Java - JPA - @Version annotation

JavaJpaJpa Annotations

Java Problem Overview


How does @Version annotation work in JPA?

I found various answers whose extract is as follows:

>JPA uses a version field in your entities to detect concurrent modifications to the same datastore record. When the JPA runtime detects an attempt to concurrently modify the same record, it throws an exception to the transaction attempting to commit last.

But I am still not sure how it works.


Also as from the following lines:

>You should consider version fields immutable. Changing the field value has undefined results.

Does it mean that we should declare our version field as final?

Java Solutions


Solution 1 - Java

> But still I am not sure how it works?

Let's say an entity MyEntity has an annotated version property:

@Entity
public class MyEntity implements Serializable {    

    @Id
    @GeneratedValue
    private Long id;

    private String name;

    @Version
    private Long version;

    //...
}

On update, the field annotated with @Version will be incremented and added to the WHERE clause, something like this:

UPDATE MYENTITY SET ..., VERSION = VERSION + 1 WHERE ((ID = ?) AND (VERSION = ?))

If the WHERE clause fails to match a record (because the same entity has already been updated by another thread), then the persistence provider will throw an OptimisticLockException.

> Does it mean that we should declare our version field as final

No but you could consider making the setter protected as you're not supposed to call it.

Solution 2 - Java

Although @Pascal answer is perfectly valid, from my experience I find the code below helpful to accomplish optimistic locking:

@Entity
public class MyEntity implements Serializable {    
    // ...

    @Version
    @Column(name = "optlock", columnDefinition = "integer DEFAULT 0", nullable = false)
    private long version = 0L;

    // ...
}

Why? Because:

  1. Optimistic locking won't work if field annotated with @Version is accidentally set to null.
  2. As this special field isn't necessarily a business version of the object, to avoid a misleading, I prefer to name such field to something like optlock rather than version.

First point doesn't matter if application uses only JPA for inserting data into the database, as JPA vendor will enforce 0 for @version field at creation time. But almost always plain SQL statements are also in use (at least during unit and integration testing).

Solution 3 - Java

Every time an entity is updated in the database the version field will be increased by one. Every operation that updates the entity in the database will have appended WHERE version = VERSION_THAT_WAS_LOADED_FROM_DATABASE to its query.

In checking affected rows of your operation the jpa framework can make sure there was no concurrent modification between loading and persisting your entity because the query would not find your entity in the database when it's version number has been increased between load and persist.

Solution 4 - Java

Version used to ensure that only one update in a time. JPA provider will check the version, if the expected version already increase then someone else already update the entity so an exception will be thrown.

So updating entity value would be more secure, more optimist.

If the value changes frequent, then you might consider not to use version field. For an example "an entity that has counter field, that will increased everytime a web page accessed"

Solution 5 - Java

Just adding a little more info.

JPA manages the version under the hood for you, however it doesn't do so when you update your record via JPAUpdateClause, in such cases you need to manually add the version increment to the query.

Same can be said about updating via JPQL, i.e. not a simple change to the entity, but an update command to the database even if that is done by hibernate

Pedro

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAmitView Question on Stackoverflow
Solution 1 - JavaPascal ThiventView Answer on Stackoverflow
Solution 2 - JavaG. DemeckiView Answer on Stackoverflow
Solution 3 - JavastefanglaseView Answer on Stackoverflow
Solution 4 - JavauudashrView Answer on Stackoverflow
Solution 5 - JavaPedro BorgesView Answer on Stackoverflow