Use `insert`:

    In [1]: ls = [1,2,3]

    In [2]: ls.insert(0, &quot;new&quot;)

    In [3]: ls
    Out[3]: [&#39;new&#39;, 1, 2, 3]


From the documentation: 

&gt; list.insert(i, x)&lt;br&gt;
&gt; Insert an item at a given position. The first
&gt; argument is the index of the element before which to insert, so
&gt; `a.insert(0, x)` inserts at the front of the list, and `a.insert(len(a),x)` is
&gt; equivalent to `a.append(x)`


http://docs.python.org/2/tutorial/datastructures.html#more-on-lists

Say, for example, you are building a project on Backbone or whatever and you need to load scripts in a certain order, e.g. `underscore.js` needs to be loaded before `backbone.js`.

How do I get it to concat the scripts so that they’re in order? 

	// JS concat, strip debugging and minify
	gulp.task(&#39;scripts&#39;, function() {
		gulp.src([&#39;./source/js/*.js&#39;, &#39;./source/js/**/*.js&#39;])
		.pipe(concat(&#39;script.js&#39;))
		.pipe(stripDebug())
		.pipe(uglify())
		.pipe(gulp.dest(&#39;./build/js/&#39;));
	});

I have the right order of scripts in my `source/index.html`, but since files are organized by alphabetic order, gulp will concat `underscore.js` after `backbone.js`, and the order of the scripts in my `source/index.html` does not matter, it looks at the files in the directory.

So does anyone have an idea on this?

Best idea I have is to rename the vendor scripts with `1`, `2`, `3` to give them the proper order, but I am not sure if I like this.

As I learned more I found Browserify is a great solution, it can be a pain at first but it’s great.

Concat scripts in order with Gulp

I want to display, above any other views, even the navigation bar, a kind of &quot;pop-up&quot; view that looks like this:

- full screen black background with a 0.5 alpha to see the other `UIViewController` underneath.
- a `UIView` window in the middle with some information, (a calendar if you want to know everything).

To do that, I&#39;ve created a UIViewController that contains the two `UIViews` (background and window), and I&#39;m trying to display it. I&#39;ve tried a simple `[mySuperVC addSubview:myPopUpVC.view]`, but I still have the navigation bar above.

I&#39;ve tried to present it as a modal, but the `UIViewController` underneath disappears, and I lose my transparency effect.

Any idea to do this, I&#39;m sure it&#39;s quite simple... 

Thanks!  

Add a UIView above all, even the navigation bar

How can I insert an element at the first index of a list?
If I use `list.insert(0, elem)`, does `elem` modify the content of the first index?
Or do I have to create a new list with the first elem and then copy the old list inside this new one? 


Insert at first position of a list in Python

<p>How can I insert an element at the first index of a list?
If I use <code>list.insert(0, elem)</code>, does <code>elem</code> modify the content of the first index?
Or do I have to create a new list with the first elem and then copy the old list inside this new one?</p>


Suppose `o` is a Python object, and I want all of the fields of `o`, without any methods or `__stuff__`. How can this be done?

I&#39;ve tried things like:

    [f for f in dir(o) if not callable(f)]

    [f for f in dir(o) if not inspect.ismethod(f)]

but these return the same as `dir(o)`, presumably because `dir` gives a list of strings. Also, things like `__class__` would be returned here, even if I get this to work.

How to list all fields of a class (and no methods)?

I am looking for the way to call shell scripts from python and write their stdout and stderr to file using logging. Here is my code:

&lt;!-- language: python --&gt;

    import logging
    import tempfile
    import shlex
    import os
    
    def run_shell_command(command_line):
        command_line_args = shlex.split(command_line)
     
        logging.info(&#39;Subprocess: \&quot;&#39; + command_line + &#39;\&quot;&#39;)
     
        process_succeeded = True
        try:
            process_output_filename = tempfile.mktemp(suffix = &#39;subprocess_tmp_file_&#39;)
            process_output = open(process_output_filename, &#39;w&#39;)
     
            command_line_process = subprocess.Popen(command_line_args,\
                                                    stdout = process_output,\
                                                    stderr = process_output)
            command_line_process.wait()
            process_output.close()
     
            process_output = open(process_output_filename, &#39;r&#39;)
            log_subprocess_output(process_output)
            process_output.close()
     
            os.remove(process_output_filename)
        except:
            exception = sys.exc_info()[1]
            logging.info(&#39;Exception occured: &#39; + str(exception))
            process_succeeded = False
     
        if process_succeeded:
            logging.info(&#39;Subprocess finished&#39;)
        else:
            logging.info(&#39;Subprocess failed&#39;)
     
        return process_succeeded

And I am sure that there is the way to do it without creating temporary file to store process output. Any ideas?

