Include SwiftUI views in existing UIKit application

SwiftSwiftui

Swift Problem Overview


Is is possible to build views with SwiftUI side by side with an existing UIKit application?

I have an existing application written in Objective-C. I've begun migrating to Swift 5. I'm wondering if I can use SwiftUI alongside my existing UIKit .xib views.

That is to say I want some views built with SwiftUI and some other views built with UIKit in the same app. Not mixing the two of course.

SomeObjCSwiftProject/
    SwiftUIViewController.swift
    SwiftUIView.xib
    UIKitViewController.swift
    UIKitView.xib

Working alongside each other

Swift Solutions


Solution 1 - Swift

edit 05/06/19: Added information about UIHostingController as suggested by @Departamento B in his answer. Credits go to him!


Using SwiftUI within UIKit

One can use SwiftUI components in existing UIKit environments by wrapping a SwiftUI View into a UIHostingController like this:

let swiftUIView = SomeSwiftUIView() // swiftUIView is View
let viewCtrl = UIHostingController(rootView: swiftUIView)

It's also possible to override UIHostingController and customize it to one's needs, e. g. by setting the preferredStatusBarStyle manually if it doesn't work via SwiftUI as expected.

UIHostingController is documented here.


Using UIKit within SwiftUI

If an existing UIKit view should be used in a SwiftUI environment, the UIViewRepresentable protocol is there to help! It is documented here and can be seen in action in this official Apple tutorial.


Compatibility

Please note that you cannot use SwiftUI on iOS versions < iOS 13, as SwiftUI is only available on iOS 13 and above. See this post for more information.

If you want to use SwiftUI in a project with a target below iOS 13, you need to tag your SwiftUI structs with @available(iOS 13.0.0, *) attribute.

Solution 2 - Swift

If you want to embed SwiftUI into a UIKit view controller, use a Container View.

class ViewController: UIViewController {
    @IBOutlet weak var theContainer: UIView!

    override func viewDidLoad() {
        super.viewDidLoad()

        let childView = UIHostingController(rootView: SwiftUIView())
        addChild(childView)
        childView.view.frame = theContainer.bounds
        theContainer.addSubview(childView.view)
        childView.didMove(toParent: self)
    }
}

Reference

Solution 3 - Swift

UIHostingController

Although at the moment the documentation for the class has not been written, UIHostingController<Content> seems to be what you're looking for: https://developer.apple.com/documentation/swiftui/uihostingcontroller

I've just tried it in my app with the following line of code:

let vc = UIHostingController(rootView: BenefitsSwiftUIView())

Where BenefitsSwiftUIView is just the default "Hello World" View from SwiftUI. This works exactly as you expect it. It also works if you subclass UIHostingController.

Solution 4 - Swift

One item I have not seen mentioned yet, and involves Xcode 11 beta 5 (11M382q) involves updating your app's info.plist file.

For my scenario, I am taking an existing Swift & UIKit based application and fully migrating it to be an iOS 13 & pure SwiftUI app, so backwards compatibility is not a concern for me.

After making the necessary changes to AppDelegate:

// MARK: UISceneSession Lifecycle
func application(_ application: UIApplication,
                 configurationForConnecting connectingSceneSession: UISceneSession,
                 options: UIScene.ConnectionOptions) -> UISceneConfiguration {
    return UISceneConfiguration(name: "Default Configuration",
                                sessionRole: connectingSceneSession.role)
}

And adding in a SceneDelegate class:

import UIKit
import SwiftUI

class SceneDelegate: UIResponder, UIWindowSceneDelegate {

    var window: UIWindow?

    func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
        if let windowScene = scene as? UIWindowScene {
            let window = UIWindow(windowScene: windowScene)
            window.rootViewController = UIHostingController(rootView: HomeList())
            self.window = window
            window.makeKeyAndVisible()
        }
    }
}

I was encountering a problem where my SceneDelegate was not being called. This was fixed by adding the following into my info.plist file:

