Java dynamic array sizes?

Java

Java Problem Overview


I have a class - xClass, that I want to load into an array of xClass so I the declaration:

xClass mysclass[] = new xClass[10];
myclass[0] = new xClass();
myclass[9] = new xClass();

However, I don't know if I will need 10. I may need 8 or 12 or any other number for that matter. I won't know until runtime. Can I change the number of elements in an array on the fly? If so, how?

Java Solutions


Solution 1 - Java

No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:

int[] oldItems = new int[10];
for (int i = 0; i < 10; i++) {
    oldItems[i] = i + 10;
}
int[] newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;

If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:

List<XClass> myclass = new ArrayList<XClass>();
myclass.add(new XClass());
myclass.add(new XClass());

Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:

class Myclass {
    private int[] items;

    public int[] getItems() {
        return items;
    }
}

you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:

class Myclass {
    private List<Integer> items;

    public List<Integer> getItems() {
        return Collections.unmodifiableList(items);
    }
}

Solution 2 - Java

In java array length is fixed.

You can use a List to hold the values and invoke the toArray method if needed See the following sample:

import java.util.List;
import java.util.ArrayList;
import java.util.Random;

public class A  {

    public static void main( String [] args ) {
        // dynamically hold the instances
        List<xClass> list = new ArrayList<xClass>();

        // fill it with a random number between 0 and 100
        int elements = new Random().nextInt(100);  
        for( int i = 0 ; i < elements ; i++ ) {
            list.add( new xClass() );
        }

        // convert it to array
        xClass [] array = list.toArray( new xClass[ list.size() ] );


        System.out.println( "size of array = " + array.length );
    }
}
class xClass {}

Solution 3 - Java

As others have said, you cannot change the size of an existing Java array.

ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:

  • You cannot use [ ... ] to index a list. You have to use the get(int) and set(int, E) methods.
  • An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call set(15, foo).
  • You cannot directly change the size of an ArrayList. You do it indirectly using the various add, insert and remove methods.

If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )

If you only really need an array that grows as you are initializing it, then the solution is something like this.

ArrayList<T> tmp = new ArrayList<T>();
while (...) {
    tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T[] array = tmp.toArray(new T[tmp.size()]);

Solution 4 - Java

You set the number of elements to anything you want at the time you create it:

xClass[] mysclass = new xClass[n];

Then you can initialize the elements in a loop. I am guessing that this is what you need.

If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.

Solution 5 - Java

You can use ArrayList:

import java.util.ArrayList;
import java.util.Iterator;

...

ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());

Solution 6 - Java

As other users say, you probably need an implementation of java.util.List.

If, for some reason, you finally need an array, you can do two things:

  • Use a List and then convert it to an array with myList.toArray()

  • Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.

Best solution will depend on your problem ;)

Solution 7 - Java

Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.

Java API

Solution 8 - Java

Yes, wrap it and use the Collections framework.

List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());

Then use List.toArray() when necessary, or just iterate over said List.

Solution 9 - Java

I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.

import java.util.*;

Vector<Integer> v=new Vector<Integer>(5,2);

to add an element simply use:

v.addElement(int);

In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.

Solution 10 - Java

Where you declare the myclass[] array as :

xClass myclass[] = new xClass[10]

, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.

Solution 11 - Java

Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.

Solution 12 - Java

Yes, we can do this way.

import java.util.Scanner;

public class Collection_Basic {

	private static Scanner sc;

	public static void main(String[] args) {
		
		Object[] obj=new Object[4];
		sc = new Scanner(System.in);
		
		
		//Storing element
		System.out.println("enter your element");
		for(int i=0;i<4;i++){
			obj[i]=sc.nextInt();
		}
		
		/*
		 * here, size reaches with its maximum capacity so u can not store more element,
		 * 
		 * for storing more element we have to create new array Object with required size
		 */
		
		Object[] tempObj=new Object[10];
		
		//copying old array to new Array
		
		int oldArraySize=obj.length;
		int i=0;
		for(;i<oldArraySize;i++){
			
			tempObj[i]=obj[i];
		}
		
		/*
		 * storing new element to the end of new Array objebt
		 */
		tempObj[i]=90;

		//assigning new array Object refeence to the old one
		
		obj=tempObj;
		
		for(int j=0;j<obj.length;j++){
			System.out.println("obj["+j+"] -"+obj[j]);
		}
	}
	

}

Solution 13 - Java

Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).

