How to send POST request?

Urllib Problem Overview

I found this script online:

import httplib, urllib
params = urllib.urlencode({'number': 12524, 'type': 'issue', 'action': 'show'})
headers = {"Content-type": "application/x-www-form-urlencoded",
            "Accept": "text/plain"}
conn = httplib.HTTPConnection("bugs.python.org")
conn.request("POST", "", params, headers)
response = conn.getresponse()
print response.status, response.reason
302 Found
data = response.read()
data
'Redirecting to <a href="http://bugs.python.org/issue12524">http://bugs.python.org/issue12524</a>'
conn.close()

But I don't understand how to use it with PHP or what everything inside the params variable is or how to use it. Can I please have a little help with trying to get this to work?

Urllib Solutions

Solution 1 - Urllib

If you really want to handle with HTTP using Python, I highly recommend Requests: HTTP for Humans. The POST quickstart adapted to your question is:

>>> import requests
>>> r = requests.post("http://bugs.python.org", data={'number': 12524, 'type': 'issue', 'action': 'show'})
>>> print(r.status_code, r.reason)
200 OK
>>> print(r.text[:300] + '...')

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title>
Issue 12524: change httplib docs POST example - Python tracker

</title>
<link rel="shortcut i...
>>>

Solution 2 - Urllib

This is a solution without any external pip dependencies, but works only in Python 3+ (Python 2 won't work):

from urllib.parse import urlencode
from urllib.request import Request, urlopen

url = 'https://httpbin.org/post' # Set destination URL here
post_fields = {'foo': 'bar'}     # Set POST fields here

request = Request(url, urlencode(post_fields).encode())
json = urlopen(request).read().decode()
print(json)

Sample output:

{
  "args": {}, 
  "data": "", 
  "files": {}, 
  "form": {
    "foo": "bar"
  }, 
  "headers": {
    "Accept-Encoding": "identity", 
    "Content-Length": "7", 
    "Content-Type": "application/x-www-form-urlencoded", 
    "Host": "httpbin.org", 
    "User-Agent": "Python-urllib/3.3"
  }, 
  "json": null, 
  "origin": "127.0.0.1", 
  "url": "https://httpbin.org/post"
}

Solution 3 - Urllib

You can't achieve POST requests using urllib (only for GET), instead try using requests module, e.g.:

Example 1.0:

import requests

base_url="www.server.com"
final_url="/{0}/friendly/{1}/url".format(base_url,any_value_here)

payload = {'number': 2, 'value': 1}
response = requests.post(final_url, data=payload)

print(response.text) #TEXT/HTML
print(response.status_code, response.reason) #HTTP

Example 1.2:

>>> import requests

>>> payload = {'key1': 'value1', 'key2': 'value2'}

>>> r = requests.post("http://httpbin.org/post", data=payload)
>>> print(r.text)
{
  ...
  "form": {
    "key2": "value2",
    "key1": "value1"
  },
  ...
}

Example 1.3:

>>> import json

>>> url = 'https://api.github.com/some/endpoint'
>>> payload = {'some': 'data'}

>>> r = requests.post(url, data=json.dumps(payload))

Solution 4 - Urllib

Use requests library to GET, POST, PUT or DELETE by hitting a REST API endpoint. Pass the rest api endpoint url in url, payload(dict) in data and header/metadata in headers

import requests, json

url = "bugs.python.org"

payload = {"number": 12524, 
           "type": "issue", 
           "action": "show"}

header = {"Content-type": "application/x-www-form-urlencoded",
          "Accept": "text/plain"} 

response_decoded_json = requests.post(url, data=payload, headers=header)
response_json = response_decoded_json.json()
 
print(response_json)

Solution 5 - Urllib

Your data dictionary conteines names of form input fields, you just keep on right their values to find results. form view Header configures browser to retrieve type of data you declare. With requests library it's easy to send POST:

import requests

url = "https://bugs.python.org"
data = {'@number': 12524, '@type': 'issue', '@action': 'show'}
headers = {"Content-type": "application/x-www-form-urlencoded", "Accept":"text/plain"}
response = requests.post(url, data=data, headers=headers)

print(response.text)

More about Request object: https://requests.readthedocs.io/en/master/api/

Solution 6 - Urllib

If you don't want to use a module you have to install like requests, and your use case is very basic, then you can use urllib2

urllib2.urlopen(url, body)

See the documentation for urllib2 here: https://docs.python.org/2/library/urllib2.html.

Solution 7 - Urllib

You can use the request library to make a post request. If you have a JSON string in the payload you can use json.dumps(payload) which is the expected form of payload.


    import requests, json
    url = "http://bugs.python.org/test"
    payload={
        "data1":1234,'data2':'test'
    }
    headers = {
        'Content-Type': 'application/json'
    }
    response = requests.post(url, headers=headers, data=json.dumps(payload))
    print(response.text , response.status_code)

Content Type	Original Author	Original Content on Stackoverflow
Question	user1113569	View Question on Stackoverflow
Solution 1 - Urllib	user816328	View Answer on Stackoverflow
Solution 2 - Urllib	stil	View Answer on Stackoverflow
Solution 3 - Urllib	d1jhoni1b	View Answer on Stackoverflow
Solution 4 - Urllib	Pranzell	View Answer on Stackoverflow
Solution 5 - Urllib	Anastasia Didan	View Answer on Stackoverflow
Solution 6 - Urllib	Phil	View Answer on Stackoverflow
Solution 7 - Urllib	Nkgupta	View Answer on Stackoverflow