    readlink -f &lt;linkname&gt;

See the readlink(1) man page for [Linux], [FreeBSD], [NetBSD], [OpenBSD], [DragonFly][dragonfly] or the [GNU coreutils] info page.


  [Linux]: https://man7.org/linux/man-pages/man1/readlink.1.html
  [FreeBSD]: https://www.freebsd.org/cgi/man.cgi?query=readlink&amp;sektion=1
  [NetBSD]: https://man.netbsd.org/readlink.1
  [OpenBSD]: https://man.openbsd.org/readlink.1
  [DragonFly]: https://leaf.dragonflybsd.org/cgi/web-man?command=readlink&amp;section=1
  [GNU coreutils]: https://www.gnu.org/software/coreutils/manual/html_node/readlink-invocation.html

    stat &lt;linkname&gt;

**Example:**

    stat /usr/local/cuda
First 2 lines will give: 

    File: &#39;/usr/local/cuda&#39; -&gt; &#39;cuda-8.0&#39;
    Size: 8         	Blocks: 0          IO Block: 4096   symbolic link
    ...

I&#39;m trying to figure out whether I can build a static library that hides all of its internal objects and functions, etc, except for the interfaces I want to export. I&#39;m experimenting with Xcode (gcc 4.2).

I&#39;ve used the `__attribute__((visibility(&quot;hidden&quot;)))` attribute on some C++ classes per [this documentation][1]. I&#39;ve also defined little helper C functions as being file-local (static), etc.

However, when I run `strings` on the resulting .a library file, even when compiled in Release configuration, I still see the names of my ostensibly-hidden classes, with their method names, and even the names of file-local functions strewn around in there as well. 

I&#39;ve added the `-fvisibility=hidden` and even `-fno-rtti` to the gcc flags. While this reduces some of the strings, the class names, method names, and static functions names are all still in there in plain or mangled-but-readable form. 

Is there a reliable way to get the compiler to build this stuff without having the string names of all the internal stuff emitted into the binary? It shouldn&#39;t be necessary to have for any external clients linking in.

(To clarify: I&#39;m asking about obfuscation of internal naming, versus literal export binding needs. I&#39;m disconcerted that all the internal workings are visible via the `strings` command, regardless of whether these symbols are formally exported or not.)

Thanks.

  [1]: http://developer.apple.com/mac/library/documentation/DeveloperTools/Conceptual/CppRuntimeEnv/Articles/SymbolVisibility.html

Symbol hiding in static libraries built with Xcode

I know that with Vim&#39;s substitution command you can specific a range of lines:

    :12,24s/search/replace

I want to be able to specify a range with normal searches as well. Something like

    :12,24/search

Since that doesn&#39;t seem to work (at least on my Vim configuration), does anybody know how to achieve this?

Thank you.

VIM: Search only between specific line numbers?

I need to process a number of directories, determine what files in them are symlinks, and what they link to. This sounds simple, but I have no control over the presence of control or other characters in the file names, and I need a robust solution.

So, given a file of arbitrary name, how do I safely determine what it links to, when the link destination can also have arbitrary contents?

In Bash, how do I safely determine what a soft link points to?

<p>I need to process a number of directories, determine what files in them are symlinks, and what they link to. This sounds simple, but I have no control over the presence of control or other characters in the file names, and I need a robust solution.</p>
<p>So, given a file of arbitrary name, how do I safely determine what it links to, when the link destination can also have arbitrary contents?</p>


I&#39;m trying to write a post-commit hook for SVN, which is hosted on our development server.  My goal is to try to automatically checkout a copy of the committed project to the directory where it is hosted on the server.  However I need to be able to read only the last directory in the directory string passed to the script in order to checkout to the same sub-directory where our projects are hosted.

For example if I make an SVN commit to the project &quot;example&quot;, my script gets &quot;/usr/local/svn/repos/example&quot; as its first argument.  I need to get just &quot;example&quot; off the end of the string and then concat it with another string so I can checkout to &quot;/server/root/example&quot; and see the changes live immediately. 

Get last dirname/filename in a file path argument in Bash

I want to be able to run a command from my machine using ssh and pass through the environment variable `$BUILD_NUMBER`


Here&#39;s what I&#39;m trying:

    ssh pvt@192.168.1.133 &#39;~/tools/myScript.pl $BUILD_NUMBER&#39;


`$BUILD_NUMBER` is set on the machine making the ssh call and since the variable doesn&#39;t exist on the remote host, it doesn&#39;t get picked up.

How do I pass the value of `$BUILD_NUMBER` ?

Passing variables in remote ssh command

How can I send an HTML email using a shell script?

Sending HTML mail using a shell script

How can I determine the current shell I am working on? 

Would the output of the `ps` command alone be sufficient?

How can this be done in different flavors of Unix?


How to determine the current interactive shell that I&#39;m in? (command-line)

When I use the `trap` command in Bash, the previous `trap` for the given signal is replaced.

