How to use continue in jQuery each() loop?

JqueryFor LoopEach

Jquery Problem Overview


In my application i am using AJAX call. I want to use break and continue in this jQuery loop.

$('.submit').filter(':checked').each(function() {

});

Jquery Solutions


Solution 1 - Jquery

We can break both a $(selector).each() loop and a $.each() loop at a particular iteration by making the callback function return false. Returning non-false is the same as a continue statement in a for loop; it will skip immediately to the next iteration.

return false; // this is equivalent of 'break' for jQuery loop

return;       // this is equivalent of 'continue' for jQuery loop

Note that $(selector).each() and $.each() are different functions.

References:

  • [$(selector).each()][1]
  • [$.each()][2]
  • [What is the difference between $.each(selector) and $(selector).each() ][3]

[1]: http://api.jquery.com/each/ "$(selector).each()" [2]: http://api.jquery.com/jquery.each/ "$.each()" [3]: https://stackoverflow.com/questions/6611190/what-is-the-difference-between-eachselector-and-selector-each "What is the difference between $.each(selector) and $(selector).each()"

Solution 2 - Jquery

$('.submit').filter(':checked').each(function() {
    //This is same as 'continue'
    if(something){
        return true;
    }
    //This is same as 'break'
    if(something){
        return false;
    }
});

Solution 3 - Jquery

return or return false are not the same as continue. If the loop is inside a function the remainder of the function will not execute as you would expect with a true "continue".

Solution 4 - Jquery

> We can break the $.each() loop at a particular iteration by making the > callback function return false. Returning non-false is the same as a > continue statement in a for loop; it will skip immediately to the next > iteration. -- jQuery.each() | jQuery API Documentation

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRavi KantView Question on Stackoverflow
Solution 1 - JqueryJayramView Answer on Stackoverflow
Solution 2 - JquerySuresh KhandekarView Answer on Stackoverflow
Solution 3 - JqueryBillyView Answer on Stackoverflow
Solution 4 - JqueryNabil KadimiView Answer on Stackoverflow