Probably the easiest thing to do is just use `gunzip` to do it:

    curl -sH &#39;Accept-encoding: gzip&#39; http://example.com/ | gunzip -

Or there&#39;s also `--compressed`, which `curl` will decompress (I believe) since it knows the response is compressed. But, not sure if that meets your needs.

`curl --compressed http://example.com` requests gzipped-compressed data and uncompresses it before writing to disk.

I am trying to use forward declarations in header files to reduce the number of `#include` used and hence reduce dependencies when users include my header file.

However, I am unable to forward declare where namespaces are used.  See example below.

File `a.hpp`:

    #ifndef __A_HPP__
    #define __A_HPP__
    
    namespace ns1 {
    
       class a {
       public:
          a(const char* const msg);
    
          void talk() const;
    
       private:
          const char* const msg_;
       };
    }
    
    #endif //__A_HPP__

File `a.cpp`:

    #include &lt;iostream&gt;

    #include &quot;a.hpp&quot;

    using namespace ns1;

    a::a(const char* const msg) : msg_(msg) {}

    void a::talk() const { 
       std::cout &lt;&lt; msg_ &lt;&lt; std::endl; 
    }


    
File `consumer.hpp`:

    #ifndef __CONSUMER_HPP__
    #define __CONSUMER_HPP__
    
    // How can I forward declare a class which uses a namespace
    //doing this below results in error C2653: &#39;ns1&#39; : is not a class or namespace name
    // Works with no namespace or if I use using namespace ns1 in header file
    // but I am trying to reduce any dependencies in this header file
    class ns1::a;
    
    class consumer
    {
    public:
       consumer(const char* const text) : a_(text) {}
       void chat() const;
    
    private:
       a&amp; a_;
    };
    
    #endif // __CONSUMER_HPP__
    
Implementation file `consumer.cpp`:

    #include &quot;consumer.hpp&quot;
    #include &quot;a.hpp&quot;
    
    consumer::consumer(const char* const text) : a_(text) {}
    
    void consumer::chat() const {
       a_.talk();
    }
    
Test file `main.cpp`:

    #include &quot;consumer.hpp&quot;
    
    int main() {
       consumer c(&quot;My message&quot;);
       c.chat();
       return 0;
    }

---
**UPDATE**:

Here is my very contrived working code using the answer below.

File `a.hpp`:

    #ifndef A_HPP__
    #define A_HPP__
    
    #include &lt;string&gt;
    
    namespace ns1 {
    
       class a {
       public:
          void set_message(const std::string&amp; msg);
          void talk() const;
    
       private:
          std::string msg_;
       };
    
    } //namespace
    
    #endif //A_HPP__
    
File `a.cpp`:

    #include &lt;iostream&gt;
    #include &quot;a.hpp&quot;
    
    void ns1::a::set_message(const std::string&amp; msg) {
        msg_ = msg;
    }
    void ns1::a::talk() const { 
       std::cout &lt;&lt; msg_ &lt;&lt; std::endl; 
    }
    
File `consumer.hpp`:

    #ifndef CONSUMER_HPP__
    #define CONSUMER_HPP__
    
    namespace ns1
    {
       class a;
    }
    
    class consumer
    {
    public:
       consumer(const char* text);
       ~consumer();
       void chat() const;
    
    private:
       ns1::a* a_;
    };
    
    #endif // CONSUMER_HPP__
    
File `consumer.cpp`:

    #include &quot;a.hpp&quot;
    #include &quot;consumer.hpp&quot;
    
    consumer::consumer(const char* text) {
       a_ = new ns1::a;
       a_-&gt;set_message(text);
    }
    consumer::~consumer() {
       delete a_;
    }
    void consumer::chat() const {
       a_-&gt;talk();
    }
    
    
File `main.cpp`:

    #include &quot;consumer.hpp&quot;
    
    int main() {
       consumer c(&quot;My message&quot;);
       c.chat();
       return 0;
    }


How to forward declare a class which is in a namespace

In Eclipse I have a simple Java project that contains a package named **(default package)** and inside this package I have a class.

I want to rename this package into something like: **com.myCompany.executable**

I tried to select the **(default package) ---&gt; right click ---&gt; refactor** but now I see only the single voice named: **Infer generic type arguments** but not the possibility to change the package name.

Why? What have I to do in Eclipse to change the name of the package?

How to change a package name in Eclipse?

Is there any way to get curl to decompress a response without sending the Accept-encoding headers in the request?

I&#39;m trying to debug an issue where the order of the Accept-encoding headers may be relevant, but I also need to know what the response is.  If I just send `-H &#39;Accept-encoding: gzip` and the server gzips the response, curl won&#39;t decompress it.

Is there any way to get curl to decompress a response without sending the Accept headers in the request?

