How to set the image from drawable dynamically in android?
AndroidAndroid Problem Overview
I am storing my project related images in drawable folder. Also I am storing the image names in string variable and dynamically I am trying to set those images to the imageview. But the image is not displaying. Please help me in this regard.
My Code:
int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName());
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(res);
In the above code "imagename" is the string variable which contains the image name.
Thanks in advance
Android Solutions
Solution 1 - Android
Try this:
String uri = "@drawable/myresource"; // where myresource (without the extension) is the file
int imageResource = getResources().getIdentifier(uri, null, getPackageName());
imageview= (ImageView)findViewById(R.id.imageView);
Drawable res = getResources().getDrawable(imageResource);
imageView.setImageDrawable(res);
Solution 2 - Android
Here i am setting the frnd_inactive
image from drawable
to the image
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageDrawable(getResources().getDrawable(R.drawable.frnd_inactive));
Solution 3 - Android
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(R.drawable.mydrawable);
Solution 4 - Android
Try this Dynamic code
String fnm = "cat"; // this is image file name
String PACKAGE_NAME = getApplicationContext().getPackageName();
int imgId = getResources().getIdentifier(PACKAGE_NAME+":drawable/"+fnm , null, null);
System.out.println("IMG ID :: "+imgId);
System.out.println("PACKAGE_NAME :: "+PACKAGE_NAME);
// Bitmap bitmap = BitmapFactory.decodeResource(getResources(),imgId);
your_image_view.setImageBitmap(BitmapFactory.decodeResource(getResources(),imgId));
In above code you will need Image-file-Name and Image-View object which both you are having.
Solution 5 - Android
See below code this is working for me
iv.setImageResource(getResources().getIdentifier(
"imagename", "drawable", "com.package.application"));
Solution 6 - Android
This works for me (dont use the extension of the image, just the name):
String imagename = "myImage";
int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName());
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(res);
Solution 7 - Android
Here is the best way that works in every phone at today. Most of those answer are deprecated or need an API >= 19 or 22. You can use the fragment code or the activity code depends what you need.
Fragment
//setting the bitmap from the drawable folder
Bitmap bitmap= BitmapFactory.decodeResource(getActivity().getResources(), R.drawable.my_image);
//set the image to the imageView
imageView.setImageBitmap(bitmap);
Activity
//setting the bitmap from the drawable folder
Bitmap bitmap= BitmapFactory.decodeResource(MyActivity.this.getResources(), R.drawable.my_image);
//set the image to the imageView
imageView.setImageBitmap(bitmap);
Cheers!
Solution 8 - Android
set in ImageView
like this : imageView.setImageResource(R.drawable.image)
Solution 9 - Android
imageView.setImageResource(R.drawable.picname);
Solution 10 - Android
getDrawable()
is deprecated, so try this
imageView.setImageResource(R.drawable.fileName)
Solution 11 - Android
First of let's your image name is myimage. So what you have to do is that go to Drawable and save the image name myimage.
Now assume you know only image name and you need to access it. Use below snippet to access it,
what you did is correct , ensure you saved image name you are going to use inside coding.
public static int getResourceId(Context context, String name, String resourceType) {
return context.getResources().getIdentifier(toResourceString(name), resourceType, context.getPackageName());
}
private static String toResourceString(String name) {
return name.replace("(", "")
.replace(")", "")
.replace(" ", "_")
.replace("-", "_")
.replace("'", "")
.replace("&", "")
.toLowerCase();
}
In addition to it you should ensure that there is no empty spaces and case sensitives
Solution 12 - Android
As of API 22, getResources().getDrawable()
is deprecated (see also https://stackoverflow.com/questions/29041027/android-getresources-getdrawable-deprecated-api-22). Here is a new way to set the image resource dynamically:
String resourceId = "@drawable/myResourceName"; // where myResourceName is the name of your resource file, minus the file extension
int imageResource = getResources().getIdentifier(resourceId, null, getPackageName());
Drawable drawable = ContextCompat.getDrawable(this, imageResource); // For API 21+, gets a drawable styled for theme of passed Context
imageview = (ImageView) findViewById(R.id.imageView);
imageview.setImageDrawable(drawable);
Solution 13 - Android
Here is how to do it in Kotlin, inside a loop i
:
Code reused from rfsbraz 's answer
val uri = "@drawable/pic_top${i+1}"
val imageResource = activity.resources.getIdentifier(uri, null, activity.packageName)
val res = activity.getResources().getDrawable(imageResource)
holder.view.imgDigit.setImageDrawable(res)
Solution 14 - Android
getDrawable() is deprecated. now you can use
imageView.setImageDrawable(ContextCompat.getDrawable(this,R.drawable.msg_status_client_read))
Solution 15 - Android
ImageView imageView=findViewById(R.id.imageView)
if you have image in drawable folder then use
imageView.setImageResource(R.drawable.imageView)
if you have uri and want to display it in imageView then use
imageView.setImageUri("uri")
if you have bitmap and want to display it in imageView then use
imageView.setImageBitmap(bitmap)
note:- 1. imageView.setImageDrawable()
is now deprecated in java
2. If image uri is from firebase or from any other online link then use
Picasso.get()
.load("uri")
.into(imageView)
(https://github.com/square/picasso)
or use
Glide.with(context)
.load("uri")
.into(imageView)
Solution 16 - Android
This works fine for me.
final R.drawable drawableResources = new R.drawable();
final Class<R.drawable> c = R.drawable.class;
final Field[] fields = c.getDeclaredFields();
for (int i=0; i < fields.length;i++)
{
resourceId[i] = fields[i].getInt(drawableResources);
/* till here you get all the images into the int array resourceId.*/
}
imageview= (ImageView)findViewById(R.id.imageView);
if(your condition)
{
imageview.setImageResource(resourceId[any]);
}
Solution 17 - Android
int[] phptr=new int[5];
adding image pointer to array
for(int lv=0;lv<3;lv++)
{
String id="a"+String.valueOf(lv+1);
phptr[lv]= getResources().getIdentifier(id, "drawable", getPackageName());
}
for(int loopvariable=0;loopvariable<3;loopvariable++)
{
et[loopvariable] = findViewById(p[loopvariable]);
}
for(int lv=0;lv<3;lv++)
{
et[k].setImageResource(phptr[k]);
}