How to skip iterations in a loop?
PythonPython Problem Overview
I have a loop going, but there is the possibility for exceptions to be raised inside the loop. This of course would stop my program all together. To prevent that I catch the exceptions and handle them. But then the rest of the iteration runs even though an exception occurred. Is there a keyword to use in my except: clause to just skip the rest of the current iteration?
Python Solutions
Solution 1 - Python
You are looking for continue.
Solution 2 - Python
for i in iterator:
try:
# Do something.
pass
except:
# Continue to next iteration.
continue
Solution 3 - Python
Example for Continue:
number = 0
for number in range(10):
number = number + 1
if number == 5:
continue # continue here
print('Number is ' + str(number))
print('Out of loop')
Output:
Number is 1
Number is 2
Number is 3
Number is 4
Number is 6 # Note: 5 is skipped!!
Number is 7
Number is 8
Number is 9
Number is 10
Out of loop
Solution 4 - Python
Something like this?
for i in xrange( someBigNumber ):
try:
doSomethingThatMightFail()
except SomeException, e:
continue
doSomethingWhenNothingFailed()
Solution 5 - Python
I think you're looking for continue
Solution 6 - Python
For this specific use-case using try..except..else is the cleanest solution, the else clause will be executed if no exception was raised.
NOTE: The else clause must follow all except clauses
for i in iterator:
try:
# Do something.
except:
# Handle exception
else:
# Continue doing something