<p>Is there any way to get curl to decompress a response without sending the Accept-encoding headers in the request?</p>
<p>I'm trying to debug an issue where the order of the Accept-encoding headers may be relevant, but I also need to know what the response is.  If I just send <code>-H 'Accept-encoding: gzip</code> and the server gzips the response, curl won't decompress it.</p>


I used this syntax to post a file along with some parameters:

    curl -v -include --form &quot;key1=value1&quot; --form upload=localfilename URL

The file is around 500K in size. First of all, I see content length to be 254 on the transmit side. Later the server response&#39;s content length is 0. 
Where am I going wrong? 

Here is the complete trace of the command.

    * Couldn&#39;t find host xxx.xxx.xxx.xxx in the _netrc file; using defaults
    * About to connect() to xxx.xxx.xxx.xxx port yyyy (#0)
    *   Trying xxx.xxx.xxx.xxx...
    * Adding handle: conn: 0x4b96a0
    * Adding handle: send: 0
    * Adding handle: recv: 0
    * Curl_addHandleToPipeline: length: 1
    * - Conn 0 (0x4b96a0) send_pipe: 1, recv_pipe: 0
    * Connected to xxx.xxx.xxx.xxx (xxx.xxx.xxx.xxx) port yyyy (#0)
    * POST /zzzzzz/UploadFile HTTP/1.1
    * User-Agent: curl/7.32.0
    * Host: xxx.xxx.xxx.xxx:yyyy
    * Accept: */*
    * Content-Length: 254
    * Expect: 100-continue
    * Content-Type: multipart/form-data; boundary=------------------------948a6137eef50079
    *
    * HTTP/1.1 100 Continue
    * HTTP/1.1 100 Continue
    
    * HTTP/1.1 200 OK
    * HTTP/1.1 200 OK
    * Server Apache-Coyote/1.1 is not blacklisted
    * Server: Apache-Coyote/1.1
    * Server: Apache-Coyote/1.1
    * Added cookie JSESSIONID=&quot;C1D7DD042E250211D9DEA82688876F88&quot; for domain xxx.xxx.xxx.xxx, path /zzzzz/, expire 0
    * Set-Cookie: JSESSIONID=C1D7DD042E250211D9DEA82688876F88; Path=/zzzzzz/;
    * HttpOnly
    * Set-Cookie: JSESSIONID=C1D7DD042E250211D9DEA82688876F88; Path=/zzzzzz/; HttpOnly
    * Content-Type: text/html;charset=ISO-8859-1
    Content-Type: text/html;charset=ISO-8859-1
    * Content-Length: 0
    * Content-Length: 0
    * Date: Tue, 01 Oct 2013 11:54:24 GMT
    * Date: Tue, 01 Oct 2013 11:54:24 GMT
    * Connection #0 to host xxx.xxx.xxx.xxx left intact



What is the right way to POST multipart/form-data using curl?

I&#39;m trying to install Facebook PHP SDK with Composer. This is what I get

    $ composer install
    Loading composer repositories with package information
    Installing dependencies (including require-dev)
    Your requirements could not be resolved to an installable set of packages.

        Problem 1
            - Installation request for facebook/php-sdk dev-master -&gt; satisfiable by facebook/php-sdk[dev-master].
            - facebook/php-sdk dev-master requires ext-curl * -&gt; the requested PHP extension curl is missing from your system.

Problem is, I have curl extension enabled (uncommented in php.ini). When I run `phpinfo()`, it says it&#39;s enabled.
Only clue I have is that when I run `$ php -m`, &#39;curl&#39; line is missing but I don&#39;t know what to do about it.

I have wamp 2.4 on Win8 and I&#39;m running composer in cmd.exe.

Composer install error - requires ext_curl when it&#39;s actually enabled

I know I can use the following 2 commands to download a file:

    curl -O example.com/file.zip
    wget example.com/file.zip

But I want them to go into a specific directory. So I can do the following:

    curl -o mydir/file.zip example.com/file.zip
    wget -O mydir/file.zip example.com/file.zip

Is there a way to not have to specify the filename? Something like this:

    curl -dir mydir example.com/file.zip



How to download a file into a directory using curl or wget?

I&#39;m working with `curl` in Linux. I&#39;m downloading a part of a file in ftp server (using the `-r` option), but my connection is not good, it always interrupts. I want to write a script which resume download when I&#39;m connected again.

I&#39;ve used this command, but it&#39;s not working: 

    until curl -r 666-9999 -C - --retry 999 -o &quot;path/to/file&quot; &quot;ftp:/path/to/remote/file&quot;; do :; done

How to resume interrupted download automatically in curl?

I am having problem with PHP curl request with basic authorization.

Here is the command line curl:

    curl -H &quot;Accept: application/product+xml&quot; &quot;https://{id}:{api_key}@api.domain.com/products?limit=1&amp;offset=0&quot;

I have tried by setting curl header in following ways but it&#39;s not working

    Authorization: Basic id:api_key
    or 
    Authorization: Basic {id}:{api_key}

I get the response &quot;authentication parameter in the request are missing or invalid&quot; but I have used proper id and api_key which is working in command line curl (I tested)

Please help me.

