How to use a variable's value as another variable's name in bash

Bash

Bash Problem Overview


I want to declare a variable, the name of which comes from the value of another variable, and I wrote the following piece of code:

a="bbb"
$a="ccc"

but it didn't work. What's the right way to get this job done?

Bash Solutions


Solution 1 - Bash

eval is used for this, but if you do it naively, there are going to be nasty escaping issues. This sort of thing is generally safe:

name_of_variable=abc

eval $name_of_variable="simpleword"   # abc set to simpleword

This breaks:

eval $name_of_variable="word splitting occurs"

The fix:

eval $name_of_variable="\"word splitting occurs\""  # not anymore

The ultimate fix: put the text you want to assign into a variable. Let's call it safevariable. Then you can do this:

eval $name_of_variable=\$safevariable  # note escaped dollar sign

Escaping the dollar sign solves all escape issues. The dollar sign survives verbatim into the eval function, which will effectively perform this:

eval 'abc=$safevariable' # dollar sign now comes to life inside eval!

And of course this assignment is immune to everything. safevariable can contain *, spaces, $, etc. (The caveat being that we're assuming name_of_variable contains nothing but a valid variable name, and one we are free to use: not something special.)

Solution 2 - Bash

You can use declare and !, like this:

John="nice guy"
programmer=John
echo ${!programmer} # echos nice guy

Second example:

programmer=Ines
declare $programmer="nice gal"
echo $Ines # echos nice gal

Solution 3 - Bash

This might work for you:

foo=bar
declare $foo=baz
echo $bar
baz

or this:

foo=bar
read $foo <<<"baz"
echo $bar
baz

Solution 4 - Bash

You could make use of eval for this.
Example:

$ a="bbb"
$ eval $a="ccc"
$ echo $bbb
ccc

Hope this helps!

Solution 5 - Bash

If you want to get the value of the variable instead of setting it you can do this

var_name1="var_name2"
var_name2=value_you_want
eval temp_var=\$$var_name1
echo "$temp_var"

You can read about it here indirect references.

Solution 6 - Bash

You can assign a value to a variable using simple assignment using a value from another variable like so:

#!/usr/bin/bash

#variable one
a="one"

echo "Variable a is $a"
#variable two with a's variable
b="$a"

echo "Variable b is $b"

#change a
a="two"
echo "Variable a is $a"
echo "Variable b is $b"

The output of that is this:

Variable a is one
Variable b is one
Variable a is two
Variable b is one

So just be sure to assign it like this b="$a" and you should be good.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionHaiyuan ZhangView Question on Stackoverflow
Solution 1 - BashKazView Answer on Stackoverflow
Solution 2 - BashFlimmView Answer on Stackoverflow
Solution 3 - BashpotongView Answer on Stackoverflow
Solution 4 - Bashanother.anon.cowardView Answer on Stackoverflow
Solution 5 - Bashbat_ventziView Answer on Stackoverflow
Solution 6 - BashJossie BView Answer on Stackoverflow