IntegrityError duplicate key value violates unique constraint - django/postgres

DjangoPostgresqlDuplicatesUnique ConstraintDatabase Integrity

Django Problem Overview


I'm following up in regards to a question that I asked earlier in which I sought to seek a conversion from a goofy/poorly written mysql query to postgresql. I believe I succeeded with that. Anyways, I'm using data that was manually moved from a mysql database to a postgres database. I'm using a query that looks like so:

  UPDATE krypdos_coderound cru

  set is_correct = case 
      when t.kv_values1 = t.kv_values2 then True 
      else False 
      end

  from 
  
  (select cr.id, 
    array_agg(
    case when kv1.code_round_id = cr.id 
    then kv1.option_id 
    else null end 
    ) as kv_values1,

    array_agg(
    case when kv2.code_round_id = cr_m.id 
    then kv2.option_id 
    else null end 
    ) as kv_values2

    from krypdos_coderound cr
     join krypdos_value kv1 on kv1.code_round_id = cr.id
     join krypdos_coderound cr_m 
       on cr_m.object_id=cr.object_id 
       and cr_m.content_type_id =cr.content_type_id 
     join krypdos_value kv2 on kv2.code_round_id = cr_m.id

   WHERE
     cr.is_master= False
     AND cr_m.is_master= True 
     AND cr.object_id=%s 
     AND cr.content_type_id=%s 

   GROUP BY cr.id  
  ) t

where t.id = cru.id
    """ % ( self.object_id, self.content_type.id)
  )

I have reason to believe that this works well. However, this has lead to a new issue. When trying to submit, I get an error from django that states:

IntegrityError at (some url): 
duplicate key value violates unique constraint "krypdos_value_pkey"

I've looked at several of the responses posted on here and I haven't quite found the solution to my problem (although the related questions have made for some interesting reading). I see this in my logs, which is interesting because I never explicitly call insert- django must handle it:

   STATEMENT:  INSERT INTO "krypdos_value" ("code_round_id", "variable_id", "option_id", "confidence", "freetext")
   VALUES (1105935, 11, 55, NULL, E'') 
   RETURNING "krypdos_value"."id"

However, trying to run that results in the duplicate key error. The actual error is thrown in the code below.

 # Delete current coding         CodeRound.objects.filter(object_id=o.id,content_type=object_type,is_master=True).delete()
  code_round = CodeRound(object_id=o.id,content_type=object_type,coded_by=request.user,comments=request.POST.get('_comments',None),is_master=True)
  code_round.save()
  for key in request.POST.keys():
    if key[0] != '_' or key != 'csrfmiddlewaretoken':
      options = request.POST.getlist(key)
      for option in options:
        Value(code_round=code_round,variable_id=key,option_id=option,confidence=request.POST.get('_confidence_'+key, None)).save()  #This is where it dies
  # Resave to set is_correct
  code_round.save()
  o.status = '3' 
  o.save(

I've checked the sequences and such and they seem to be in order. At this point I'm not sure what to do- I assume it's something on django's end but I'm not sure. Any feedback would be much appreciated!

Django Solutions


Solution 1 - Django

This happend to me - it turns out you need to resync your primary key fields in Postgres. The key is the SQL statement:

SELECT setval('tablename_id_seq', (SELECT MAX(id) FROM tablename)+1);

Solution 2 - Django

It appears to be a known difference of behaviour between the MySQL and SQLite (they update the next available primary key even when inserting an object with an explicit id) backends, and other backends like Postgres, Oracle, ... (they do not).

There is a ticket describing the same issue. Even though it was closed as invalid, it provides a hint that there is a Django management command to update the next available key.

To display the SQL updating all next ids for the application MyApp:

python manage.py sqlsequencereset MyApp

In order to have the statement executed, you can provide it as the input for the dbshell management command. For bash, you could type:

python manage.py sqlsequencereset MyApp | python manage.py dbshell

The advantage of the management commands is that abstracts away the underlying DB backend, so it will work even if later migrating to a different backend.

Solution 3 - Django

I had an existing table in my "inventory" app and I wanted to add new records in Django admin and I got this error:

> Duplicate key value violates unique constraint "inventory_part_pkey" > DETAIL: Key (part_id)=(1) already exists.

As mentioned before, I run the code below to get the SQL command to reset the id-s:

python manage.py sqlsequencereset inventory

Piping the python manage.py sqlsequencereset inventory | python manage.py dbshell to the shell was not working

  • So I copied the generated raw SQL command
  • Then opened pgAdmin3 https://www.pgadmin.org for postgreSQL and opened my db
  • Clicked on the 6. icon (Execute arbitrary SQL queries)
  • Copied the statement what was generated

In my case the raw SQL command was:

BEGIN;
SELECT setval(pg_get_serial_sequence('"inventory_signup"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "inventory_signup";
SELECT setval(pg_get_serial_sequence('"inventory_supplier"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "inventory_supplier";
COMMIT;

Executed it with F5.

This fixed everything.

Solution 4 - Django

In addition to zapphods answer:

In my case the indexing was indeed incorrect, since I had deleted all migrations, and the database probably 10-15 times when developing as I wasn't in the stage of migrating anything.

I was getting an IntegrityError on finished_product_template_finishedproduct_pkey

Reindex the table and restart runserver:

I was using pgadmin3 and for whichever index was incorrect and throwing duplicate key errors I navigated to the constraints and reindexed.

enter image description here

And then reindexed.

enter image description here

Solution 5 - Django

The solution is that you need to resync your primary key fields as reported by "Hacking Life" who wrote an example SQL code but, as suggested by "Ad N" is better to run the Django command sqlsequencereset to get the exact SQL code that you can copy and past or run with another command.

