"Instantiating" a List in Java?

JavaList

Java Problem Overview


Trying to use the following code:

List<Integer> list = new List<Integer>();

I get the following error message:

> java.util.List is abstract; cannot be instantiated

What does this mean and why can't I initialize a List the same way I would an ArrayList?

Java Solutions


Solution 1 - Java

In Java, List is an interface. That is, it cannot be instantiated directly.

Instead you can use ArrayList which is an implementation of that interface that uses an array as its backing store (hence the name).

Since ArrayList is a kind of List, you can easily upcast it:

List<T> mylist = new ArrayList<T>();

This is in contrast with .NET, where, since version 2.0, List<T> is the default implementation of the IList<T> interface.

Solution 2 - Java

List is an interface, not a concrete class.
An interface is just a set of functions that a class can implement; it doesn't make any sense to instantiate an interface.

ArrayList is a concrete class that happens to implement this interface and all of the methods in it.

Solution 3 - Java

Use List<Integer> list = new ArrayList<Integer>();

Solution 4 - Java

List is the interface, not a class so it can't be instantiated. ArrayList is most likely what you're after:

ArrayList<Integer> list = new ArrayList<Integer>();

An interface in Java essentially defines a blueprint for the class - a class implementing an interface has to provide implementations of the methods the list defines. But the actual implementation is completely up to the implementing class, ArrayList in this case.

The JDK also provides LinkedList - an alternative implementation that again conforms to the list interface. It works very differently to the ArrayList underneath and as such it tends to be more efficient at adding / removing items half way through the list, but for the vast majority of use cases it's less efficient. And of course if you wanted to define your own implementation it's perfectly possible!

In short, you can't create a list because it's an interface containing no concrete code - that's the job of the classes that implement that list, of which ArrayList is the most used by far (and with good reason!)

It's also worth noting that in C# a List is a class, not an interface - that's IList. The same principle applies though, just with different names.

Solution 5 - Java

A List isn't a real thing in Java. It's an interface, a way of defining how an object is allowed to interact with other objects. As such, it can't ever be instantiated. An ArrayList is an implementation of the List interface, as is a linked list, and so on. Use those instead.

Solution 6 - Java

A List in java is an interface that defines certain qualities a "list" must have. Specific list implementations, such as ArrayList implement this interface and flesh out how the various methods are to work. What are you trying to accomplish with this list? Most likely, one of the built-in lists will work for you.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionhello253View Question on Stackoverflow
Solution 1 - JavaEtienne de MartelView Answer on Stackoverflow
Solution 2 - JavaSLaksView Answer on Stackoverflow
Solution 3 - JavaEng.FouadView Answer on Stackoverflow
Solution 4 - JavaMichael BerryView Answer on Stackoverflow
Solution 5 - JavaOwenView Answer on Stackoverflow
Solution 6 - JavaChristopher ArmstrongView Answer on Stackoverflow