indexOf method in an object array?
JavascriptJavascript Problem Overview
What's the best method to get the index of an array which contains objects?
Imagine this scenario:
var hello = {
hello: 'world',
foo: 'bar'
};
var qaz = {
hello: 'stevie',
foo: 'baz'
}
var myArray = [];
myArray.push(hello,qaz);
Now I would like to have the indexOf the object which hello property is 'stevie' which, in this example, would be 1.
I'm pretty newbie with JavaScript and I don't know if there is a simple method or if I should build my own function to do that.
Javascript Solutions
Solution 1 - Javascript
I think you can solve it in one line using the map function:
pos = myArray.map(function(e) { return e.hello; }).indexOf('stevie');
Solution 2 - Javascript
Array.prototype.findIndex is supported in all browsers other than IE (non-edge). But the polyfill provided is nice.
var indexOfStevie = myArray.findIndex(i => i.hello === "stevie");
The solution with map is okay. But you are iterating over the entire array every search. That is only the worst case for findIndex which stops iterating once a match is found.
var searchTerm = "stevie",
index = -1;
for(var i = 0, len = myArray.length; i < len; i++) {
if (myArray[i].hello === searchTerm) {
index = i;
break;
}
}
or as a function:
function arrayObjectIndexOf(myArray, searchTerm, property) {
for(var i = 0, len = myArray.length; i < len; i++) {
if (myArray[i][property] === searchTerm) return i;
}
return -1;
}
arrayObjectIndexOf(arr, "stevie", "hello"); // 1
Just some notes:
- Don't use for...in loops on arrays
- Be sure to break out of the loop or return out of the function once you've found your "needle"
- Be careful with object equality
For example,
var a = {obj: 0};
var b = [a];
b.indexOf({obj: 0}); // -1 not found
Solution 3 - Javascript
In ES2015, this is pretty easy:
myArray.map(x => x.hello).indexOf('stevie')
or, probably with better performance for larger arrays:
myArray.findIndex(x => x.hello === 'stevie')
Solution 4 - Javascript
var idx = myArray.reduce( function( cur, val, index ){
if( val.hello === "stevie" && cur === -1 ) {
return index;
}
return cur;
}, -1 );
Solution 5 - Javascript
I like Pablo's answer, but Array#indexOf and Array#map don't work on all browsers. Underscore will use native code if it's available, but has fallbacks as well. Plus it has the pluck method for doing exactly what Pablo's anonymous map method does.
var idx = _.chain(myArray).pluck("hello").indexOf("Stevie").value();
Solution 6 - Javascript
Or prototype it :
Array.prototype.indexOfObject = function arrayObjectIndexOf(property, value) {
for (var i = 0, len = this.length; i < len; i++) {
if (this[i][property] === value) return i;
}
return -1;
}
myArr.indexOfObject("name", "stevie");
Solution 7 - Javascript
#Brief
myArray.indexOf('stevie','hello')
#Use Cases :
/*****NORMAL****/
[2,4,5].indexOf(4) ;//OUTPUT 1
/****COMPLEX*****/
[{slm:2},{slm:4},{slm:5}].indexOf(4,'slm');//OUTPUT 1
//OR
[{slm:2},{slm:4},{slm:5}].indexOf(4,function(e,i){
return e.slm;
});//OUTPUT 1
/***MORE Complex**/
[{slm:{salat:2}},{slm:{salat:4}},{slm:{salat:5}}].indexOf(4,function(e,i){
return e.slm.salat;
});//OUTPUT 1
#API :
Array.prototype.indexOfOld=Array.prototype.indexOf
Array.prototype.indexOf=function(e,fn){
if(!fn){return this.indexOfOld(e)}
else{
if(typeof fn ==='string'){var att=fn;fn=function(e){return e[att];}}
return this.map(fn).indexOfOld(e);
}
};
Solution 8 - Javascript
I compared several methods and received a result with the fastest way to solve this problem. It's a for loop. It's 5+ times faster than any other method.
Here is the test's page: https://jsbench.me/9hjewv6a98
Solution 9 - Javascript
While, most other answers here are valid. Sometimes, it's best to just make a short simple function near where you will use it.
