As documented, you need to set the values of your InlineModelAdmin subclass:

InlineModelAdmin.verbose_name - 
An override to the verbose_name found in the model’s inner Meta class.

InlineModelAdmin.verbose_name_plural - 
An override to the verbose_name_plural found in the model’s inner Meta class.

In this example, instead of the title &#39;Device&#39; we use &#39;Phone&#39;:

    class DeviceInline(admin.TabularInline):
        model = Device
        verbose_name = &quot;Phone&quot;
        verbose_name_plural = &quot;My Phones&quot;


Here is what my solution is looking like at the moment:

![enter image description here][1]

In the Tutomentor.Branding project, I&#39;d like to save branding information in the App.config file, like names, colors, etc.

In the Tutomentor.Data project, the App.config was created when I added an entity .edmx model file.

Is this possible? Any recommendations?

When deploying, will the output COMBINE these App.config files into a single one?

  [1]: http://i.stack.imgur.com/9OpOZ.jpg

Can a class library have an App.config file?

I need to download a web page on an Android app and I am having a hard time deciding whether to use the Android Apache HTTP client or Java&#39;s URLConnection.

Any thoughts?




Apache HTTP client or URLConnection

I need to change the `inline title` to something else other than the `verbose_name` of the class Meta in the model. Is there an attribute to achieve this?



How to set another Inline title in Django Admin?

<p>I need to change the <code>inline title</code> to something else other than the <code>verbose_name</code> of the class Meta in the model. Is there an attribute to achieve this?</p>


&gt; **Possible Duplicates:**  
&gt; [clear terminal in python](https://stackoverflow.com/questions/2084508/clear-terminal-in-python)  
&gt; [How to clear python interpreter console?](https://stackoverflow.com/questions/517970/how-to-clear-python-interpreter-console)  

&lt;!-- End of automatically inserted text --&gt;

I&#39;m trying to write a program in Python but I don&#39;t know how to clear the screen.
I use both Windows and Linux and I use commands to clear the screen in those, but I don&#39;t know how to do it in Python.

How do I use Python to clear the screen?


how to clear the screen in python

I often use python to process directories of data. Recently, I have noticed that the default order of the lists has changed to something almost nonsensical. For example, if I am in a current directory containing the following subdirectories: run01, run02, ... run19, run20, and then I generate a list from the following command:

    dir = os.listdir(os.getcwd())

then I usually get a list in this order:

    dir = [&#39;run01&#39;, &#39;run18&#39;, &#39;run14&#39;, &#39;run13&#39;, &#39;run12&#39;, &#39;run11&#39;, &#39;run08&#39;, ... ]

and so on. The order used to be alphanumeric. But this new order has remained with me for a while now.

What is determining the (displayed) order of these lists?

Non-alphanumeric list order from os.listdir()

What is the difference between `subprocess.Popen()` and `os.system()`?

Difference between subprocess.Popen and os.system

I&#39;ve been reading the Python documentation about the subprocess module (see [here][1]) and it talks about a `subprocess.check_output()` command which seems to be exactly what I need.

However, when I try and use it I get an error that it doesn&#39;t exist, and when I run `dir(subprocess)` it is not listed.

I am running Python 2.6.5, and the code I have used is below:

    import subprocess
    subprocess.check_output([&quot;ls&quot;, &quot;-l&quot;, &quot;/dev/null&quot;])

Does anyone have any idea why this is happening?


  [1]: http://docs.python.org/library/subprocess.html#subprocess-replacements

subprocess.check_output() doesn&#39;t seem to exist (Python 2.6.5)

In python, I have to instantiate certain class, knowing its name in a string, but this class &#39;lives&#39; in a dynamically imported module. An example follows:

loader-class script:


    import sys
    class loader:
      def __init__(self, module_name, class_name): # both args are strings
        try:
          __import__(module_name)
          modul = sys.modules[module_name]
          instance = modul.class_name() # obviously this doesn&#39;t works, here is my main problem!
        except ImportError:
           # manage import error



some-dynamically-loaded-module script:

    class myName:
      # etc...

I use this arrangement to make any dynamically-loaded-module to be used by the loader-class following certain predefined behaviours in the dyn-loaded-modules...


Dynamic instantiation from string name of a class in dynamically imported module?