<key>UIApplicationSceneManifest</key>
<dict>
    <key>UIApplicationSupportsMultipleScenes</key>
    <false/>
    <key>UISceneConfigurations</key>
    <dict>
        <key>UIWindowSceneSessionRoleApplication</key>
        <array>
            <dict>
                <key>UISceneClassName</key>
                <string></string>
                <key>UISceneDelegateClassName</key>
                <string>$(PRODUCT_MODULE_NAME).SceneDelegate</string>
                <key>UISceneConfigurationName</key>
                <string>Default Configuration</string>
                <key>UISceneStoryboardFile</key>
                <string>LaunchScreen</string>
            </dict>
        </array>
    </dict>
</dict>

And a screenshot to see: enter image description here

The main items to keep in sync are:

  • Delegate Class Name so that Xcode knows where to find your SceneDelegate file
  • Configuration Name so that the call in AppDelegate can load the correct UISceneConfiguration

After doing this, I was then able to load my newly created HomeList view (A SwiftUI object)

Solution 5 - Swift

If you're looking to create a SwiftUI view from a legacy Objective C project, then this technique worked perfectly for me,

See Adding SwiftUI to Objective-C Apps

Kudos to our friend who wrote that up.

Solution 6 - Swift

if you are facing layout problems, you must add constraints to view of UIHostingController,

class ViewController: UIViewController {
    @IBOutlet weak var theContainer: UIView!

    override func viewDidLoad() {
        super.viewDidLoad()

        let childView = UIHostingController(rootView: SwiftUIView())
        addChild(childView)
        childView.view.frame = theContainer.bounds
        theContainer.addConstrained(subview: childView.view)
        childView.didMove(toParent: self)
    }
}

using this extension:

extension UIView {
    func addConstrained(subview: UIView) {
        addSubview(subview)
        subview.translatesAutoresizingMaskIntoConstraints = false
        subview.topAnchor.constraint(equalTo: topAnchor).isActive = true
        subview.leadingAnchor.constraint(equalTo: leadingAnchor).isActive = true
        subview.trailingAnchor.constraint(equalTo: trailingAnchor).isActive = true
        subview.bottomAnchor.constraint(equalTo: bottomAnchor).isActive = true
    }
}

Solution 7 - Swift

Here's How I do it:

Create a SwiftUI Adapter

/**
 * Adapts a SwiftUI view for use inside a UIViewController.
 */
class SwiftUIAdapter<Content> where Content : View {

    private(set) var view: Content!
    weak private(set) var parent: UIViewController!
    private(set) var uiView : WrappedView
    private var hostingController: UIHostingController<Content>

    init(view: Content, parent: UIViewController) {
        self.view = view
        self.parent = parent
        hostingController = UIHostingController(rootView: view)
        parent.addChild(hostingController)
        hostingController.didMove(toParent: parent)
        uiView = WrappedView(view: hostingController.view)
    }

    deinit {
        hostingController.removeFromParent()
        hostingController.didMove(toParent: nil)
    }

}

Add to a view controller as follows:

class FeedViewController: UIViewController {
    
    var adapter : SwiftUIAdapter<FeedView>!

    override required init(nibName nibNameOrNil: String?, bundle nibBundleOrNil: Bundle?) {
        super.init(nibName: nibNameOrNil, bundle: nibBundleOrNil)
        adapter = SwiftUIAdapter(view: FeedView(), parent: self)
    }

    required init?(coder: NSCoder) {
        super.init(coder: coder)
    }
    
    /** Override load view to load the SwiftUI adapted view */
    override func loadView() {
        view = adapter.uiView;
    }
}

Here's the Code for Wrapped View

Wrapped view uses manual layout (layoutSubViews) rather than auto-layout, for this very simple case.

class WrappedView: UIView {

    private (set) var view: UIView!

    init(view: UIView) {
        self.view = view
        super.init(frame: CGRect.zero)
        addSubview(view)
    }

    override init(frame: CGRect) {
        super.init(frame: frame)
    }

    required init?(coder: NSCoder) {
        super.init(coder: coder)
    }

    override func layoutSubviews() {
        super.layoutSubviews()
        view.frame = bounds
    }
}

Solution 8 - Swift

With The Storyboard

You can use HotingViewController component in the interface builder:

Preview

Then if you have a simple HotingController like this:

class MySwiftUIHostingController: UIHostingController<Text> {
    required init?(coder: NSCoder) {
        super.init(coder: coder, rootView: Text("Hello World"))
    }
}

you can set it as the custom class of the controller:

Preview 2


With Code

let mySwiftUIHostingController = UIHostingController(rootView: Text("Hello World"))

And then you can use it like a normal UIViewController


Important Note

Don't forget to import SwiftUI where ever you need UIHostingController

Solution 9 - Swift

You can achieve this by simply following these steps...

