Is there a way to interpolate CSS variables with url()?

CssCss Variables

Css Problem Overview


I want to store my background URLs in custom properties (CSS variables) and use them with the background property. However, I couldn't find a way to interpolate the string when using it as a parameter in url().

Here is my sample code:

:root {
    --url: "https://download.unsplash.com/photo-1420708392410-3c593b80d416";
}

body {
    background: url(var(--url));
}

I know that this can be easily done in Sass or LESS using the interpolation function but I'm curious if there is a way to do it without any pre-processor.

Css Solutions


Solution 1 - Css

You can perform interpolation with most CSS functions, including rgba() (see an example here). In fact, interpolation is one of the main features of custom properties.

But you cannot do this with url(), as url(var(--url)) is parsed not as a url( function token followed by var(--url) followed by a ), but a single url() token that is invalid because the var(--url) is being treated as a URL itself, and unquoted URLs in url() tokens cannot contain parentheses unless they are escaped. This means the substitution never actually occurs, because the parser never sees any var() expressions in the property value — indeed, your background declaration is completely invalid.

If you didn't understand any of that, that's fine. Just know that you cannot use var() interpolation with url() due to legacy reasons.

Even though the problem depicted in the question is related to the legacy url() token, you cannot do this by building URL tokens out of several var() expressions either, in case you were thinking of trying something like --uo: url(; --uc: ); or --uo: url("; --uc: ");, and background: var(--uo) var(--url) var(--uc);. This is because custom properties cannot contain unmatched string delimiters or parts of url() tokens (called bad URL tokens).

If you want to specify a URL in a custom property, you need to write out the entire url() expression, and substitute that entire expression:

:root {
  --url: url("https://download.unsplash.com/photo-1420708392410-3c593b80d416");
}

body {
  background: var(--url);
}

Or, use JavaScript instead of var() to perform the interpolation.

Solution 2 - Css

You cannot interpolate css variables with url but what you can do is to implement the url function as part of your variable like this:

:root {
    --url: url("https://download.unsplash.com/photo-1420708392410-3c593b80d416");
}

body {
    background: var(--url);
}

in HTML could be:

<div class="css_class_setting_background" style=" --url: url("https://download.unsplash.com/photo-1420708392410-3c593b80d416");"> </div>

This works on most of modern browsers.

Solution 3 - Css

I had the same issue on a project with Cordova so I used:

header{
  --bg-header: url(../img/header_home.png) left center/cover no-repeat;
  background: var(--bg-header,
      url("../img/header_home.png") left center/cover no-repeat
  );
}

Apparently, if you use url("") with double quotes on the --var declaration, the value will not work.

Solution 4 - Css

here is the solution which works in vue3

<script setup>
const backImage = ref("url(/img/imImage.webp)")
</script>

<style>
div {
  background-image: v-bind(backImage );
}
</style>

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionYashAroraView Question on Stackoverflow
Solution 1 - CssBoltClockView Answer on Stackoverflow
Solution 2 - CssAndré RodriguezView Answer on Stackoverflow
Solution 3 - CssLucasTelesxView Answer on Stackoverflow
Solution 4 - CsshusaytView Answer on Stackoverflow