Is there a "previous sibling" selector?

Css Problem Overview

The plus sign (+) is for selecting the next sibling.

Is there an equivalent for the previous sibling?

Css Solutions

Solution 1 - Css

No, there is no "previous sibling" selector.

On a related note, ~ is for general successor sibling (meaning the element comes after this one, but not necessarily immediately after) and is a CSS3 selector. + is for next sibling and is CSS2.1.

See Adjacent sibling combinator from Selectors Level 3 and 5.7 Adjacent sibling selectors from Cascading Style Sheets Level 2 Revision 1 (CSS 2.1) Specification.

Solution 2 - Css

I found a way to style all previous siblings (opposite of ~) that may work depending on what you need.

Let's say you have a list of links and when hovering on one, all the previous ones should turn red. You can do it like this:

/* default link color is blue */
.parent a {
  color: blue;
}

/* prev siblings should be red */
.parent:hover a {
  color: red;
}
.parent a:hover,
.parent a:hover ~ a {
  color: blue;
}

<div class="parent">
  <a href="#">link</a>
  <a href="#">link</a>
  <a href="#">link</a>
  <a href="#">link</a>
  <a href="#">link</a>
</div>

Solution 3 - Css

Selectors level 4 proposes :has() (previously the subject indicator !) which will, one day, allow you to select a previous sibling with:

previous:has(+ next) {}

… but at the time of writing browser support is practically non-existent.

Solution 4 - Css

Consider the `order` property of flex and grid layouts.

I'll focus on flexbox in the examples below, but the same concepts apply to Grid.

With flexbox, a previous sibling selector can be simulated.

In particular, the flex order property can move elements around the screen.

Here's an example:

> You want element A to turn red when element B is hovered. > >

STEPS

Make the ul a flex container.
```
 ul { display: flex; }
```

Reverse the order of siblings in the mark-up.

 <ul>
    <li>B</li>
    <li>A</li>
 </ul>

Use a sibling selector to target Element A (~ or + will do) .
```
 li:hover + li { background-color: red; }
```

Use the flex order property to restore the order of siblings on the visual display.
```
 li:last-child { order: -1; }
```

...and voilà! A previous sibling selector is born (or at least simulated).

Here's the full code:

ul {
    display: flex;
}

li:hover + li {
    background-color: red;
}

li:last-child {
    order: -1;
}

/* non-essential decorative styles */
li {
    height: 200px;
    width: 200px;
    background-color: aqua;
    margin: 5px;
    list-style-type: none;
    cursor: pointer;
}

<ul>
    <li>B</li>
    <li>A</li>
</ul>

From the flexbox spec:

>5.4. Display Order: the order property > >Flex items are, by default, displayed and laid out in the same order as they appear in the source document. The order property can be used to change this ordering. > >The order property controls the order in which flex items appear within the flex container, by assigning them to ordinal groups. It takes a single <integer> value, which specifies which ordinal group the flex item belongs to.

The initial order value for all flex items is 0.

Also see order in the CSS Grid Layout spec.

Examples of "previous sibling selectors" created with the flex order property.

.container { display: flex; }

.box5 { order: 1; }    
.box5:hover + .box4 { background-color: orangered; font-size: 1.5em; }

.box6 { order: -4; }
.box7 { order: -3; }
.box8 { order: -2; }
.box9 { order: -1; }
.box9:hover ~ :not(.box12):nth-child(-1n+5) { background-color: orangered;
                                              font-size: 1.5em; }
.box12 { order: 2; }
.box12:hover ~ :nth-last-child(-1n+2) { background-color: orangered;
                                        font-size: 1.5em; }
.box21 { order: 1; }
.box21:hover ~ .box { background-color: orangered; font-size: 1.5em; }

/* non-essential decorative styles */
.container {
    padding: 5px;
    background-color: #888;
}
.box {
    height: 50px;
    width: 75px;
    margin: 5px;
    background-color: lightgreen;
    display: flex;
    justify-content: center;
    align-items: center;
    text-align: center;
    cursor: pointer;
}

