How to update the _id of one MongoDB Document?

Mongodb

Mongodb Problem Overview


I want update an _id field of one document. I know it's not really good practice. But for some technical reason, I need to update it.

If I try to update it I get:

db.clients.update({ _id: ObjectId("123")}, { $set: { _id: ObjectId("456")}})

Performing an update on the path '_id' would modify the immutable field '_id'

And the update is rejected. How I can update it?

Mongodb Solutions


Solution 1 - Mongodb

You cannot update it. You'll have to save the document using a new _id, and then remove the old document.

// store the document in a variable
doc = db.clients.findOne({_id: ObjectId("4cc45467c55f4d2d2a000002")})

// set a new _id on the document
doc._id = ObjectId("4c8a331bda76c559ef000004")

// insert the document, using the new _id
db.clients.insert(doc)

// remove the document with the old _id
db.clients.remove({_id: ObjectId("4cc45467c55f4d2d2a000002")})

Solution 2 - Mongodb

To do it for your whole collection you can also use a loop (based on Niels example):

db.status.find().forEach(function(doc){ 
    doc._id=doc.UserId; db.status_new.insert(doc);
});
db.status_new.renameCollection("status", true);

In this case UserId was the new ID I wanted to use

Solution 3 - Mongodb

In case, you want to rename _id in same collection (for instance, if you want to prefix some _ids):

db.someCollection.find().snapshot().forEach(function(doc) { 
   if (doc._id.indexOf("2019:") != 0) {
       print("Processing: " + doc._id);
       var oldDocId = doc._id;
       doc._id = "2019:" + doc._id; 
       db.someCollection.insert(doc);
       db.someCollection.remove({_id: oldDocId});
   }
});

if (doc._id.indexOf("2019:") != 0) {... needed to prevent infinite loop, since forEach picks the inserted docs, even throught .snapshot() method used.

Solution 4 - Mongodb

Here I have a solution that avoid multiple requests, for loops and old document removal.

You can easily create a new idea manually using something like:_id:ObjectId() But knowing Mongo will automatically assign an _id if missing, you can use aggregate to create a $project containing all the fields of your document, but omit the field _id. You can then save it with $out

So if your document is:

{
"_id":ObjectId("5b5ed345cfbce6787588e480"),
"title": "foo",
"description": "bar"
}

Then your query will be:

    db.getCollection('myCollection').aggregate([
        {$match:
             {_id: ObjectId("5b5ed345cfbce6787588e480")}
        }        
        {$project:
            {
             title: '$title',
             description: '$description'             
            }     
        },
        {$out: 'myCollection'}
    ])

Solution 5 - Mongodb

You can also create a new document from MongoDB compass or using command and set the specific _id value that you want.

Solution 6 - Mongodb

As a very small improvement to the above answers i would suggest using

let doc1 = {... doc};

then

db.dyn_user_metricFormulaDefinitions.deleteOne({_id: doc._id});

This way we don't need to create extra variable to hold old _id.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionshingaraView Question on Stackoverflow
Solution 1 - MongodbNiels van der RestView Answer on Stackoverflow
Solution 2 - MongodbPatrick WolfView Answer on Stackoverflow
Solution 3 - MongodbMarkView Answer on Stackoverflow
Solution 4 - MongodbFlorent ArlandisView Answer on Stackoverflow
Solution 5 - MongodbTalha NoyonView Answer on Stackoverflow
Solution 6 - MongodbGPuriView Answer on Stackoverflow