How to use subList()

Java

Java Problem Overview


I have a JSF page which displays list of Glassfish log files. I use lazy loading for pagination. I keep the list of the log files names into Java List.

private List<directoryListObj> dataList = new ArrayList<>();

dataList = dataList.subList(firstRow, lastRow);

And here is the problem. For example I have 35 files into the directory. When I do this

dataList = dataList.subList(5, 15);

It works fine. But when I do this:

dataList = dataList.subList(30, 38);

I get error wrong index because I want to get index outside of the List. How I can for example return List elements from 30 to 35? I want if I want to get index from 30 to 40 but if there only 35 indexes to get only 5.

Java Solutions


Solution 1 - Java

Using subList(30, 38); will fail because max index 38 is not available in list, so its not possible.

Only way may be before asking for the sublist, you explicitly determine the max index using list size() method.

for example, check size, which returns 35, so call sublist(30, size());

OR

COPIED FROM pb2q comment

dataList = dataList.subList(30, 38 > dataList.size() ? dataList.size() : 38);

Solution 2 - Java

I've implemented and tested this one; it should cover most bases:

public static <T> List<T> safeSubList(List<T> list, int fromIndex, int toIndex) {
	int size = list.size();
	if (fromIndex >= size || toIndex <= 0 || fromIndex >= toIndex) {
		return Collections.emptyList();
	}
	
	fromIndex = Math.max(0, fromIndex);
	toIndex = Math.min(size, toIndex);
	
	return list.subList(fromIndex, toIndex);
}

Solution 3 - Java

To get the last element, simply use the size of the list as the second parameter. So for example, if you have 35 files, and you want the last five, you would do:

dataList.subList(30, 35);

A guaranteed safe way to do this is:

dataList.subList(Math.max(0, first), Math.min(dataList.size(), last) );

Solution 4 - Java

You could use streams in Java 8. To always get 10 entries at the most, you could do:

dataList.stream().skip(5).limit(10).collect(Collectors.toList());
dataList.stream().skip(30).limit(10).collect(Collectors.toList());

Solution 5 - Java

Although it may be too late, I suggest using stream in Java 8 to avoid handling the out of boundry exception manually.

this code

dataList = dataList.stream().skip(30).limit(8).collect(Collectors.toList());

works same as

dataList = dataList.subList(30, 38);

and in case of out of index error, dataList will be empty list instead of throwing any exception.

Solution 6 - Java

For kotlin, you could use: myList.subList(min, max.coerceAtMost(myList.size)

Or in terms of the question above: myList.subList(30, 38.coerceAtMost(myList.size)

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser1285928View Question on Stackoverflow
Solution 1 - JavakosaView Answer on Stackoverflow
Solution 2 - JavaHaroldo_OKView Answer on Stackoverflow
Solution 3 - JavaJoe KView Answer on Stackoverflow
Solution 4 - JavaStefan HaberlView Answer on Stackoverflow
Solution 5 - JavahaoView Answer on Stackoverflow
Solution 6 - JavaTonyView Answer on Stackoverflow