<p>
Using the flex <code>order</code> property to construct a previous sibling selector
</p>

<div class="container">
    <div class="box box1"><span>1</span></div>
    <div class="box box2"><span>2</span></div>
    <div class="box box3"><span>3</span></div>
    <div class="box box5"><span>HOVER ME</span></div>
    <div class="box box4"><span>4</span></div>
</div>

<br>

<div class="container">
    <div class="box box9"><span>HOVER ME</span></div>
    <div class="box box12"><span>HOVER ME</span></div>
    <div class="box box6"><span>6</span></div>
    <div class="box box7"><span>7</span></div>
    <div class="box box8"><span>8</span></div>
    <div class="box box10"><span>10</span></div>
    <div class="box box11"><span>11</span></div>
</div>

<br>

<div class="container">
    <div class="box box21"><span>HOVER ME</span></div>
    <div class="box box13"><span>13</span></div>
    <div class="box box14"><span>14</span></div>
    <div class="box box15"><span>15</span></div>
    <div class="box box16"><span>16</span></div>
    <div class="box box17"><span>17</span></div>
    <div class="box box18"><span>18</span></div>
    <div class="box box19"><span>19</span></div>
    <div class="box box20"><span>20</span></div>
</div>

jsFiddle

A Side Note – Two Outdated Beliefs about CSS

Flexbox is shattering long-held beliefs about CSS.

One such belief is that a previous sibling selector is not possible in CSS.

To say this belief is widespread would be an understatement. Here's a sampling of related questions on Stack Overflow alone:

As described above, this belief is not entirely true. A previous sibling selector can be simulated in CSS using the flex order property.

The z-index Myth

Another long-standing belief has been that z-index works only on positioned elements.

In fact, the most current version of the spec – the W3C Editor's Draft – still asserts this to be true:

> 9.9.1 Specifying the stack level: the z-index > property > > z-index > > - Value: auto | | inherit > - Initial: auto > - Applies to: positioned elements > - Inherited: no > - Percentages: N/A > - Media: visual > - Computed value: as specified > > _{(emphasis added)}

In reality, however, this information is obsolete and inaccurate.

Elements that are flex items or grid items can create stacking contexts even when position is static.

>4.3. Flex Item Z-Ordering > >Flex items paint exactly the same as inline blocks, except that order-modified document order is used in place of raw document order, and z-index values other than auto create a stacking context even if position is static.

>5.4. Z-axis Ordering: the z-index property > >The painting order of grid items is exactly the same as inline blocks, except that order-modified document order is >used in place of raw document order, and z-index values other than auto create a stacking context even if >position is static.

Here's a demonstration of z-index working on non-positioned flex items: https://jsfiddle.net/m0wddwxs/

Solution 5 - Css

I had the same question, but then I had a "duh" moment. Instead of writing

x ~ y

write

y ~ x

Obviously this matches "x" instead of "y", but it answers the "is there a match?" question, and simple DOM traversal may get you to the right element more efficiently than looping in javascript.

I realize that the original question was a CSS question so this answer is probably completely irrelevant, but other Javascript users may stumble on the question via search like I did.

Solution 6 - Css

There's not "previous selector", but you can use the combination of :not and ~ ("after selector"). No reverse order, no javascript.

.parent a{
  color: blue
}

.parent a.active{
  color: red
}

.parent a:not(.parent a.active ~ a){
  color: red
}

<div class="parent">
  <a href="">link</a>
  <a href="">link</a>
  <a href="" class="active">link</a>
  <a href="">link</a>
  <a href="">link</a>
</div>

I think my approach is more straight-forward than "style all divs, than remove styling for after divs", or using javascript, or using reverse order.

Solution 7 - Css

> + is for the next sibling. Is there an equivalent for the previous > sibling?