One of my view needs to add an item, along with other functionality, but I already have another view which specifically adds an item. 

Can I do something like:

    def specific_add_item_view(request):
        item = Item.objects.create(foo=request.bar)

    def big_view(request):
        # ...
        specific_add_item_view(request)

Can I call a view from within another view?

I need to perform a django query that checks if a field contains all values within a list. The list will be of varying length

Example

    User.objects.filter(first_name__contains=[&#39;x&#39;,&#39;y&#39;,&#39;z&#39;])

Django: Query using contains each value in a list

&lt;br&gt;I am trying to pass in url parameters to a django template like this...

    response = render_to_string(&#39;persistConTemplate.html&#39;, request.GET)

This the calling line from my views.py file.  persistConTemplate.html is the name of my template and request.GET is the dictionary that contains the url parameters.

In the template I try to use one of the parameters like this...

    {% for item in (numItems) %}

      item {{item}}

    {% endfor %}

numItems is one of the url parameters that I am sending in my request like this...

    http:/someDomain/persistentConTest.html/?numItems=12

When I try the for loop above, I get an output like this....
&gt;image 1 image 2

I am expecting and would like to see the word image printed 12 times...

&gt;image 1 image 2 image 3 image 4 image 5 image 6 image 7 image 8 image 9 image 10 image 11 image 12

Can anyone please tell me what I am going wrong?


Need to convert a string to int in a django template

First, I create my database.

    create database mydb;

I add &quot;south&quot; to installed Apps.  Then, I go to this tutorial:  http://south.aeracode.org/docs/tutorial/part1.html

The tutorial tells me to do this:

    $ py manage.py  schemamigration wall --initial
    &gt;&gt;&gt; Created 0001_initial.py. You can now apply this migration with: ./manage.py migrate wall

Great, now I migrate.

    $ py manage.py migrate wall

But it gives me this error...

    django.db.utils.DatabaseError: (1146, &quot;Table &#39;fable.south_migrationhistory&#39; doesn&#39;t exist&quot;)

So I use Google (which never works. hence my 870 questions asked on Stackoverflow), and I get this page: http://groups.google.com/group/south-users/browse_thread/thread/d4c83f821dd2ca1c

Alright, so I follow that instructions

    &gt;&gt; Drop database mydb;
    &gt;&gt; Create database mydb;
    $ rm -rf ./wall/migrations
    $ py manage.py syncdb

But when I run syncdb, Django creates a bunch of tables. Yes, it creates the south_migrationhistory table, but **it also creates my app&#39;s tables.**


    Synced:
     &gt; django.contrib.admin
     &gt; django.contrib.auth
     &gt; django.contrib.contenttypes
     &gt; django.contrib.sessions
     &gt; django.contrib.sites
     &gt; django.contrib.messages
     &gt; south
     &gt; fable.notification
     &gt; pagination
     &gt; timezones
     &gt; fable.wall
     &gt; mediasync
     &gt; staticfiles
     &gt; debug_toolbar
    
    Not synced (use migrations):
     - 
    (use ./manage.py migrate to migrate these)

Cool....now it tells me to migrate these.  So, I do this:

    $ py manage.py  migrate wall
    The app &#39;wall&#39; does not appear to use migrations.

Alright, so fine. I&#39;ll add wall to initial migrations.

    $ py manage.py schemamigration wall --initial

Then I migrate:

    $ py manage.py migrate wall

You know what? It gives me this BS:

    _mysql_exceptions.OperationalError: (1050, &quot;Table &#39;wall_content&#39; already exists&quot;)


Sorry, this is really pissing me off. Can someone help ? thanks.

How do I get South to work and sync correctly with everything? The only thing I can think of is remove my app from INSTALLED_APPS, then run syncdb, then add it back on.

**That is SO SILLY.**

Why don&#39;t my south migrations work?

I use the &#39;messages&#39; interface to pass messages to user like this:

    request.user.message_set.create(message=message)

I would like to include html in my `{{ message }}` variable and render it without escaping the markup in the template.

Rendering a template variable as HTML

Let&#39;s say I am in the save code. How can I obtain the model&#39;s name or the content type of the object, and use it?

    from django.db import models

    class Foo(models.Model):
        ...
        def save(self):
            I am here....I want to obtain the model_name or the content type of the object

This code works, but I have to know the model_name:

    import django.db.models
    from django.contrib.contenttypes.models import ContentType

    content_type = ContentType.objects.get(model=model_name)
    model = content_type.model_class()

How can I obtain the model&#39;s name or the content type of a Django object?

