solution 5 - Java

SSSSSS is microseconds. Let us say the time is 10:30:22 (Seconds 22) and 10:30:22.1 would be 22 seconds and 1/10 of a second . Extending the same logic , 10:32.22.000132 would be 22 seconds and 132/1,000,000 of a second, which is nothing but microseconds.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionmaxxymeView Question on Stackoverflow
Solution 1 - JavappeterkaView Answer on Stackoverflow
Solution 2 - JavaBasil BourqueView Answer on Stackoverflow
Solution 3 - JavatutejszyView Answer on Stackoverflow
Solution 4 - JavaEvgeniy DorofeevView Answer on Stackoverflow
Solution 5 - Javauser9301292View Answer on Stackoverflow