You can use the two axe selectors: `!` and `?`

There are 2 subsequent sibling selectors in conventional CSS:

+ is the immediate subsequent sibling selector
~ is the any subsequent sibling selector

In conventional CSS, there is no previous sibling selector.

However, in the axe CSS post-processor library, there are 2 previous sibling selectors:

? is the immediate previous sibling selector (opposite of +)
! is the any previous sibling selector (opposite of ~)

Working Example:

In the example below:

.any-subsequent:hover ~ div selects any subsequent div
.immediate-subsequent:hover + div selects the immediate subsequent div
.any-previous:hover ! div selects any previous div
.immediate-previous:hover ? div selects the immediate previous div

div {
  display: inline-block;
  width: 60px;
  height: 100px;
  color: rgb(255, 255, 255);
  background-color: rgb(255, 0, 0);
  text-align: center;
  vertical-align: top;
  cursor: pointer;
  opacity: 0;
  transition: opacity 0.6s ease-out;
}

code {
  display: block;
  margin: 4px;
  font-size: 24px;
  line-height: 24px;
  background-color: rgba(0, 0, 0, 0.5);
}

div:nth-of-type(-n+4) {
  background-color: rgb(0, 0, 255);
}

div:nth-of-type(n+3):nth-of-type(-n+6) {
  opacity: 1;
}

.any-subsequent:hover ~ div,
.immediate-subsequent:hover + div,
.any-previous:hover ! div,
.immediate-previous:hover ? div {
  opacity: 1;
}

<h2>Hover over any of the blocks below</h2>

<div></div>
<div></div>

<div class="immediate-previous">Hover for <code>?</code> selector</div>
<div class="any-previous">Hover for <code>!</code> selector</div>
<div class="any-subsequent">Hover for <code>~</code> selector</div>
<div class="immediate-subsequent">Hover for <code>+</code> selector</div>

<div></div>
<div></div>

<script src="https://rouninmedia.github.io/axe/axe.js"></script>

Solution 8 - Css

Three tricks:
basically, reversing the HTML order of your elements in HTML,
and using the ~ Next siblings operator:

1. Using CSS Flex and row-reverse

.reverse {
  display: inline-flex;
  flex-direction: row-reverse;
}
.reverse span:hover ~ span { /* On SPAN hover target its "previous" elements */
  background:gold;
}

Hover a SPAN and see the previous elements being styled!<br>

<div class="reverse">
  <!-- Reverse the order of inner elements -->
  <span>5</span>
  <span>4</span>
  <span>3</span>
  <span>2</span>
  <span>1</span>
</div>

2. Using Flex with direction: RTL

.reverse {
  display: inline-flex;
  direction: rtl;
}
.reverse span:hover ~ span { /* On SPAN hover target its "previous" elements */
  background: red;
}

Hover a SPAN and see the previous elements being styled!<br>

<div class="reverse">
  <!-- Reverse the order of inner elements -->
  <span>5</span>
  <span>4</span>
  <span>3</span>
  <span>2</span>
  <span>1</span>
</div>

3. Using float right

.reverse { 
  display: inline-block;
}
.reverse span{
  float: right; 
}
.reverse span:hover ~ span { /* On SPAN hover target its "previous" elements */
  background: red;
}

Hover a SPAN and see the previous elements being styled!<br>

<div class="reverse">
  <!-- Reverse the order of inner elements -->
  <span>5</span>
  <span>4</span>
  <span>3</span>
  <span>2</span>
  <span>1</span>
</div>

Solution 9 - Css

Another flexbox solution

You can use inverse the order of elements in HTML. Then besides using order as in Michael_B's answer you can use flex-direction: row-reverse; or flex-direction: column-reverse; depending on your layout.

