Find only regular files under current directory, and print them without &quot;`./`&quot; prefix:

    find -type f -printf &#39;%P\n&#39;

From man find, description of `-printf` format:

&gt; %P &amp;nbsp; &amp;nbsp; File&#39;s name with the name of the command line argument under which it was found removed.



Use sed

    find . | sed &quot;s|^\./||&quot;


If they&#39;re only in the current directory

`find * -type f -print`

Is that what you want?

Another way of stripping the `./` is by using `cut` like:

    find -type f | cut -c3-

Further explanation can be found [here][1]


  [1]: https://unix.stackexchange.com/a/331713/343429

Since `-printf` option is not available on OSX `find` here is one command that works on OSX find, just in case if someone doesn&#39;t want to install `gnu find` using `brew` etc:

    find . -type f -execdir printf &#39;%s\n&#39; {} + 


Another way of stripping the ./

    find * -type d -maxdepth 0

I have a string like the following:

    String str = &quot;4*5&quot;;

Now I have to get the result of `20` by using the string.

I know in some other languages the `eval()` function will do this.
How can I do this in Java?

Is there an eval() function in Java?

I am using logback/slf4j to do my logging. I want to parse my log file to analyze some data, so instead of parsing a great big file (mostly consisting of debug statements) I want to have two logger instances which each log to a separate file; one for analytics and one for all purpose logging. Does anyone know if this is possible with Logback, or any other logger for that matter?

Logback to log different messages to two files

    find . -type f -print
prints out
 
    ./file1
    ./file2
    ./file3

Any way to make it print
    
    file1
    file2
    file3

?


How to strip leading &quot;./&quot; in unix &quot;find&quot;?

<pre><code class="hljs language-lua">find . -type f -print
</code></pre>
prints out
<pre><code class="hljs language-bash">./file1
./file2
./file3
</code></pre>
Any way to make it print
<pre><code class="hljs">file1
file2
file3
</code></pre>
?

How can I programmatically (i.e., not using [`vi`][1]) convert DOS/Windows newlines to Unix?

The `dos2unix` and `unix2dos` commands are not available on certain systems. How can I emulate these with commands like `sed`, `awk`, and `tr`?

  [1]: https://en.wikipedia.org/wiki/Vi





How to convert DOS/Windows newline (CRLF) to Unix newline (LF) in a Bash script

I need to find all image files from directory (gif, png, jpg, jpeg).

    find /path/to/ -name &quot;*.jpg&quot; &gt; log

How to modify this string to find not only .jpg files?

How to use find command to find all files with extensions from list?

I want to remove the EXIF information (including thumbnail, metadata, camera info... everything!) from JPEG files, but I don&#39;t want to recompress it, as recompressing the JPEG will degrade the quality, as well as usually increasing the file size.

I&#39;m looking for a Unix/Linux solution, even better if using the command-line. If possible, using ImageMagick (convert tool). If that&#39;s not possible, a small Python, Perl, PHP (or other common language on Linux) script would be ok.


There is a similar question, but [related to .NET][1].


  [1]: https://stackoverflow.com/questions/1813676/how-can-i-write-an-exif-header-without-recompressing-the-jpeg-in-net

How to remove EXIF data without recompressing the JPEG?

Either I missed some backlash or backlashing does not seem to work with too much programmer-quote-looping.

    $ echo &quot;hello1-`echo hello2-\`echo hello3-\`echo hello4\`\``&quot;
    
    hello1-hello2-hello3-echo hello4

**Wanted**

    hello1-hello2-hello3-hello4-hello5-hello6-...


How to properly nest Bash backticks

Given file names like these:

    /the/path/foo.txt
    bar.txt

I hope to get:

    foo
    bar

Why this doesn&#39;t work?

    #!/bin/bash
    
    fullfile=$1
    fname=$(basename $fullfile)
    fbname=${fname%.*}
    echo $fbname

What&#39;s the right way to do it?



Extract file basename without path and extension in bash

    &lt;?xml version=&quot;1.0&quot; ?&gt;
    &lt;data&gt;
        &lt;test &gt;
            &lt;f1 /&gt;
        &lt;/test &gt;
        &lt;test2 &gt;
            &lt;test3&gt;
             &lt;f1 /&gt;
            &lt;/test3&gt;
        &lt;/test2&gt;
        &lt;f1 /&gt;
    &lt;/data&gt;

Using lxml is it possible to find recursively for tag &quot; f1 &quot;? I tried findall method but it works only for immediate children.

I think I should go for BeautifulSoup for this !!!


How to find recursively for a tag of XML using LXML?

I have several configuration files nested like such:

    C:\Projects\Project_1\project1.config
      
    C:\Projects\Project_2\project2.config

In my configuration I need to do a string replace like such:

    &lt;add key=&quot;Environment&quot; value=&quot;Dev&quot;/&gt;

will become:

    &lt;add key=&quot;Environment&quot; value=&quot;Demo&quot;/&gt;

I thought about using batch scripting, but there was no good way to do this, and I heard that with PowerShell scripting you can easily perform this. I have found examples of find/replace, but I was hoping for a way that would traverse all folders within my C:\Projects directory and find any files that end with the &#39;.config&#39; extension. When it finds one, I want it to replace my string values.

