Java 8 Stream API to find Unique Object matching a property value

JavaFilterJava 8Java Stream

Java Problem Overview


Find the object matching with a Property value from a Collection using Java 8 Stream.

List<Person> objects = new ArrayList<>();

Person attributes -> Name, Phone, Email.

Iterate through list of Persons and find object matching email. Saw that this can be done through Java 8 stream easily. But that will still return a collection?

Ex:

List<Person> matchingObjects = objects.stream.
    filter(p -> p.email().equals("testemail")).
    collect(Collectors.toList());

But I know that it will always have one unique object. Can we do something instead of Collectors.toList so that i got the actual object directly.Instead of getting the list of objects.

Java Solutions


Solution 1 - Java

Instead of using a collector try using findFirst or findAny.

Optional<Person> matchingObject = objects.stream().
    filter(p -> p.email().equals("testemail")).
    findFirst();

This returns an Optional since the list might not contain that object.

If you're sure that the list always contains that person you can call:

Person person = matchingObject.get();

Be careful though! get throws NoSuchElementException if no value is present. Therefore it is strongly advised that you first ensure that the value is present (either with isPresent or better, use ifPresent, map, orElse or any of the other alternatives found in the Optional class).

If you're okay with a null reference if there is no such person, then:

Person person = matchingObject.orElse(null);

If possible, I would try to avoid going with the null reference route though. Other alternatives methods in the Optional class (ifPresent, map etc) can solve many use cases. Where I have found myself using orElse(null) is only when I have existing code that was designed to accept null references in some cases.


Optionals have other useful methods as well. Take a look at Optional javadoc.

Solution 2 - Java

findAny & orElse

By using findAny() and orElse():

Person matchingObject = objects.stream().
filter(p -> p.email().equals("testemail")).
findAny().orElse(null);

Stops looking after finding an occurrence.

>findAny > >Optional<T> findAny() > >Returns an Optional describing some element of the stream, or an empty Optional if the stream is empty. This is a short-circuiting terminal operation. The behavior of this operation is explicitly nondeterministic; it is free to select any element in the stream. This is to allow for maximal performance in parallel operations; the cost is that multiple invocations on the same source may not return the same result. (If a stable result is desired, use findFirst() instead.)

Solution 3 - Java

Guava API provides MoreCollectors.onlyElement() which is a collector that takes a stream containing exactly one element and returns that element.

The returned collector throws an IllegalArgumentException if the stream consists of two or more elements, and a NoSuchElementException if the stream is empty.

Refer the below code for usage:

import static com.google.common.collect.MoreCollectors.onlyElement;

Person matchingPerson = objects.stream
                        .filter(p -> p.email().equals("testemail"))
                        .collect(onlyElement());

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSantoshView Question on Stackoverflow
Solution 1 - JavaIndrek OtsView Answer on Stackoverflow
Solution 2 - JavaBijaya Bhaskar SwainView Answer on Stackoverflow
Solution 3 - JavaSahil ChhabraView Answer on Stackoverflow