How to strings.Split on newline?
GoGo Problem Overview
I'm trying to do the rather simple task of splitting a string by newlines.
This does not work:
temp := strings.Split(result,`\n`)
I also tried ' instead of ` but no luck.
Any ideas?
Go Solutions
Solution 1 - Go
You have to use "\n"
.
Splitting on `\n`
, searches for an actual \
followed by n
in the text, not the newline byte.
Solution 2 - Go
For those of us that at times use Windows platform, it can help remember to use replace before split:
strings.Split(strings.ReplaceAll(windows, "\r\n", "\n"), "\n")
Solution 3 - Go
It does not work because you're using backticks:
> Raw string literals are character sequences between back quotes ``. Within the quotes, any character is legal except back quote. The value of a raw string literal is the string composed of the uninterpreted (implicitly UTF-8-encoded) characters between the quotes; in particular, backslashes have no special meaning and the string may contain newlines.
Reference: http://golang.org/ref/spec#String_literals
So, when you're doing
strings.Split(result,`\n`)
you're actually splitting using the two consecutive characters "" and "n", and not the character of line return "\n". To do what you want, simply use "\n"
instead of backticks.
Solution 4 - Go
Your code doesn't work because you're using backticks instead of double quotes. However, you should be using a bufio.Scanner
if you want to support Windows.
import (
"bufio"
"strings"
)
func SplitLines(s string) []string {
var lines []string
sc := bufio.NewScanner(strings.NewReader(s))
for sc.Scan() {
lines = append(lines, sc.Text())
}
return lines
}
Alternatively, you can use strings.FieldsFunc
(this approach skips blank lines)
strings.FieldsFunc(s, func(c rune) bool { return c == '\n' || c == '\r' })
Solution 5 - Go
' doesn't work because it is not a string type, but instead a rune.
temp := strings.Split(result,'\n')
go compiler: cannot use '\u000a' (type rune) as type string in argument to strings.Split
definition: Split(s, sep string) []string
Solution 6 - Go
import regexp
var lines []string = regexp.MustCompile("\r?\n").Split(inputString, -1)
MustCompile()
creates a regular expression that allows to split by both \r\n
and \n
Split()
performs the split, seconds argument sets maximum number of parts, -1
for unlimited