Run subprocess and print output to logging

I have the following shell script for a very simple HTTP server:

    #!/bin/sh
    
    echo &quot;Serving at http://localhost:3000&quot;
    python -m SimpleHTTPServer 3000

I was wondering how I can enable or add [a CORS header](https://en.wikipedia.org/wiki/Cross-origin_resource_sharing) like `Access-Control-Allow-Origin: *` to this server?

Enable access control on simple HTTP server

I have a program which creates a window where a message is displayed according to a check box.

How can I make the window size constant when the message is displayed and the message is not displayed?
        
    from Tkinter import *
    
    class App:
        def __init__(self,master):
            self.var = IntVar()
            frame = Frame(master)
            frame.grid()
            f2 = Frame(master,width=200,height=100)
            f2.grid(row=0,column=1)
            button = Checkbutton(frame,text=&#39;show&#39;,variable=self.var,command=self.fx)
            button.grid(row=0,column=0)
            msg2=&quot;&quot;&quot;I feel bound to give them full satisfaction on this point&quot;&quot;&quot;
            self.v= Message(f2,text=msg2)
        def fx(self):
            if self.var.get():
                self.v.grid(column=1,row=0,sticky=N)
            else:
                self.v.grid_remove()
    
    top = Tk()
    app = App(top)            
    top.mainloop()



How can I prevent a window from being resized with tkinter?

I&#39;m debugging my Python scripts using *pdb* and the manual says I can use **p variables** command to print the values of the specified variables at a certain point. But what if I had lots of variables, like 20 variables, and I would like to track the value of all of them? How do I print all of them without specifying each one manually? Take for example this script:

    a = 1
    b = 2
    c = 3

I can debug it with pdb and print all of them using **p a, b, c** like this:

    $ python -m pdb test.py 
    &gt; /media/test.py(1)&lt;module&gt;()
    -&gt; a = 1
    (Pdb) n
    &gt; /media/test.py(2)&lt;module&gt;()
    -&gt; b = 2
    (Pdb) n
    &gt; /media/test.py(3)&lt;module&gt;()
    (Pdb) n
    --Return--
    &gt; /media/test.py(3)&lt;module&gt;()-&gt;None
    -&gt; c = 3
    (Pdb) p a, b, c
    (1, 2, 3)
    (Pdb) 

But I have to manually specify each variable. Is there a way of print all variables at once, without specifying each one of them?

How to print all variables values when debugging Python with pdb, without specifying each variable?

Suppose I have function with list parameter, and inside its body I want to modify passed list, by copying elements of an array to the list:&lt;br&gt;

    def function1 (list_arg):
       a = function2()    #function2 returns an array of numbers
       list_arg = list(a)
    
    list1 = [0] * 5
    function1(list1)
    list1
    [0,0,0,0,0]

When doing it like this, it doesn&#39;t work. After executing `function1(list1)`, `list1` remains unchanged. So, how to make `function1` return `list1` with the same elements (numbers) as array `a`?  

python; modifying list inside a function

I have a pandas data frame `df` like:

    a b
    A 1
    A 2
    B 5
    B 5
    B 4
    C 6

I want to **group by the first column and get second column as lists in rows**:

    A [1,2]
    B [5,5,4]
    C [6]

Is it possible to do something like this using pandas groupby?

How to group dataframe rows into list in pandas groupby

I&#39;m trying to learn R and I can&#39;t figure out how to append to a list.

If this were Python I would . . .
 
    #Python
    vector = []
    values = [&#39;a&#39;,&#39;b&#39;,&#39;c&#39;,&#39;d&#39;,&#39;e&#39;,&#39;f&#39;,&#39;g&#39;]
    
    for i in range(0,len(values)):
        vector.append(values[i])

How do you do this in R?