Working sample:

.flex {
  display: flex;
  flex-direction: row-reverse;
   /* Align content at the "reversed" end i.e. beginning */
  justify-content: flex-end;
}

/* On hover target its "previous" elements */
.flex-item:hover ~ .flex-item {
  background-color: lime;
}

/* styles just for demo */
.flex-item {
  background-color: orange;
  color: white;
  padding: 20px;
  font-size: 3rem;
  border-radius: 50%;
}

<div class="flex">
  <div class="flex-item">5</div>
  <div class="flex-item">4</div>
  <div class="flex-item">3</div>
  <div class="flex-item">2</div>
  <div class="flex-item">1</div>
</div>

Solution 10 - Css

There is no official way to do that at the moment but you can use a little trick to achieve this ! Remember that it is experimental and it has some limitation ... (check this link if you worries about navigator compatibility )

What you can do is use a CSS3 selector : the pseudo classe called nth-child()

#list>* {
  display: inline-block;
  padding: 20px 28px;
  margin-right: 5px;
  border: 1px solid #bbb;
  background: #ddd;
  color: #444;
  margin: 0.4em 0;
}

#list :nth-child(-n+4) {
  color: #600b90;
  border: 1px dashed red;
  background: orange;
}

<p>The oranges elements are the previous sibling li selected using li:nth-child(-n+4)</p>

<div id="list">
  <span>1</span><!-- this will be selected -->
  <p>2</p><!-- this will be selected -->
  <p>3</p><!-- this will be selected -->
  <div>4</div><!-- this will be selected -->
  <div>5</div>
  <p>6</p>
  <p>7</p>
  <p>8</p>
  <p>9</p>
</div>

Limitations

You can't select previous elements based on the classes of the next elements
This is the same for pseudo classes

Solution 11 - Css

You could use double negation

SELECTOR:not([SELECTOR]FILTER):not([SELECTOR]FILTER + SELECTOR) { ... }

Replace SELECTOR with either the TAG or .CLASS ( Using #ID is probably too specific ). Replace FILTER with some other :PSUEDO-SELECTOR (I've only tried :hover) or .CLASS (More for toggling through Javascript).

Since the typical usage will probably rely upon hovering (See example that follows)

/* Effect only limited when hovering */
TAG.CLASS:not(TAG.CLASS:hover):not(TAG.CLASS:hover + TAG.CLASS) {}
/* Effect only applied when hovering */
PARENT.CLASS:hover > CHILD.CLASS:not(CHILD.CLASS:hover):not(CHILD.CLASS:hover + CHILD.CLASS) {}

/* Solution */
div.parent:hover > div.child:not(:hover):not(:hover ~ .child)  {
    background-color:red;
    border-radius:1.5em;
}
div.parent:hover > div.child:not(:hover):not(:hover ~ .child) > div {
    background-color:yellow;
}

/* Make pretty (kinda) */
div.parent {
  width:9em;
  height:9em;
  /* Layout */
  display:grid;
  grid-template-columns : auto auto auto;
  grid-template-rows : auto auto auto;
}
div.child {
  /* Dimensions */
  height:3em;
  width:3em;
  /* Layout */
  position:relative;
  /* Cursor */
  cursor: pointer;
  /* Presentation */
  border: 1px black solid;
  border-radius:1.5em;
}
.star {
  /* Dimensions */
  width: 2.5em;
  height: 2.5em;
  /* Placement */
  position:absolute;
  top: 50%;
  left: 50%;
  transform:translate(-50%,-50%);
  /* Geometry */
  -webkit-clip-path: polygon(
    50% 0%,
    63% 38%,
    100% 38%,
    69% 59%,
    82% 100%,
    50% 75%,
    18% 100%,
    31% 59%,
    0% 38%,
    37% 38%
  );
  clip-path: polygon(
    50% 0%,
    63% 38%,
    100% 38%,
    69% 59%,
    82% 100%,
    50% 75%,
    18% 100%,
    31% 59%,
    0% 38%,
    37% 38%
  );
  /* Presentation */
  background-color: lightgrey;
}
div.child:hover {
    /* Presentation */
    background-color:yellow;
    border-radius:1.5em;
}
div.child:hover > div.star {
    /* Presentation */
    background-color:red;
}

<div class="parent">
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
  <div class="child" href="#"><div class="star"></div></div>
 </div>

Solution 12 - Css

No. It is not possible via CSS. It takes the "Cascade" to heart ;-).