// indexOf wrapper for the list of objects
function indexOfbyKey(obj_list, key, value) {
for (index in obj_list) {
if (obj_list[index][key] === value) return index;
}
return -1;
}
// Find the string in the list (default -1)
var test1 = indexOfbyKey(object_list, 'name', 'Stevie');
var test2 = indexOfbyKey(object_list, 'last_name', 'some other name');
It depends on what is important to you. It might save lines of code and be very clever to use a one-liner, or to put a generic solution somewhere that covers various edge cases. But sometimes it's better to just say: "here I did it like this" rather than leave future developers to have extra reverse engineering work. Especially if you consider yourself "a newbie" like in your question.
Solution 10 - Javascript
If your object is the same object of the ones you are using within the array, you should be able to get the index of the Object in the same way you do as if it was a string.
var hello = {
hello: 'world',
foo: 'bar'
};
var qaz = {
hello: 'stevie',
foo: 'baz'
}
var qazCLONE = { // new object instance and same structure
hello: 'stevie',
foo: 'baz'
}
var myArray = [hello,qaz];
myArray.indexOf(qaz) // should return 1
myArray.indexOf(qazCLONE) // should return -1
Solution 11 - Javascript
I did some performance testing of various answers here, which anyone can run them self:
https://jsperf.com/find-index-of-object-in-array-by-contents
Based on my initial tests in Chrome, the following method (using a for loop set up inside a prototype) is the fastest:
Array.prototype.indexOfObject = function (property, value) {
for (var i = 0, len = this.length; i < len; i++) {
if (this[i][property] === value) return i;
}
return -1;
}
myArray.indexOfObject("hello", "stevie");
This code is a slightly modified version of Nathan Zaetta's answer.
In the performance benchmarks I tried it with both the target being in the middle (index 500) and very end (index 999) of a 1000 object array, and even if I put the target in as the very last item in the array (meaning that it it has to loop through every single item in the array before it's found) it still ends up the fastest.
This solution also has the benefit of being one of the most terse for repeatedly executing, since only the last line needs to be repeated:
myArray.indexOfObject("hello", "stevie");
Solution 12 - Javascript
array.filter(function(item, indx, arr){ return(item.hello === 'stevie'); })[0];
Mind the [0].
It is proper to use reduce as in Antonio Laguna's answer.
Apologies for the brevity...
Solution 13 - Javascript
Try this:
console.log(Object.keys({foo:"_0_", bar:"_1_"}).indexOf("bar"));
https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Object/keys
Solution 14 - Javascript
simple:
myArray.indexOf(myArray.filter(function(item) {
return item.hello == "stevie"
})[0])
Solution 15 - Javascript
you can use findIndex() method:
cosnt myIndex=myArray.findIndex(el=>el.hello==='stevie')
if myIndex < 0 that means is not exist
Solution 16 - Javascript
You can use a native and convenient function Array.prototype.findIndex() basically:
> The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.
Just a note it is not supported on Internet Explorer, Opera and Safari, but you can use a Polyfill provided in the link below.
More information:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex
var hello = {
hello: 'world',
foo: 'bar'
};
var qaz = {
hello: 'stevie',
foo: 'baz'
}
var myArray = [];
myArray.push(hello, qaz);
var index = myArray.findIndex(function(element, index, array) {
if (element.hello === 'stevie') {
return true;
}
});
alert('stevie is at index: ' + index);
Solution 17 - Javascript
If you are only interested into finding the position see @Pablo's answer.
pos = myArray.map(function(e) { return e.hello; }).indexOf('stevie');
However, if you are looking forward to finding the element (i.e. if you were thinking of doing something like this myArray[pos]), there is a more efficient one-line way to do it, using filter.
element = myArray.filter((e) => e.hello === 'stevie')[0];
See perfomance results (~ +42% ops/sec): http://jsbench.github.io/#7fa01f89a5dc5cc3bee79abfde80cdb3
Solution 18 - Javascript
See this example: http://jsfiddle.net/89C54/
for (i = 0; i < myArray.length; i++) {
if (myArray[i].hello === 'stevie') {
alert('position: ' + i);
return;
}
}
It starts to count with zero.