    #R Programming
    &gt; vector = c()
    &gt; values = c(&#39;a&#39;,&#39;b&#39;,&#39;c&#39;,&#39;d&#39;,&#39;e&#39;,&#39;f&#39;,&#39;g&#39;)
    &gt; for (i in 1:length(values))
    + #append value[i] to empty vector



Append value to empty vector in R?

I have a dataframe `df` imported from an Excel document like this:

	cluster	load_date	budget	actual	fixed_price
	A	1/1/2014	1000	4000	Y
	A	2/1/2014	12000	10000	Y
	A	3/1/2014	36000	2000	Y
	B	4/1/2014	15000	10000	N
	B	4/1/2014	12000	11500	N
	B	4/1/2014	90000	11000	N
	C	7/1/2014	22000	18000	N
	C	8/1/2014	30000	28960	N
	C	9/1/2014	53000	51200	N

I want to be able to return the contents of column 1 `df[&#39;cluster&#39;]` as a list, so I can run a for-loop over it, and create an Excel worksheet for every cluster.

Is it also possible to return the contents of a whole column or row to a list? e.g.

    list = [], list[column1] or list[df.ix(row1)]

Get list from pandas dataframe column or row?

I have a Python list, say `a = [0,1,2,3,4,5,6]`. I also have a list of indices, say `b = [0,2,4,5]`. How can I get the list of elements of `a` with indices in `b`?

Getting a sublist of a Python list, with the given indices?

I have a dataframe:

    s1 = pd.Series([5, 6, 7])
    s2 = pd.Series([7, 8, 9])
    
    df = pd.DataFrame([list(s1), list(s2)],  columns =  [&quot;A&quot;, &quot;B&quot;, &quot;C&quot;])

       A  B  C
    0  5  6  7
    1  7  8  9
    
    [2 rows x 3 columns]

and I need to add a first row [2, 3, 4] to get:

       A  B  C
    0  2  3  4
    1  5  6  7
    2  7  8  9

I&#39;ve tried `append()` and `concat()` functions but can&#39;t find the right way how to do that.

How to add/insert series to dataframe?

Insert a row to pandas dataframe

I am new to this SQL; I have seen similar question with much bigger programs, which I can&#39;t understand at the moment. I am making a database for games of cards to use in my homepage. 

I am using MySQL Workbench on Windows. The error I get is:

&gt; Error Code: 1364. Field &#39;id&#39; doesn&#39;t have a default value

    CREATE TABLE card_games
    (
    nafnleiks varchar(50), 
    leiklysing varchar(3000), 
    prentadi varchar(1500), 
    notkunarheimildir varchar(1000), 
    upplysingar varchar(1000), 
    ymislegt varchar(500), 
    id int(11) PK
    );

    insert into card_games (nafnleiks, leiklysing, prentadi, notkunarheimildir, upplysingar, ymislegt)
    
    values(&#39;Svartip&#233;tur&#39;,
    &#39;Leikl&#253;singu vantar&#39;,
    &#39;Er prenta&#240; &#237;: &#222;&#243;rarinn Gu&#240;mundsson (2010). Spilab&#243;kin - Allir helstu spilaleikir og spil.&#39;,
    &#39;Heimildir um notkun: &#193;rni Sigur&#240;sson (1951). H&#225;t&#237;&#240;ir og skemmtanir fyrir hundra&#240; &#225;rum&#39;,
    &#39;A&#240;rar uppl&#253;singar&#39;,
    &#39;ekkert h&#233;r sem stendur&#39;
    );
    
    values(&#39;Handkurra&#39;,
    &#39;Leikl&#253;singu vantar&#39;,
    &#39;Er prenta&#240; &#237;: &#222;&#243;rarinn Gu&#240;mundsson (2010). Spilab&#243;kin - Allir helstu spilaleikir og spil.&#39;,
    &#39;Heimildir um notkun&#39;, 
    &#39;A&#240;rar uppl&#253;singar&#39;,
    &#39;ekkert her sem stendur&#39;
    );
    
    values(&#39;Vei&#240;ima&#240;ur&#39;,
    &#39;Leikl&#253;singu vantar&#39;,
    &#39;&#222;&#243;rarinn Gu&#240;mundsson (2010). Spilab&#243;kin - Allir helstu spilaleikir og spil. Reykjav&#237;k: B&#243;kaf&#233;lagi&#240;. Bls. 19-20.&#39;,
    &#39;vantar&#39;,
    &#39;vantar&#39;,
    &#39;vantar&#39;
    );

Field &#39;id&#39; doesn&#39;t have a default value?