However, if you are able to add JavaScript to your page, a little bit of jQuery could get you to your end goal.
You can use jQuery's find to perform a "look-ahead" on your target element/class/id, then backtrack to select your target.
Then you use jQuery to re-write the DOM (CSS) for your element.

Based on this answer by Mike Brant, the following jQuery snippet could help.

$('p + ul').prev('p')

This first selects all <ul>s that immediately follow a <p>.
Then it "backtracks" to select all the previous <p>s from that set of <ul>s.

Effectively, "previous sibling" has been selected via jQuery.
Now, use the .css function to pass in your CSS new values for that element.

In my case I was looking to find a way to select a DIV with the id #full-width, but ONLY if it had a (indirect) descendant DIV with the class of .companies.

I had control of all the HTML under .companies, but could not alter any of the HTML above it.
And the cascade goes only 1 direction: down.

Thus I could select ALL #full-widths.
Or I could select .companies that only followed a #full-width.
But I could not select only #full-widths that proceeded .companies.

And, again, I was unable to add .companies any higher up in the HTML. That part of the HTML was written externally, and wrapped our code.

But with jQuery, I can select the required #full-widths, then assign the appropriate style:

$("#full-width").find(".companies").parents("#full-width").css( "width", "300px" );

This finds all #full-width .companies, and selects just those .companies, similar to how selectors are used to target specific elements in standard in CSS.
Then it uses .parents to "backtrack" and select ALL parents of .companies,
but filters those results to keep only #fill-width elements, so that in the end,
it only selects a #full-width element if it has a .companies class descendant.
Finally, it assigns a new CSS (width) value to the resulting element.

$(".parent").find(".change-parent").parents(".parent").css( "background-color", "darkred");

div {
  background-color: lightblue;
  width: 120px;
  height: 40px;
  border: 1px solid gray;
  padding: 5px;
}
.wrapper {
  background-color: blue;
  width: 250px;
  height: 165px;
}
.parent {
  background-color: green;
  width: 200px;
  height: 70px;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<html>
<div class="wrapper">

  <div class="parent">
    "parent" turns red
    <div class="change-parent">
    descendant: "change-parent"
    </div>
  </div>
  
  <div class="parent">
    "parent" stays green
    <div class="nope">
    descendant: "nope"
    </div>
  </div>
  
</div>
Target <b>"<span style="color:darkgreen">parent</span>"</b> to turn <span style="color:red">red</span>.<br>
<b>Only</b> if it <b>has</b> a descendant of "change-parent".<br>
<br>
(reverse cascade, look ahead, parent un-descendant)
</html>

jQuery Reference Docs:
$() or jQuery(): DOM element.
.find: Get the descendants of each element in the current set of matched elements, filtered by a selector, jQuery object, or element.
.parents: Get the immediately preceding sibling of each element in the set of matched elements. If a selector is provided, it retrieves the previous sibling only if it matches that selector (filters the results to only include the listed elements/selectors).
.css: Set one or more CSS properties for the set of matched elements.

Solution 13 - Css

If you know the exact position an :nth-child()-based exclusion of all following siblings would work.

ul li:not(:nth-child(n+3))

Which would select all lis before the 3rd (e.g. 1st and 2nd). But, in my opinion this looks ugly and has a very tight usecase.

You also could select the nth-child right-to-left:

ul li:nth-child(-n+2)

Which does the same.

Solution 14 - Css

Overriding the styles of next siblings on hover, so that it looks like only previous siblings have styles added on hover.

ul li {
  color: red;
}

ul:hover li {
  color: blue;
}

ul:hover li:hover ~ li{
  color: red;
}

<ul>
    <li>item 1</li>
    <li>item 2</li>
    <li>item 3</li>
</ul>

Solution 15 - Css

Depending on your exact objective, there is a way to achieve the usefulness of a parent selector without using one (even if one were to exist)...