Example:

Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
    builder.add(i);
}
int[] array = builder.build().toArray();

Note: available since Java 8.

Solution 14 - Java

It is a good practice get the amount you need to store first then initialize the array.

for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store. if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.

//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList(); 
//add a certain amount of data
for(int i=0;i<x;i++)
{
  al.add("data "+i); 
}

//get size of data inside
int size = al.size(); 
//initialize String array with the size you have
String strArray[] = new String[size]; 
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
  strArray[i] = al.get(i);
}

doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack

Solution 15 - Java

I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:

class MyClass {
    void myFunction () {
        Scanner s = new Scanner (System.in);
        int myArray [];
        int x;
    
        System.out.print ("Enter the size of the array: ");
        x = s.nextInt();
    
        myArray = new int[x];
    }
}

this assigns your array size to be the one entered at run time into x.

Solution 16 - Java

Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.

import java.util.Scanner;
    public class Dynamic {
    	public static Scanner value;
    	public static void main(String[]args){
    		value=new Scanner(System.in);
    		System.out.println("Enter the number of tests to calculate average\n");
    		int limit=value.nextInt();
    		int index=0;
    		int [] marks=new int[limit];
    		float sum,ave;
    		sum=0;		
    		while(index<limit)
    		{
    			int test=index+1;
    			System.out.println("Enter the marks on test " +test);
    			marks[index]=value.nextInt();
    			sum+=marks[index];
    			index++;
    		}
    		ave=sum/limit;
    		System.out.println("The average is: " + ave);
    	}
    }

Solution 17 - Java

In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself

This is the most "used" as well as preferred way to do it-

    int temp[]=new int[stck.length+1];
    for(int i=0;i<stck.length;i++)temp[i]=stck[i];
	stck=temp;

In the above code we are initializing a new temp[] array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck[]. And then again copying it back to the original one, giving us a new array of new SIZE.

No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code. For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.

Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time

File-name: DStack.java

public class DStack {
private int stck[];
int tos;

void Init_Stck(int size) {
	stck=new int[size];
	tos=-1;
}
int Change_Stck(int size){
	return stck[size];
}

public void push(int item){
	if(tos==stck.length-1){
		int temp[]=new int[stck.length+1];
		for(int i=0;i<stck.length;i++)temp[i]=stck[i];
		stck=temp;
		stck[++tos]=item;
	}
	else
		stck[++tos]=item;
}
public int pop(){
	if(tos<0){
		System.out.println("Stack Underflow");
		return 0;
	}
	else return stck[tos--];
}

public void display(){
	for(int x=0;x<stck.length;x++){
		System.out.print(stck[x]+" ");
	}
	System.out.println();
}

}

File-name: Exec.java
(with the main class)

import java.util.*;
public class Exec {

private static Scanner in;

public static void main(String[] args) {
	in = new Scanner(System.in);
	int option,item,i=1;
	DStack obj=new DStack();
	obj.Init_Stck(1);
	do{
		System.out.println();
		System.out.println("--MENU--");
		System.out.println("1. Push a Value in The Stack");
		System.out.println("2. Pop a Value from the Stack");
		System.out.println("3. Display Stack");
		System.out.println("4. Exit");
		option=in.nextInt();
		switch(option){
		case 1:
			System.out.println("Enter the Value to be Pushed");
			item=in.nextInt();
			obj.push(item);
			break;
		case 2:
			System.out.println("Popped Item: "+obj.pop());
			obj.Change_Stck(obj.tos);
			break;
		case 3:
			System.out.println("Displaying...");
			obj.display();
			break;
		case 4:
			System.out.println("Exiting...");
			i=0;
			break;
		default:
			System.out.println("Enter a Valid Value");
				
		}
	}while(i==1);

}

}

Hope this solves your query.

Solution 18 - Java

You can do some thing

private  static Person []  addPersons(Person[] persons, Person personToAdd) {
	int currentLenght = persons.length;
	
	Person [] personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
	personsArrayNew[currentLenght]  = personToAdd;
	
	return personsArrayNew;
	
}

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