As a further improvement to these answers I would suggest to you and other reader to dont' copy and paste the SQL code but, more safely, to execute the SQL query generated by sqlsequencereset from within your python code in this way (using the default database):

from django.core.management.color import no_style
from django.db import connection

from myapps.models import MyModel1, MyModel2


sequence_sql = connection.ops.sequence_reset_sql(no_style(), [MyModel1, MyModel2])
with connection.cursor() as cursor:
    for sql in sequence_sql:
        cursor.execute(sql)

I tested this code with Python3.6, Django 2.0 and PostgreSQL 10.

Solution 6 - Django

If you want to reset the PK on all of your tables, like me, you can use the PostgreSQL recommended way:

SELECT 'SELECT SETVAL(' ||
       quote_literal(quote_ident(PGT.schemaname) || '.' || quote_ident(S.relname)) ||
       ', COALESCE(MAX(' ||quote_ident(C.attname)|| '), 1) ) FROM ' ||
       quote_ident(PGT.schemaname)|| '.'||quote_ident(T.relname)|| ';'
FROM pg_class AS S,
     pg_depend AS D,
     pg_class AS T,
     pg_attribute AS C,
     pg_tables AS PGT
WHERE S.relkind = 'S'
    AND S.oid = D.objid
    AND D.refobjid = T.oid
    AND D.refobjid = C.attrelid
    AND D.refobjsubid = C.attnum
    AND T.relname = PGT.tablename
ORDER BY S.relname;

After running this query, you will need to execute the results of the query. I typically copy and paste into Notepad. Then I find and replace "SELECT with SELECT and ;" with ;. I copy and paste into pgAdmin III and run the query. It resets all of the tables in the database. More "professional" instructions are provided at the link above.

Solution 7 - Django

If you have manually copied the databases, you may be running into the http://www.vlent.nl/weblog/2011/05/06/integrityerror-duplicate-key-value-violates-unique-constraint/">issue described here.

Solution 8 - Django

I encountered this error because I was passing extra arguments to the save method in the wrong way.

For anybody who encounters this, try forcing UPDATE with:

instance_name.save(..., force_update=True)

If you get an error that you cannot pass force_insert and force_update at the same time, you're probably passing some custom arguments the wrong way, like I did.

Solution 9 - Django

I was getting the same error as the OP.

I had created some Django models, created a Postgres table based on the models, and added some rows to the Postgres table via Django Admin. Then I fiddled with some of the columns in the models (changing around ForeignKeys, etc.) but had forgotten to migrate the changes.

Running the migration commands solved my problem, which makes sense given the SQL answers above.

To see what changes would be applied, without actually applying them:
python manage.py makemigrations --dry-run --verbosity 3

If you're happy with those changes, then run:
python manage.py makemigrations

Then run:
python manage.py migrate

Solution 10 - Django

I was getting a similar issue and nothing seemed to be working. If you need the data (ie cant exclude it when doing dump) make sure you have turned off (commented) any post_save receivers. I think the data would be imported but it would create the same model again because of these. Worked for me.

Solution 11 - Django

You just have to go to pgAdmin III and there execute your script with the name of the table:

SELECT setval('tablename_id_seq', (SELECT MAX(id) FROM tablename)+1);

Solution 12 - Django

Based on Paolo Melchiorre's answer, I wrote a chunk as a function to be called before any .save()

from django.db import connection
def setSqlCursor(db_table):
    sql = """SELECT pg_catalog.setval(pg_get_serial_sequence('"""+db_table+"""', 'id'), MAX(id)) FROM """+db_table+""";"""
    with connection.cursor() as cursor:
        cursor.execute(sql)

Solution 13 - Django

This is the right statement. Mostly, It happens when we insert rows with id field.

SELECT setval('tablename_id_seq', (SELECT MAX(id) FROM tablename));

Solution 14 - Django

This question was asked about 9 years ago, and lots of people gave their own ways to solve it.

For me, I put unique=True in my email custom model field, but while creating superuser I didn't ask for the email to be mandatory.

Now after creating a superuser my email field is just saved as blank or Null. Now this is how I created and saved new user

obj = mymodel.objects.create_user(username='abc', password='abc')
obj.email = '[email protected]'
obj.save()

It just threw the error saying duplicate-key-value-violates in the first line because the email was set to empty by default which was the same with the admin user. Django spotted a duplicate !!!

Solution
  • Option1: Make email mandatory while creating any user (for superuser as well)
  • Option2: Remove unique=True and run migrations
  • Option3: If you don't know where are the duplicates, you either drop the column or you can clear the database using python manage.py flush

It is highly recommended to know the reason why the error occurred in your case.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionthe_man_slimView Question on Stackoverflow
Solution 1 - DjangoHacking LifeView Answer on Stackoverflow
Solution 2 - DjangoAd NView Answer on Stackoverflow
Solution 3 - DjangojturiView Answer on Stackoverflow
Solution 4 - DjangojmunschView Answer on Stackoverflow
Solution 5 - DjangoPaolo MelchiorreView Answer on Stackoverflow
Solution 6 - DjangoBobortView Answer on Stackoverflow
Solution 7 - DjangozaphodView Answer on Stackoverflow
Solution 8 - DjangoJacobFView Answer on Stackoverflow
Solution 9 - DjangoallardbrainView Answer on Stackoverflow
Solution 10 - DjangoJoshView Answer on Stackoverflow
Solution 11 - DjangoLuis RealesView Answer on Stackoverflow
Solution 12 - DjangoRaphael FernandesView Answer on Stackoverflow
Solution 13 - DjangoPraveen KumarView Answer on Stackoverflow
Solution 14 - DjangoAditya RajgorView Answer on Stackoverflow