Django provides an utility function to remove HTML tags:

    from django.utils.html import strip_tags
    
    my_string = &#39;&lt;div&gt;Hello, world&lt;/div&gt;&#39;
    my_string = strip_tags(my_string)
    print(my_string)
    # Result will be &quot;Hello, world&quot; without the &lt;div&gt; elements

This function used to be unsafe on older Django version (before 1.7) but nowadays it is **completely safe** to use it. [Here is][1] an article that reviewed this issue when it was relevant.


  [1]: https://www.mehmetince.net/django-strip_tags-bypass-vulnerability-exploit/

The [striptags][1] template filter.

    {{ value|striptags }}

  [1]: http://docs.djangoproject.com/en/dev/ref/templates/builtins/#striptags

Django 3

    {{ the_value | striptags | safe | escape }}

This Code:

    Something = new Guid() 

is returning:

&gt; 00000000-0000-0000-0000-000000000000

all the time and I can&#39;t tell why? So, why?

How to use Guids in C#?

I have created a custom URL protocol handler.

`http://`

`mailto://`

**`custom://`**

I have registered a WinForms application to respond accordingly. This all works great.

But I would like to be able to gracefully handle the case where the user doesn&#39;t have the custom URL protocol handler installed, yet.

In order to be able to do this I need to be able to detect the browser&#39;s registered protocol handlers, I would assume from JavaScript. But I have been unable to find a way to poll for the information. I am hoping to find a solution to this problem.

Thanks for any ideas you might be able to share.





How to detect browser&#39;s protocol handlers?

What is the easiest way to strip all html/javascript from a string?

How to strip html/javascript from text input in django

<p>What is the easiest way to strip all html/javascript from a string?</p>


With python properties, I can make it such that 

    obj.y 

calls a function rather than just returning a value.

Is there a way to do this with modules? I have a case where I want

    module.y 

to call a function, rather than just returning the value stored there.


Can modules have properties the same way that objects can?

I&#39;m trying to create a daemon in python. I&#39;ve found the [following question][1], which has some good resources in it which I am currently following, but I&#39;m curious as to why a double fork is necessary. I&#39;ve scratched around google and found plenty of resources declaring that one is necessary, but not why.

Some mention that it is to prevent the daemon from acquiring a controlling terminal. How would it do this without the second fork? What are the repercussions?

  [1]: https://stackoverflow.com/questions/473620/how-do-you-create-a-daemon-in-python

What is the reason for performing a double fork when creating a daemon?

Is there any way to get the effect of running `python -u` from within my code? Failing that, can my program check if it is running in `-u` mode and exit with an error message if not? This is on Linux (Ubuntu 8.10 Server).

Unbuffered stdout in python (as in python -u) from within the program

I&#39;ve been trying to understand what&#39;s the optimal way to do [Ajax][1] in [Django][2]. By reading stuff here and there I gathered that the common process is: 

1. formulate your Ajax call using some [JavaScript][3] library (e.g., [jQuery][4]), set up a URL pattern in Django that catches the call and passes it to a view function

2. in the [Python][5] view function retrieve the objects you are interested in and send them back to the client in JSON format or similar (by using the built in serializer module, or [simplejson][6])

3. define a callback function in JavaScript that receives the JSON data and parses them, so to  create whatever HTML is needed to be displayed. Finally, the JavaScript script puts the HTML  wherever it should stay.

Now, what I still don&#39;t get is *how are Django templates related to all of this?* Apparently, we&#39;re not making use of the power of templates at all. 
Ideally, I thought it&#39;d be nice to pass back a JSON object and a template name, so that the data could be iterated over and an HTML block is created. But maybe I&#39;m totally wrong here...

The only resource I found that goes in this direction is [this snippet (769)][7] but I haven&#39;t tried it yet. 
Obviously, what&#39;s going to happen in this case is that all the resulting HTML is created on the server side, then passed to the client. The JavaScript-callback function only has to display it in the right place.

Does this cause performance problems? If not, even without using the snippet above, why not formatting the HTML directly in the backend using Python instead of the front-end?

Many thanks! 

**UPDATE: please use [snippet 942][8] because it is an enhanced version of the one above!** I found that the inheritance support works much better this way..


