How to store directory files listing into an array?
BashShellBash Problem Overview
I'm trying to store the files listing into an array and then loop through the array again.
Below is what I get when I run ls -ls command from the console.
total 40
36 -rwxrwxr-x 1 amit amit 36720 2012-03-31 12:19 1.txt
4 -rwxrwxr-x 1 amit amit 1318 2012-03-31 14:49 2.txt
The following bash script I've written to store the above data into a bash array.
i=0
ls -ls | while read line
do
array[ $i ]="$line"
(( i++ ))
done
But when I echo $array, I get nothing!
FYI, I run the script this way: ./bashscript.sh
Bash Solutions
Solution 1 - Bash
I'd use
files=(*)
And then if you need data about the file, such as size, use the stat command on each file.
Solution 2 - Bash
Try with:
#! /bin/bash
i=0
while read line
do
array[ $i ]="$line"
(( i++ ))
done < <(ls -ls)
echo ${array[1]}
In your version, the while runs in a subshell, the environment variables you modify in the loop are not visible outside it.
(Do keep in mind that parsing the output of ls is generally not a good idea at all.)
Solution 3 - Bash
Here's a variant that lets you use a regex pattern for initial filtering, change the regex to be get the filtering you desire.
files=($(find -E . -type f -regex "^.*$"))
for item in ${files[*]}
do
printf " %s\n" $item
done
Solution 4 - Bash
This might work for you:
OIFS=$IFS; IFS=$'\n'; array=($(ls -ls)); IFS=$OIFS; echo "${array[1]}"
Solution 5 - Bash
Running any shell command inside $(...) will help to store the output in a variable. So using that we can convert the files to array with IFS.
IFS=' ' read -r -a array <<< $(ls /path/to/dir)
Solution 6 - Bash
You may be tempted to use (*) but what if a directory contains the * character? It's very difficult to handle special characters in filenames correctly.
You can use ls -ls. However, it fails to handle newline characters.
# Store la -ls as an array
readarray -t files <<< $(ls -ls)
for (( i=1; i<${#files[@]}; i++ ))
{
# Convert current line to an array
line=(${files[$i]})
# Get the filename, joining it together any spaces
fileName=${line[@]:9}
echo $fileName
}
If all you want is the file name, then just use ls:
for fileName in $(ls); do
echo $fileName
done
See this article or this this post for more information about some of the difficulties of dealing with special characters in file names.
Solution 7 - Bash
Isn't these 2 code lines, either using scandir or including the dir pull in the declaration line, supposed to work?
src_dir="/3T/data/MySQL";
# src_ray=scandir($src_dir);
declare -a src_ray ${src_dir/*.sql}
printf ( $src_ray );
Solution 8 - Bash
simply you can use this below for loop
declare -a arr
for file in *.txt
do
arr=(${arrPi[*]} "$file")
done