Is there a way of making more than one `trap` fire for the same signal?

Multiple Bash traps for the same signal

Consider the following command line snippet: 

    $ cd /tmp/
    $ mkdir dirA
    $ mkdir dirB
    $ echo &quot;the contents of the &#39;original&#39; file&quot; &gt; orig.file
    $ ls -la orig.file 
    -rw-r--r-- 1 $USER $USER 36 2010-12-26 00:57 orig.file
    
    # create symlinks in dirA and dirB that point to /tmp/orig.file:
    
    $ ln -s $(pwd)/orig.file $(pwd)/dirA/
    $ ln -s $(pwd)/orig.file $(pwd)/dirB/lorig.file
    $ ls -la dirA/ dirB/
    dirA/:
    total 44
    drwxr-xr-x  2 $USER $USER  4096 2010-12-26 00:57 .
    drwxrwxrwt 20 root          root          36864 2010-12-26 00:57 ..
    lrwxrwxrwx  1 $USER $USER    14 2010-12-26 00:57 orig.file -&gt; /tmp/orig.file
    
    dirB/:
    total 44
    drwxr-xr-x  2 $USER $USER  4096 2010-12-26 00:58 .
    drwxrwxrwt 20 root          root          36864 2010-12-26 00:57 ..
    lrwxrwxrwx  1 $USER $USER    14 2010-12-26 00:58 lorig.file -&gt; /tmp/orig.file

At this point, I can use `readlink` to see what is the &#39;original&#39; (well, I guess the usual term here is either &#39;target&#39; or &#39;source&#39;, but those in my mind can be opposite concepts as well, so I&#39;ll just call it &#39;original&#39;) file of the symlinks, i.e.

    $ readlink -f dirA/orig.file 
    /tmp/orig.file
    $ readlink -f dirB/lorig.file 
    /tmp/orig.file

... However, what I&#39;d like to know is - is there a command I could run on the &#39;original&#39; file, and find all the symlinks that point to it? In other words, something like (pseudo):

    $ getsymlinks /tmp/orig.file
    /tmp/dirA/orig.file 
    /tmp/dirB/lorig.file

Thanks in advance for any comments, 

Cheers!

Linux: Find all symlinks of a given &#39;original&#39; file? (reverse &#39;readlink&#39;)

When you do 

    cat some-symlink-to-some-real-file

it shows the contents of the real file, not what is within the symlink itself. Is there a way to see what&#39;s actually in it?


is there a way to see the actual contents of a symlink?

Is there a single way of detecting if a directory/file/symlink/etc. entity (more generalized) exists? 

I need a single function because I need to check an array of paths that could be directories, files or symlinks. I know `File.exists?&quot;file_path&quot;` works for directories and files but not for symlinks (which is `File.symlink?&quot;symlink_path&quot;`). 


How to check if a directory/file/symlink exists with one command in Ruby

I&#39;m trying to check if a symlink exists in bash. Here&#39;s what I&#39;ve tried.


    mda=/usr/mda
    if [ ! -L $mda ]; then
      echo &quot;=&gt; File doesn&#39;t exist&quot;
    fi


    mda=&#39;/usr/mda&#39;
    if [ ! -L $mda ]; then
      echo &quot;=&gt; File doesn&#39;t exist&quot;
    fi


However, that doesn&#39;t work. 
If &#39;!&#39; is left out, it never triggers. And if &#39;!&#39; is there, it triggers every time.


How to check if a symlink exists

Our developers use a mix of Windows and Unix-based OSes. Therefore, symbolic links created on Unix machines become a problem for Windows developers. In Windows ([MSysGit][1]), the symbolic link is converted to a text file with a path to the file it points to. Instead, I&#39;d like to convert the symbolic link into an actual Windows symbolic link.

The (**updated**) solution I have to this is:

 - Write a post-checkout script that will recursively look for &quot;symbolic link&quot; text files.
 - Replace them with a Windows symbolic link (using [mklink][2]) with the same name and extension as dummy &quot;symbolic link&quot;
 - Ignore these Windows symbolic links by adding an entry into file *.git/info/exclude*

I have not implemented this, but I believe this is a solid approach to this problem.

 1. What, if any, downsides do you see to this approach?
 2. Is this post-checkout script even implementable? I.e., can I recursively find out the dummy &quot;symlink&quot; files Git creates?

  [1]: https://github.com/msysgit/
  [2]: https://en.wikipedia.org/wiki/NTFS_links#Command-line_tools




Content Type	Original Author	Original Content on Stackoverflow
Question	swestrup	View Question on Stackoverflow
Solution 1 - Bash	eduffy	View Answer on Stackoverflow
Solution 2 - Bash	Konstantinos Roditakis	View Answer on Stackoverflow

In Bash, how do I safely determine what a soft link points to?

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Solution 2 - Bash

VIM: Search only between specific line numbers?

Symbol hiding in static libraries built with Xcode

Attributions