  1. Create a button in viewController presented on mainStoryBoard and import SwiftUI

  2. Add a hostingViewController in mainStoryboard and Drag a Segue (show Segue) from button to hostingViewController.Drag segue from storyBoard to SwiftUI

  3. Add SwiftUI file in your project by clicking Cmd+N Creating SwiftUI file

  4. Add segueAction form segue presented in mainStoryBoard to viewController.

  5. Write the folling lines of code in segueAction...

@IBSegueAction func ActionMe(_ coder: NSCoder) -> UIViewController? {
    return UIHostingController(coder: coder, rootView: SWIFTUI())
}

Solution 10 - Swift

You can use them together. You can 'transfer' a UIView to View by UIViewRepresentable conformance. Details can be found in the official tutorial.

However, you should also consider its compatibility.

Here is the code snippet from Protocol View of SwiftUI:

///
/// You create custom views by declaring types that conform to the `View`
/// protocol. Implement the required `body` property to provide the content
/// and behavior for your custom view.
@available(iOS 13.0, OSX 10.15, tvOS 13.0, watchOS 6.0, *)
public protocol View : _View {

    /// The type of view representing the body of this view.
    ///
    /// When you create a custom view, Swift infers this type from your
    /// implementation of the required `body` property.
    /// ...
}

So it's not backwards compatible.

  • iOS 13.0+
  • macOS 10.15+
  • watchOS 6.0+

Solution 11 - Swift

import Foundation
    #if canImport(SwiftUI)
    import SwiftUI

internal final class SomeRouter {
    fileprivate weak var presentingViewController: UIViewController!
    
    function navigateToSwiftUIView() {
       if #available(iOS 13, *) {
            let hostingController = UIHostingController(rootView: contentView())  
presentingViewController?.navigationController?.pushViewController(hostingController, animated: true)
            return
        }
        //Keep the old way when not 13.
}
#endif

Solution 12 - Swift

Others has been showcasing how to use UIHostingController.

I can show how you can present a UIViewController from SwiftUI UIViewControllerRepresentable:

struct YourViewControllerWrapper: UIViewControllerRepresentable {
    typealias UIViewControllerType = YourViewController

    func makeUIViewController(context: UIViewControllerRepresentableContext<YourViewControllerWrapper>) -> YourViewController {
        let storyBoard = UIStoryboard(name: "YourStoryboard", bundle: Bundle.main)
        return storyBoard.instantiateViewController(withIdentifier: "YourViewController") as! YourViewController
    }

    func updateUIViewController(_ uiViewController: YourViewController, context: UIViewControllerRepresentableContext<YourViewController>) {
        // do nothing
    }
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionviscView Question on Stackoverflow
Solution 1 - SwiftfredpiView Answer on Stackoverflow
Solution 2 - SwiftMike LeeView Answer on Stackoverflow
Solution 3 - SwiftLucas van DongenView Answer on Stackoverflow
Solution 4 - SwiftCodeBenderView Answer on Stackoverflow
Solution 5 - SwiftSnipsView Answer on Stackoverflow
Solution 6 - SwiftMostfa EssamView Answer on Stackoverflow
Solution 7 - SwiftJasper BluesView Answer on Stackoverflow
Solution 8 - SwiftMojtaba HosseiniView Answer on Stackoverflow
Solution 9 - SwiftUsamaDevView Answer on Stackoverflow
Solution 10 - SwiftBenjaminView Answer on Stackoverflow
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Solution 12 - SwiftnigongView Answer on Stackoverflow