Ignore namespaces in LINQ to XML

.NetXmlLinq

.Net Problem Overview


How do I have LINQ to XML iqnore all namespaces? Or alteranately, how to I strip out the namespaces?

I'm asking because the namespaces are being set in a semi-random fashion and I'm tired of having to search for nodes both with and without a namespace.

.Net Solutions


Solution 1 - .Net

Instead of writing:

nodes.Elements("Foo")

write:

nodes.Elements().Where(e => e.Name.LocalName == "Foo")

and when you get tired of it, make your own extension method:

public static IEnumerable<XElement> ElementsAnyNS<T>(this IEnumerable<T> source, string localName)
    where T : XContainer
{
    return source.Elements().Where(e => e.Name.LocalName == localName);
}

Ditto for attributes, if you have to deal with namespaced attributes often (which is relatively rare).

[EDIT] Adding solution for XPath

For XPath, instead of writing:

/foo/bar | /foo/ns:bar | /ns:foo/bar | /ns:foo/ns:bar

you can use local-name() function:

/*[local-name() = 'foo']/*[local-name() = 'bar']

Solution 2 - .Net

Here's a method to strip namespaces:

private static XElement StripNamespaces(XElement rootElement)
{
    foreach (var element in rootElement.DescendantsAndSelf())
    {
        // update element name if a namespace is available
        if (element.Name.Namespace != XNamespace.None)
        {
            element.Name = XNamespace.None.GetName(element.Name.LocalName);
        }

        // check if the element contains attributes with defined namespaces (ignore xml and empty namespaces)
        bool hasDefinedNamespaces = element.Attributes().Any(attribute => attribute.IsNamespaceDeclaration ||
                (attribute.Name.Namespace != XNamespace.None && attribute.Name.Namespace != XNamespace.Xml));

        if (hasDefinedNamespaces)
        {
            // ignore attributes with a namespace declaration
            // strip namespace from attributes with defined namespaces, ignore xml / empty namespaces
            // xml namespace is ignored to retain the space preserve attribute
            var attributes = element.Attributes()
                                    .Where(attribute => !attribute.IsNamespaceDeclaration)
                                    .Select(attribute =>
                                        (attribute.Name.Namespace != XNamespace.None && attribute.Name.Namespace != XNamespace.Xml) ?
                                            new XAttribute(XNamespace.None.GetName(attribute.Name.LocalName), attribute.Value) :
                                            attribute
                                    );

            // replace with attributes result
            element.ReplaceAttributes(attributes);
        }
    }
    return rootElement;
}

Example usage:

XNamespace ns = "http://schemas.domain.com/orders";
XElement xml =
    new XElement(ns + "order",
        new XElement(ns + "customer", "Foo", new XAttribute("hello", "world")),
        new XElement("purchases",
            new XElement(ns + "purchase", "Unicycle", new XAttribute("price", "100.00")),
            new XElement("purchase", "Bicycle"),
            new XElement(ns + "purchase", "Tricycle",
                new XAttribute("price", "300.00"),
                new XAttribute(XNamespace.Xml.GetName("space"), "preserve")
            )
        )
    );

Console.WriteLine(xml.Element("customer") == null);
Console.WriteLine(xml);
StripNamespaces(xml);
Console.WriteLine(xml);
Console.WriteLine(xml.Element("customer").Attribute("hello").Value);

Solution 3 - .Net

As I found this question in search for an easy way to ignore namespaces on attributes, here's an extension for ignoring namespaces when accessing an attribute, based on Pavel´s answer (for easier copying, I included his extension):

public static XAttribute AttributeAnyNS<T>(this T source, string localName)
where T : XElement
{
    return source.Attributes().SingleOrDefault(e => e.Name.LocalName == localName);
}

public static IEnumerable<XElement> ElementsAnyNS<T>(this IEnumerable<T> source, string localName)
where T : XContainer
{
    return source.Elements().Where(e => e.Name.LocalName == localName);
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionJonathan AllenView Question on Stackoverflow
Solution 1 - .NetPavel MinaevView Answer on Stackoverflow
Solution 2 - .NetAhmad MageedView Answer on Stackoverflow
Solution 3 - .NetJoboView Answer on Stackoverflow