How to use basic authorization in PHP curl

The compression algorithm used in *zlib* is essentially the same as that in *gzip* and *zip*. What are *gzip* and *zip*? How are they different and how are they same?

How are zlib, gzip and zip related? What do they have in common and how are they different?

I am trying to connect to an api, that returns GZip encoded JSON, from a WCF service (WCF service to WCF service). I am using the **HTTPClient** to connect to the API and have been able to return the JSON object as a string. However I need to be able to store this returned data in a database and as such I figured the best way would be to return and store the JSON object in an array or byte or something along those lines. 

What I am having trouble with specifically is the decompressing of the GZip encoding and have been trying lots of different example but still cant get it. 

The below code is how I am establishing my connection and getting a response, this is the code that returns a string from the API.

    public string getData(string foo)
    {
        string url = &quot;&quot;;
        HttpClient client = new HttpClient();
        HttpResponseMessage response;
        string responseJsonContent;
        try
        {
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue(&quot;application/json&quot;));
            response = client.GetAsync(url + foo).Result;
            responseJsonContent = response.Content.ReadAsStringAsync().Result;
            return responseJsonContent;
        }
        catch (Exception ex)
        {
            System.Windows.Forms.MessageBox.Show(ex.Message);
            return &quot;&quot;;
        }
    }

I have been following a few different examples like these [StackExchange API][1], [MSDN][2], and a couple on stackoverflow, but I haven&#39;t been able to get any of these to work for me. 

What is the best way to accomplish this, am I even on the right track? 

Thanks guys.

  [1]: https://web.archive.org/web/20150312130407/http://cgeers.com/2011/10/02/stack-exchange-api/
  [2]: https://msdn.microsoft.com/en-us/library/system.io.compression.gzipstream%28v=vs.110%29.aspx

Decompressing GZip Stream from HTTPClient Response

We use Spring Boot/MVC with annotation-based java-config for series of RESTful services and we want to selectively enable HTTP GZIP stream compression on some API responses.

I know I can do this manually in my controller and a `byte[] @ResponseBody`, however we&#39;d prefer to rely on the Spring MVC infrastructure (filters/etc) and have it automatically do the JSON conversion and compression (i.e. the method returns a POJO).

How can I enable GZIP compression in the ResponseBody or embedded Tomcat instance, and in a way we can selectively compress only some responses?

We don&#39;t currently have any XML based configuration.

Using GZIP compression with Spring Boot/MVC/JavaConfig with RESTful

I&#39;m serving gzipped copies of my css / javascript files. As per a tutorial, I set the content-type as `application/gzip` when serving these files. However, chrome doesn&#39;t seem to un-gzip these files, and for the javascript files I get a lot of &#39;illegal character&#39; errors. If I view source, I still see the files as compressed, rather than uncompressed.

My question is, what should I set as the content type for these files, in order for the browser to interpret them correctly as gzipped css / js files, and un-gzip them? If I just set `text/javascript` or `text/css`, will the browser still interpret them correctly?

Edit: Full response headers:

    HTTP/1.1 200 OK
    x-amz-id-2: UIBkZT/MuFxsmn+3nVOzEO63rRY99l3traCbMExUgSdGHUrOIPtNp34h1+ujYKmt
    x-amz-request-id: 19346C9B01D8FC62
    Date: Mon, 12 May 2014 03:59:51 GMT
    Content-Encoding: gzip
    Last-Modified: Mon, 12 May 2014 02:24:54 GMT
    ETag: &quot;561080b5e19f6daea2e74fd5a0623c79&quot;
    Accept-Ranges: bytes
    Content-Type: application/x-gzip
    Content-Length: 5153
    Server: AmazonS3



What &#39;Content-Type&#39; header to use when serving gzipped files?

I wanted to try out the python BytesIO class.

As an experiment I tried writing to a zip file in memory, and then reading the bytes back out of that zip file. So instead of passing in a file-object to `gzip`, I pass in a `BytesIO` object. Here is the entire script:

    from io import BytesIO
    import gzip

    # write bytes to zip file in memory
    myio = BytesIO()
    with gzip.GzipFile(fileobj=myio, mode=&#39;wb&#39;) as g:
        g.write(b&quot;does it work&quot;)
    
    # read bytes from zip file in memory
    with gzip.GzipFile(fileobj=myio, mode=&#39;rb&#39;) as g:
        result = g.read()

    print(result)

But it is returning an empty `bytes` object for `result`. This happens in both Python 2.7 and 3.4. What am I missing?


Content Type	Original Author	Original Content on Stackoverflow
Question	Jun-Dai Bates-Kobashigawa	View Question on Stackoverflow
Solution 1 - Curl	FatalError	View Answer on Stackoverflow
Solution 2 - Curl	thakis	View Answer on Stackoverflow

Is there any way to get curl to decompress a response without sending the Accept headers in the request?

Curl Problem Overview

Curl Solutions

Solution 1 - Curl

Solution 2 - Curl

How to change a package name in Eclipse?

How to forward declare a class which is in a namespace

Attributions