How to use zIndex in react-native
JavascriptReact NativeFlexboxJavascript Problem Overview
I've want to achieve the following:
The following images are what I can do right now, but that's NOT what I want.
Sample of code I have right now:
renderA() {
return (
<View style={ position: 'absolute', zIndex: 0 }> // parent of A
<View style={ zIndex: 2 }> // element A
</View>
<View style={ zIndex: 2 }> // element A
</View>
</View>
);
}
renderB() {
return (
<View style={ position: 'absolute', zIndex: 1 }> // element B
</View>
);
}
render() {
return (
<View>
{this.renderA()}
{this.renderB()}
</View>
);
}
To put it in words, I want
- Parent A: to be below everything.
- Element B: to be at the above parent A but below element A.
- Element A: above everything.
Note that Parent A and Element B both have to be absolutely positioned, and both elements A and elements B have to be clickable...!
Javascript Solutions
Solution 1 - Javascript
Use elevation instead of zIndex for android devices
elevatedElement: {
zIndex: 3, // works on ios
elevation: 3, // works on android
}
This worked fine for me!
Solution 2 - Javascript
I believe there are different ways to do this based on what you need exactly, but one way would be to just put both Elements A and B inside Parent A.
<View style={{ position: 'absolute' }}> // parent of A
<View style={{ zIndex: 1 }} /> // element A
<View style={{ zIndex: 1 }} /> // element A
<View style={{ zIndex: 0, position: 'absolute' }} /> // element B
</View>
Solution 3 - Javascript
I finally solved this by creating a second object that imitates B.
My schema now looks like this:
I now have B1 (within parent of A) and B2 outside of it.
B1 and B2 are right next to one another, so to the naked eye it looks as if it's just 1 object.
Solution 4 - Javascript
UPDATE: Supposedly, zIndex has been added to the react-native library. I've been trying to get it to work without success. Check here for details of the fix.
Solution 5 - Javascript
You can use the Elevation property in your StyleSheet
containerText: {
elevation: 3,
backgroundColor: '#FB8500',
padding: 3,
borderRadius: 15,
marginTop: -30,
marginLeft: -10,
},
Solution 6 - Javascript
You cannot achieve the desired solution with CSS z-index either, as z-index is only relative to the parent element. So if you have parents A and B with respective children a and b, b's z-index is only relative to other children of B and a's z-index is only relative to other children of A.
The z-index of A and B are relative to each other if they share the same parent element, but all of the children of one will share the same relative z-index at this level.