Say we have:

<div>
  <ul>
    <li><a>Pants</a></li>
    <li><a>Socks</a></li>
    <ul>
      <li><a>White socks</a></li>
      <li><a>Blue socks</a></li>
    </ul>
  </ul>
</div>

What can we do to make the Socks block (including sock colours) stand out visually using spacing?

What would be nice but doesn't exist:

ul li ul:parent {
  margin-top: 15px;
  margin-bottom: 15px;
}

What does exist:

li > a {
  margin-top: 15px;
  display: block;
}
li > a:only-child {
  margin-top: 0px;
}

This sets all anchor links to have 15px margin on the top and resets it back to 0 for those with no UL elements (or other tags) inside LIs.

Solution 16 - Css

/* Add a style to all the children, then undo the style to the target 
and sibling children of your target. */

ul>li {
  color: red;
}

ul>li.target,
ul>li.target~li {
  color: inherit;
}

<ul>
  <li>before</li>
  <li class="target">target</li>
  <li>after</li>
  <li>after</li>
</ul>

Solution 17 - Css

There is no "previous" sibling selector unfortunately, but you can possibly still get the same effect by using positioning (e.g. float right). It depends on what you are trying to do.

In my case, I wanted a primarily CSS 5-star rating system. I would need to color (or swap the icon of) the previous stars. By floating each element right, I am essentially getting the same effect (the html for the stars thus must be written 'backwards').

I'm using FontAwesome in this example and swapping between the unicodes of fa-star-o and fa-star http://fortawesome.github.io/Font-Awesome/

CSS:

.fa {
    display: inline-block;
    font-family: FontAwesome;
    font-style: normal;
    font-weight: normal;
    line-height: 1;
    -webkit-font-smoothing: antialiased;
    -moz-osx-font-smoothing: grayscale;
}

/* set all stars to 'empty star' */
.stars-container {
    display: inline-block;      
}   

/* set all stars to 'empty star' */
.stars-container .star {
    float: right;
    display: inline-block;
    padding: 2px;
    color: orange;
    cursor: pointer;
    
}

.stars-container .star:before {
    content: "\f006"; /* fontAwesome empty star code */
}

/* set hovered star to 'filled star' */
.star:hover:before{
    content: "\f005"; /* fontAwesome filled star code */
}

/* set all stars after hovered to'filled star' 
** it will appear that it selects all after due to positioning */
.star:hover ~ .star:before {
    content: "\f005"; /* fontAwesome filled star code */
}

HTML:

(40)

JSFiddle: http://jsfiddle.net/andrewleyva/88j0105g/

Solution 18 - Css

I needed a solution to select the previous sibling tr. I came up with this solution using React and Styled-components. This is not my exact solution (This is from memory, hours later). I know there is a flaw in the setHighlighterRow function.

OnMouseOver a row will set the row index to state, and rerender the previous row with a new background color

class ReactClass extends Component {
  constructor() {
    this.state = {
       highlightRowIndex: null
    }
  }

  setHighlightedRow = (index) => {
    const highlightRowIndex = index === null ? null : index - 1;
    this.setState({highlightRowIndex});
  }

  render() {
    return (
       <Table>
		<Tbody>
		   {arr.map((row, index) => {
				const isHighlighted = index === this.state.highlightRowIndex
				return {
					<Trow 
						isHighlighted={isHighlighted}
						onMouseOver={() => this.setHighlightedRow(index)}
						onMouseOut={() => this.setHighlightedRow(null)}
						>
						...
					</Trow>
				}
		   })}  
		</Tbody>   
       </Table>
    )
  }
}

const Trow = styled.tr`
	& td {
		background-color: ${p => p.isHighlighted ? 'red' : 'white'};
	}
	
	&:hover {
		background-color: red;
	}
`;

Solution 19 - Css

There isn't, and there is.