  [1]: http://en.wikipedia.org/wiki/Ajax_%28programming%29
  [2]: http://en.wikipedia.org/wiki/Django_%28web_framework%29
  [3]: http://en.wikipedia.org/wiki/JavaScript
  [4]: http://en.wikipedia.org/wiki/JQuery
  [5]: http://en.wikipedia.org/wiki/Python_%28programming_language%29
  [6]: http://code.google.com/p/simplejson/
  [7]: http://www.djangosnippets.org/snippets/769/
  [8]: http://www.djangosnippets.org/snippets/942/

Rendering JSON objects using a Django template after an Ajax call

How to send HTML content in email using Python? I can send simple texts.

Send HTML emails with Python

Often, when restarting Django runserver, if I use the same port number, I get a &#39;port is already in use&#39; message.  Subsequently, I need to increment the port number each time to avoid this.

It&#39;s not the case on all servers, however, so I&#39;m wondering how I might achieve this on the current system that I&#39;m working on? 

BTW, the platform is Ubuntu 8.10

How to &#39;clear&#39; the port when restarting django runserver

I&#39;m building a web application with Django. The reasons I chose Django were:

 - I wanted to work with free/open-source tools.
 - I like Python and feel it&#39;s a **long-term** language, whereas regarding Ruby I wasn&#39;t sure, and PHP seemed like a huge hassle to learn.
 - I&#39;m building a prototype for an idea and wasn&#39;t thinking too much about the future. Development speed was the main factor, and I already knew Python.
 - I knew the migration to Google App Engine would be easier should I choose to do so in the future.
 - I heard Django was &quot;nice&quot;.

Now that I&#39;m getting closer to thinking about publishing my work, I start being concerned about scale. The only information I found about the scaling capabilities of Django is provided by the Django team (I&#39;m not saying anything to disregard them, but this is clearly not objective information...).

**My questions:**

 - What&#39;s the &quot;largest&quot; site that&#39;s built on Django today? (I measure size mostly by user traffic)
 - Can Django deal with *100,000 users daily*, each visiting the site for a couple of hours?
 - Could a site like Stack Overflow run on Django?

Does Django scale?

I&#39;d like to call the equivalent of `manage.py loaddata` from a Django view.  I&#39;d like to be able to specify where to load the data from and which application to load it into.

Any ideas?

Programmatically using Django&#39;s loaddata

I know how to reload a regular Python module within a regular Python interpreter session. This question documents how to do that pretty well:

[How do I unload (reload) a Python module?][1]

For some reason, I am having trouble doing that within Django&#39;s &quot;manage.py shell&quot; interpreter session. To recreate my issue, start the basic Django tutorial found here:

[Writing your first Django app, part 1][2]

After creating the &quot;polls&quot; application and &quot;Poll&quot; class, start up the interpreter via &quot;manage.py shell&quot; and import the &quot;polls&quot; app into it.

    import polls.models as pm

Create a new &quot;Poll&quot; object:

    p = pm.Poll()

All is well and good so far. Now go back to your source and add any arbitrary method or attribute. For example, I&#39;ve added:

    def x(self):
        return 2+2

Now go back to the interpreter and &quot;reload&quot; the module:

    reload(pm)

Now try to use your new method or attribute:

    p1 = pm.Poll()
    p1.x()

You&#39;ll get this message:

    &#39;Poll&#39; object has no attribute &#39;x&#39;

What gives? I&#39;ve also tried rerunning the import command, importing the module using different syntax, deleting all references to any &quot;Poll&quot; objects or to the &quot;Poll&quot; class. I&#39;ve also tried this with both the IPython interpreter and with the plain Python (v2.6) interpreter. Nothing seems to work.

Using the same techniques with an arbitrary Python module in a regular interpreter session works perfectly. I just can&#39;t seem to get it to work in Django&#39;s &quot;shell&quot; session.

By the way, if it makes any difference, I&#39;m doing this on a Ubuntu 9.04 machine.

  [1]: https://stackoverflow.com/questions/437589/how-do-i-unload-reload-a-python-module
  [2]: http://docs.djangoproject.com/en/dev/intro/tutorial01/

Content Type	Original Author	Original Content on Stackoverflow
Question	Eldila	View Question on Stackoverflow
Solution 1 - Python	Eldila	View Answer on Stackoverflow
Solution 2 - Python	Ayman Hourieh	View Answer on Stackoverflow
Solution 3 - Python	Ahmed Shehab	View Answer on Stackoverflow

How to strip html/javascript from text input in django

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

Solution 3 - Python

How to detect browser's protocol handlers?

How to use Guids in C#?

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