What is the difference between `std::unordered_map::emplace` and `std::unordered_map::insert` in C++?

What is the difference between unordered_map::emplace and unordered_map::insert in C++?

I have a list &#39;abc&#39; and a dataframe &#39;df&#39;:

    abc = [&#39;foo&#39;, &#39;bar&#39;]
    df =
        A  B
    0  12  NaN
    1  23  NaN

I want to insert the list into cell 1B, so I want this result:

        A  B
    0  12  NaN
    1  23  [&#39;foo&#39;, &#39;bar&#39;]

Ho can I do that?

1) If I use this:

    df.ix[1,&#39;B&#39;] = abc

I get the following error message:

    ValueError: Must have equal len keys and value when setting with an iterable

because it tries to insert the list (that has two elements) into a row / column but not into a cell.

2) If I use this:

    df.ix[1,&#39;B&#39;] = [abc]

then it inserts a list that has only one element that is the &#39;abc&#39; list ( `[[&#39;foo&#39;, &#39;bar&#39;]]` ).

3) If I use this:

    df.ix[1,&#39;B&#39;] = &#39;, &#39;.join(abc)

then it inserts a string: ( `foo, bar` ) but not a list.

4) If I use this:

    df.ix[1,&#39;B&#39;] = [&#39;, &#39;.join(abc)]

then it inserts a list but it has only one element ( `[&#39;foo, bar&#39;]` ) but not two as I want ( `[&#39;foo&#39;, &#39;bar&#39;]` ).

Thanks for help!

------------
EDIT
------------
My new dataframe and the old list:

    abc = [&#39;foo&#39;, &#39;bar&#39;]
    df2 =
        A    B         C
    0  12  NaN      &#39;bla&#39;
    1  23  NaN  &#39;bla bla&#39;

Another dataframe:

    df3 =
        A    B         C                    D
    0  12  NaN      &#39;bla&#39;  [&#39;item1&#39;, &#39;item2&#39;]
    1  23  NaN  &#39;bla bla&#39;        [11, 12, 13]

I want insert the &#39;abc&#39; list into `df2.loc[1,&#39;B&#39;]` and/or `df3.loc[1,&#39;B&#39;]`.

If the dataframe has columns only with integer values and/or NaN values and/or list values then inserting a list into a cell works perfectly. If the dataframe has columns only with string values and/or NaN values and/or list values then inserting a list into a cell works perfectly. But if the dataframe has columns with integer and string values and other columns then the error message appears if I use this: `df2.loc[1,&#39;B&#39;] = abc` or `df3.loc[1,&#39;B&#39;] = abc`.

Another dataframe:

    df4 =
              A     B
    0      &#39;bla&#39;  NaN
    1  &#39;bla bla&#39;  NaN

These inserts work perfectly: `df.loc[1,&#39;B&#39;] = abc` or `df4.loc[1,&#39;B&#39;] = abc`.


Python pandas insert list into a cell

I have a string like this in Swift:

    var stringts:String = &quot;3022513240&quot;

If I want to change it to string to something like this: `&quot;(302)-251-3240&quot;`, I want to add the partheses at index 0, how do I do it?

In Objective-C, it is done this way:

     NSMutableString *stringts = &quot;3022513240&quot;;
     [stringts insertString:@&quot;(&quot; atIndex:0];

How to do it in Swift?

Content Type	Original Author	Original Content on Stackoverflow
Question	Fr0z3n7	View Question on Stackoverflow
Solution 1 - Python	michel-slm	View Answer on Stackoverflow
Solution 2 - Python	Anov	View Answer on Stackoverflow

Insert at first position of a list in Python

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

Add a UIView above all, even the navigation bar

Concat scripts in order with Gulp

Attributions