If you must place the label before the input, just place the label after the input and keep both the label & the input inside a div, and style the div as following :

.input-box {
  display: flex;
  flex-direction: column-reverse;
}

<div class="input-box">
  <input
   id="email"
   class="form-item"           
   />

   <label for="email" class="form-item-header">                  
   E-Mail*                  
   </label>
</div>

Now you can apply the standard next sibling styling options available in css, and it will appear like you are using a previous sibling styling.

Solution 20 - Css

There is no such selector, but in the DOM API has a pretty read-only property

Node.previousSibling

Solution 21 - Css

I've found the easiest solution. It might only apply based on what you're doing.

Let's say you want to hover on "sibling_2" to change "sibling_1" in the example below:

<div class='parent'>
  <div class='sibling_1'></div>
  <div class='sibling_2'></div>
</div>

Since there's no previous element selector you can simply switch 'sibling_1' and 'sibling_2' around and apply so they look the same.

.parent {
  display: flex;
  flex-direction: row-reverse;
}

Now you can select them like that.

.sibling_1:hover ~ .sibling_2 {
  #your CSS
}

Solution 22 - Css

I had a similar problem and found out that all problem of this nature can be solved as follows:

give all your items a style.
give your selected item a style.
give next items a style using + or ~.

and this way you'll be able to style your current, previous items(all items overridden with current and next items) and your next items.

example:

/* all items (will be styled as previous) */
li {
  color: blue;
}

/* the item i want to distinguish */
li.milk {
  color: red;
}

/* next items */
li ~ li  {
  color: green;
}


<ul>
  <li>Tea</li>
  <li class="milk">Milk</li>
  <li>Juice</li>
  <li>others</li>
</ul>

Hope it helps someone.

Solution 23 - Css

here is the link for a similar question

https://stackoverflow.com/questions/63876804/css-select-all-previous-siblings-for-a-star-rating?noredirect=1#comment113074363_63876804

So I post my solution using bits of everyones responses and anyone can use it as reference and possibliy recommend improvements.

// Just to check input value
// Consts
const starRadios = document.querySelectorAll('input[name="rating"]');

// EventListeners
starRadios.forEach((radio) => radio.addEventListener('change', getStarRadioValue));

// Get star radio value
function getStarRadioValue(event) { 
    alert(event.target.value) 
    // Do something with it
};

.star-rating {
  font-size: 1.5rem;
  unicode-bidi: bidi-override;
  direction: rtl;
  text-align: left;
}
.star-rating.editable label:hover {
  cursor: pointer;
}
.star-rating.editable .icon-star:hover,
.star-rating.editable .icon-star:hover ~ .icon-star {
  background-color: #fb2727 !important;
}

.icon-star {
  position: relative;
  background-color: #72747d;
  width: 32px;
  height: 32px;
  display: inline-block;
  transition: background-color 0.3s ease;
}
.icon-star.filled {
  background-color: #fb2727;
}

.icon-star > label {
  display: inline-block;
  width: 100%;
  height: 100%;
  left: 0;
  top: 0;
  position: absolute;
}

.icon-star > label > input[type="radio"] {
  position: absolute;
  top: 0;
  left: 0;
  transform: translateY(50%) translateX(50%);
  display: none;
}

<div class="star-rating editable">
  <span class="icon-star">
    <label>
      <input type="radio" name="rating"  value="5" />
    </label>
  </span>
  <span class="icon-star">
    <label>
      <input type="radio" name="rating" value="4" />
    </label>
  </span>
  <span class="icon-star">
    <label>
      <input type="radio" name="rating" value="3" />
    </label>
  </span>
  <span class="icon-star">
    <label>
      <input type="radio" name="rating" value="2" />
    </label>
  </span>
  <span class="icon-star">
    <label>
      <input type="radio" name="rating"  value="1" />
    </label>
  </span>
</div>