Any good resources to find out how to do this or any PowerShell gurus that can offer some insight?


PowerShell Script to Find and Replace for all Files with a Specific Extension

I was helped out today with a command, but it doesn&#39;t seem to be working. This is the command:

    find /home/me/download/ -type f -name &quot;*.rm&quot; -exec ffmpeg -i {} -sameq {}.mp3 &amp;&amp; rm {}\;

The shell returns

    find: missing argument to `-exec&#39;

What I am basically trying to do is go through a directory recursively (if it has other directories) and run the ffmpeg command on the `.rm` file types and convert them to `.mp3` file types. Once this is done, remove the `.rm` file that has just been converted.

I appreciate any help on this.

find: missing argument to -exec

My source tree contains several directories which are using Git source control, and I need to tarball the whole tree excluding any references to the Git metadata or custom log files.

I thought I&#39;d have a go using a combination of find/egrep/xargs/tar, but somehow the tar file contains the .git directories and the *.log files.

This is what I have:

    find -type f . | egrep -v &#39;\.git|\.log&#39; | xargs tar rvf ~/app.tar

Can someone explain my misunderstanding here? Why is tar processing the files that find and egrep are filtering?

I&#39;m open to other techniques as well.


Tarballing without Git metadata

I want to strip double quotes from:

    string = &#39;&quot;&quot; &quot; &quot; &quot;&quot;\\1&quot; &quot; &quot;&quot; &quot;&quot;&#39;

to obtain:

    string = &#39;&quot; &quot; &quot; &quot;&quot;\\1&quot; &quot; &quot;&quot; &quot;&#39;

I tried to use `rstrip`, `lstrip` and `strip(&#39;[^\&quot;]|[\&quot;$]&#39;)` but it did not work.

How can I do this?


How can I strip first and last double quotes?

I know this is not quite a data visualization issue, but the boss asked for it, so I need to figure out if it is possible.

Thanks!

can I change the position of the strip label in ggplot from the top to the bottom?

Is there a built-in function in Python that would replace (or remove, whatever) the extension of a filename (if it has one)?

Example:

    print replace_extension(&#39;/home/user/somefile.txt&#39;, &#39;.jpg&#39;)

In my example: `/home/user/somefile.txt` would become `/home/user/somefile.jpg`

I don&#39;t know if it matters, but I need this for a SCons module I&#39;m writing. (So perhaps there is some SCons specific function I can use ?)

I&#39;d like something **clean**. Doing a simple string replacement of all occurrences of `.txt` within the string is obviously not clean. (This would fail if my filename is `somefile.txt.txt.txt`)

How can I replace (or strip) an extension from a filename in Python?

How do I strip all the spaces in a python string? For example, I want a string like `strip my spaces` to be turned into `stripmyspaces`, but I cannot seem to accomplish that with `strip()`:

    &gt;&gt;&gt; &#39;strip my spaces&#39;.strip()
    &#39;strip my spaces&#39;

How to strip all whitespace from string

I have some python code that splits on comma, but doesn&#39;t strip the whitespace:

    &gt;&gt;&gt; string = &quot;blah, lots  ,  of ,  spaces, here &quot;
    &gt;&gt;&gt; mylist = string.split(&#39;,&#39;)
    &gt;&gt;&gt; print mylist
    [&#39;blah&#39;, &#39; lots  &#39;, &#39;  of &#39;, &#39;  spaces&#39;, &#39; here &#39;]

I would rather end up with whitespace removed like this:

    [&#39;blah&#39;, &#39;lots&#39;, &#39;of&#39;, &#39;spaces&#39;, &#39;here&#39;]

I am aware that I could loop through the list and strip() each item but, as this is Python, I&#39;m guessing there&#39;s a quicker, easier and more elegant way of doing it.

Content Type	Original Author	Original Content on Stackoverflow
Question	breadjesus	View Question on Stackoverflow
Solution 1 - Unix	Ilia K.	View Answer on Stackoverflow
Solution 2 - Unix	Lie Ryan	View Answer on Stackoverflow
Solution 3 - Unix	Tim Green	View Answer on Stackoverflow
Solution 4 - Unix	ghostdog74	View Answer on Stackoverflow
Solution 5 - Unix	banjoAtix	View Answer on Stackoverflow
Solution 6 - Unix	anubhava	View Answer on Stackoverflow
Solution 7 - Unix	Valheru	View Answer on Stackoverflow

How to strip leading "./" in unix "find"?

Unix Problem Overview

Unix Solutions

Solution 1 - Unix

Solution 2 - Unix

Solution 3 - Unix

Solution 4 - Unix

Solution 5 - Unix

Solution 6 - Unix

Solution 7 - Unix

Logback to log different messages to two files

Is there an eval() function in Java?

Attributions