Solution 19 - Javascript
I have made a generic function to check the below is the code & works for any object
function indexOfExt(list, item) {
var len = list.length;
for (var i = 0; i < len; i++) {
var keys = Object.keys(list[i]);
var flg = true;
for (var j = 0; j < keys.length; j++) {
var value = list[i][keys[j]];
if (item[keys[j]] !== value) {
flg = false;
}
}
if (flg == true) {
return i;
}
}
return -1;
}
var items = [{ "hello": 'world', "foo": 'bar' }];
var selectedItem = { "hello": 'world', "foo": 'bar' };
alert(items.indexOf(selectedItem));
alert(indexOfExt(items, selectedItem));
The first alert will return -1 (means match not found) & second alert will return 0 (means match found).
Solution 20 - Javascript
Use _.findIndex from underscore.js library
Here's the example
_.findIndex([{a:1},{a: 2,c:10},{a: 3}], {a:2,c:10}) //1
Solution 21 - Javascript
Using the ES6 findIndex method, without lodash or any other libraries, you can write:
function deepIndexOf(arr, obj) {
return arr.findIndex(function (cur) {
return Object.keys(obj).every(function (key) {
return obj[key] === cur[key];
});
});
}
This will compare the immediate properties of the object, but not recurse into the properties.
If your implementation doesn't provide findIndex yet (most don't), you can add a light polyfill that supports this search:
function deepIndexOf(arr, obj) {
function findIndex = Array.prototype.findIndex || function (pred) {
for (let i = 0; i < this.length; ++i) {
if (pred.call(this, this[i], i)) {
return i;
}
}
return -1;
}
return findIndex.call(arr, function (cur) {
return Object.keys(obj).every(function (key) {
return obj[key] === cur[key];
});
});
}
(from my answer on this dupe)
Solution 22 - Javascript
Furthor of @Monika Garg answer, you can use findIndex() (There is a polyfill for unsupprted browsers).
I saw that people downvoted this answer, and I hope that they did this because of the wrong syntax, because on my opinion, this is the most elegant way.
> The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.
For example:
var hello = {
hello: 'world',
foo: 'bar'
};
var qaz = {
hello: 'stevie',
foo: 'baz'
}
var myArray = [];
myArray.push(hello,qaz);
var index = myArray.findIndex(function(element) {
return element.hello == 'stevie';
});
alert(index);
Solution 23 - Javascript
This is the way to find the object's index in array
var myArray = [{ hello: 'world',
foo: 'bar'
},{
hello: 'stevie',
foo: 'baz'
}];
for (i = 0; i < myArray.length; i++) {
if (myArray[i].hello === 'stevie') {
alert('position: ' + i);
return;
}
}
Solution 24 - Javascript
This works without custom code
var arr, a, found;
arr = [{x: 1, y: 2}];
a = {x: 1, y: 2};
found = JSON.stringify(arr).indexOf(JSON.stringify(a)) > - 1;
// found === true
>Note: this does not give the actual index, it only tells if your object exists in the current data structure
Solution 25 - Javascript
You can simply use
const someId = 2;
const array = [{id:1}, {id:2}, {id:3}];
const index = array.reduce((i, item, index) => item.id === someId ? index : i, -1);
alert('someId ' + someId + ' is at index ' + index);
No underscore, no for, just a reduce.
Solution 26 - Javascript
var hello = {hello: "world", foo: "bar"};
var qaz = {hello: "stevie", foo: "baz"};
var myArray = [];
myArray.push(hello,qaz);
function indexOfObject( arr, key, value ) {
var j = -1;
var result = arr.some(function(obj, i) {
j++;
return obj[key] == value;
})
if (!result) {
return -1;
} else {
return j;
};
}
alert(indexOfObject(myArray,"hello","world"));
Solution 27 - Javascript
Most answers response here do not resolve all cases. I found this solution better:
const isInarray = myArr.filter((obj) => obj.hello === 'stevie' && obj.foo === 'baz').length > 0;
if (!isInArray) {
....
}
Solution 28 - Javascript
You can create your own prototype to do this:
something like:
Array.prototype.indexOfObject = function (object) {
for (var i = 0; i < this.length; i++) {
if (JSON.stringify(this[i]) === JSON.stringify(object))
return i;
}
}
Solution 29 - Javascript
I will prefer to use findIndex() method:
var index = myArray.findIndex('hello','stevie');
index will give you the index number.