Solution 24 - Css

For my use case was needed to change previous element style on focus and hover only having 2 items in parent element. to do so used :focus-within and :hover pseudo-classes.

like so selecting whenever focus/hover event occurs

.root-element:hover .element-to-style { background-color: red;} 
.root-element:focus-within .element-to-style { background-color: green;}

<div class="root-element">
<span class="element-to-style"> TextFocused</span>
<input type="text" placeholder="type To Style"/>

</div>

Solution 25 - Css

I had this same problem, while I was trying to change prepend icon fill color on input focus, my code looked something like this:

<template #append>
    <b-input-group-text><strong class="text-danger">!</strong></b-input-group-text>
</template>
<b-form-input id="password_confirmation" v-model="form.password_confirmation" type="password" placeholder="Repeat password" autocomplete="new-password" />

The problem was that I'm using a vue-bootstrap slot to inject the prepend, so even if i change the location still get rendered after the input

Well my solution was to swipe their location, and add custom prepend and used ~ symbol, as css doesn't support previous sibling.

<div class="form-input-prepend">
    <svg-vue icon="common.lock" />
</div>
<b-form-input id="password_confirmation" v-model="form.password_confirmation" type="password" placeholder="Repeat password" autocomplete="new-password" />

Scss style

.form-control:focus ~ .form-input-prepend {
    svg path {
        fill: $accent;
    }
}

So just try to change its position, and if necessary use css order or position: absolute; to achieve what you want, and to avoid using javascript for this kind of needs.

Solution 26 - Css

I fixed this problem by putting my elements in a flexbox and then using flex-direction: column-reverse.

Then I had to invert my elements in the HTML manually (put them in reverse order), and it looked normal and it worked!

<div style="display: flex; flex-direction: column-reverse">
  <a class="element2">Element 2</a>
  <a class="element1">Element 1</a>
</div>
...
<style>
  .element2:hover + element1 {
    ...
  }
</style>

Content Type	Original Author	Original Content on Stackoverflow
Question	Jourkey	View Question on Stackoverflow
Solution 1 - Css	cletus	View Answer on Stackoverflow
Solution 2 - Css	mantish	View Answer on Stackoverflow
Solution 3 - Css	Quentin	View Answer on Stackoverflow
Solution 4 - Css	Michael Benjamin	View Answer on Stackoverflow
Solution 5 - Css	Bryan Larsen	View Answer on Stackoverflow
Solution 6 - Css	Victor Gorban	View Answer on Stackoverflow
Solution 7 - Css	Rounin - Standing with Ukraine	View Answer on Stackoverflow
Solution 8 - Css	Roko C. Buljan	View Answer on Stackoverflow
Solution 9 - Css	Vadim Ovchinnikov	View Answer on Stackoverflow
Solution 10 - Css	0x1gene	View Answer on Stackoverflow
Solution 11 - Css	Carel	View Answer on Stackoverflow
Solution 12 - Css	SherylHohman	View Answer on Stackoverflow
Solution 13 - Css	kernel	View Answer on Stackoverflow
Solution 14 - Css	Megha	View Answer on Stackoverflow
Solution 15 - Css	DynamicDan	View Answer on Stackoverflow
Solution 16 - Css	Nando	View Answer on Stackoverflow
Solution 17 - Css	Andrew Leyva	View Answer on Stackoverflow
Solution 18 - Css	kyle	View Answer on Stackoverflow
Solution 19 - Css	Ron16	View Answer on Stackoverflow
Solution 20 - Css	Dandgerson	View Answer on Stackoverflow
Solution 21 - Css	Roma Kim	View Answer on Stackoverflow
Solution 22 - Css	Hejar	View Answer on Stackoverflow
Solution 23 - Css	Jackal	View Answer on Stackoverflow
Solution 24 - Css	Nerius Jok	View Answer on Stackoverflow
Solution 25 - Css	user7153178	View Answer on Stackoverflow
Solution 26 - Css	tolypash	View Answer on Stackoverflow