In Django, you can specify relationships like:

    author = ForeignKey(&#39;Person&#39;)

And then internally it has to convert the string &quot;Person&quot; into the model `Person`. 

Where&#39;s the function that does this? I want to use it, but I can&#39;t find it.

Django: Get model from string?

Often I find myself wanting to get the first object from a queryset in Django, or return `None` if there aren&#39;t any.  There are lots of ways to do this which all work.  But I&#39;m wondering which is the most performant.

    qs = MyModel.objects.filter(blah = blah)
    if qs.count() &gt; 0:
        return qs[0]
    else:
        return None

Does this result in two database calls?  That seems wasteful.  Is this any faster? 

    qs = MyModel.objects.filter(blah = blah)
    if len(qs) &gt; 0:
        return qs[0]
    else:
        return None

Another option would be:

    qs = MyModel.objects.filter(blah = blah)
    try:
        return qs[0]
    except IndexError:
        return None

This generates a single database call, which is good.  But requires creating an exception object a lot of the time, which is a very memory-intensive thing to do when all you really need is a trivial if-test.

How can I do this with just a single database call and without churning memory with exception objects?


Fastest way to get the first object from a queryset in django?

I am using `BooleanField` in Django.

By default, the checkbox generated by it is unchecked state. I want the state to be checked by default. How do I do that?

How to set True as default value for BooleanField on Django?

How does one change the &#39;Django administration&#39; text in the django admin header?

It doesn&#39;t seem to be covered in the &quot;Customizing the admin&quot; documentation.

Django Admin - change header &#39;Django administration&#39; text

I find the the Django Admin&#39;s default `models.ManyToManyField` widget to be cumbersome to use. It&#39;s the [HTML select](http://www.htmlcodetutorial.com/forms/_SELECT_MULTIPLE.html) element and if you have a lot of Objects of the &quot;other&quot; model then it&#39;s quite impractical to actually find the &quot;other&quot; Objects you want to associate with &quot;this&quot; Object. And if you have ***a lot*** of objects of the &quot;other&quot; model it seems to even slows down the rendering of the Admin page.

I&#39;m aware that I can build my own custom admin widget and apply it to my `ManyToManyFields` as I see fit, but are there any pre-built ones out there that I might use instead? In my dreams, I picture an auto-completing text input HTML widget. Is this even practical/possible to do in the Django admin framework?

Thanks.

A Better Django Admin ManyToMany Field Widget

If, for a field that you want to filter by, you have more than ~10 values, the filtering sidebar starts to be ugly and harder to use.

I&#39;m looking for a solution to replace the `&lt;li&gt;` with a dropdown selection (combobox) or something similar that will solve the same problem.

How to change the Django admin filter to use a dropdown instead of list?

I have a standard many-to-one relationship set up. There are a bunch of fields, but for our purposes here, the relevant model is:

    class Class(models.Model):
        name = models.CharField(max_length=128)
    
    class Student(models.Model):
        class = models.ForeignKey(Class)
        name = models.CharField(max_length=128)
        address = models.CharField(max_length=128)
        # ...etc

I created an admin, and it works great. it even automatically has the ability for me to set the Class when I am editing a Student. However, when I go to create/edit a Class, all I get is an input box for the name.

Is there a way to add a box/field where Students can be added as members of Class from the Class admin page? I can make a form inline, but that is to create new Students. I already have all my Students created and am just looking for a quick method to add multiple existing Students to different Class&#39;.

one-to-many inline select with django admin

How to add hint for the form field in django admin like in next example?

![form field description in django admin][1]


  [1]: http://i.stack.imgur.com/nciDr.png

(here: **URL** and **Content** descriptions are shown with gray color under field)

Content Type	Original Author	Original Content on Stackoverflow
Question	eos87	View Question on Stackoverflow
Solution 1 - Python	odedfos	View Answer on Stackoverflow

How to set another Inline title in Django Admin?

Python Problem Overview

Python Solutions

Solution 1 - Python

Apache HTTP client or URLConnection

Can a class library have an App.config file?

Attributions