How to save MailMessage object to disk as *.eml or *.msg file

C#.NetEmailMailmessageEml

C# Problem Overview


How do I save MailMessage object to the disk? The MailMessage object does not expose any Save() methods.

I dont have a problem if it saves in any format, *.eml or *.msg. Any idea how to do this?

C# Solutions


Solution 1 - C#

For simplicity, I'll just quote an explanation from a Connect item:

> You can actually configure the > SmtpClient to send emails to the file > system instead of the network. You can > do this programmatically using the > following code: > > SmtpClient client = new SmtpClient("mysmtphost"); > client.DeliveryMethod = SmtpDeliveryMethod.SpecifiedPickupDirectory; > client.PickupDirectoryLocation = @"C:\somedirectory"; > client.Send(message); > > You can also set this up in your > application configuration file like > this:

 <configuration>
     <system.net>
         <mailSettings>
             <smtp deliveryMethod="SpecifiedPickupDirectory">
                 <specifiedPickupDirectory pickupDirectoryLocation="C:\somedirectory" />
             </smtp>
         </mailSettings>
     </system.net>
 </configuration>

> > After sending the email, you should > see email files get added to the > directory you specified. You can then > have a separate process send out the > email messages in batch mode.

You should be able to use the empty constructor instead of the one listed, as it won't be sending it anyway.

Solution 2 - C#

Here's an extension method to convert a MailMessage to a stream containing the EML data. Its obviously a bit of a hack as it uses the file system, but it works.

public static void SaveMailMessage(this MailMessage msg, string filePath)
{
    using (var fs = new FileStream(filePath, FileMode.Create))
    {
        msg.ToEMLStream(fs);
    }
}

/// <summary>
/// Converts a MailMessage to an EML file stream.
/// </summary>
/// <param name="msg"></param>
/// <returns></returns>
public static void ToEMLStream(this MailMessage msg, Stream str)
{
    using (var client = new SmtpClient())
    {
        var id = Guid.NewGuid();

        var tempFolder = Path.Combine(Path.GetTempPath(), Assembly.GetExecutingAssembly().GetName().Name);

        tempFolder = Path.Combine(tempFolder, "MailMessageToEMLTemp");

        // create a temp folder to hold just this .eml file so that we can find it easily.
        tempFolder = Path.Combine(tempFolder, id.ToString());

        if (!Directory.Exists(tempFolder))
        {
            Directory.CreateDirectory(tempFolder);
        }

        client.UseDefaultCredentials = true;
        client.DeliveryMethod = SmtpDeliveryMethod.SpecifiedPickupDirectory;
        client.PickupDirectoryLocation = tempFolder;
        client.Send(msg);

        // tempFolder should contain 1 eml file

        var filePath = Directory.GetFiles(tempFolder).Single();

        // stream out the contents
        using (var fs = new FileStream(filePath, FileMode.Open))
        {
            fs.CopyTo(str);
        }
        
        if (Directory.Exists(tempFolder))
        {
            Directory.Delete(tempFolder, true);
        }
    }
}

You can then take the stream thats returned and do as you want with it, including saving to another location on disk or storing in a database field, or even emailing as an attachment.

Solution 3 - C#

If you are using Mailkit. Just write below code

string fileName = "your filename full path";
MimeKit.MimeMessage message = CreateMyMessage ();
message.WriteTo(fileName);

Solution 4 - C#

With the help of community I came up with an solution for .NET 5. I have combined this old solution with suggestions in this post and got inspired by Mailkit which resulted in nice extension method without unnecessary dependencies

public static class MailMessageHelper
{
    public static void WriteTo(this MailMessage mail, Stream stream)
    {
        Assembly assembly = typeof(SmtpClient).Assembly;
        Type _mailWriterType = assembly.GetType("System.Net.Mail.MailWriter");

        // Get reflection info for MailWriter contructor
        ConstructorInfo _mailWriterConstructor =
            _mailWriterType.GetConstructor(
                BindingFlags.Instance | BindingFlags.NonPublic,
                null,
                new Type[] { typeof(Stream), typeof(bool) },
                null);

        // Construct MailWriter object with our FileStream
        object _mailWriter =
          _mailWriterConstructor.Invoke(new object[] { stream, true });

        // Get reflection info for Send() method on MailMessage
        MethodInfo _sendMethod =
            typeof(MailMessage).GetMethod(
                "Send",
                BindingFlags.Instance | BindingFlags.NonPublic);

        // Call method passing in MailWriter
        _sendMethod.Invoke(
            mail,
            BindingFlags.Instance | BindingFlags.NonPublic,
            null,
            new object[] { _mailWriter, true, true },
            null);

        // Finally get reflection info for Close() method on our MailWriter
        MethodInfo _closeMethod =
            _mailWriter.GetType().GetMethod(
                "Close",
                BindingFlags.Instance | BindingFlags.NonPublic);

        // Call close method
        _closeMethod.Invoke(
            _mailWriter,
            BindingFlags.Instance | BindingFlags.NonPublic,
            null,
            Array.Empty<object>(),
            null);
    }
}

Usage

MailMessage mail = new(mailFrom, mailTo, mailSubject, mailContent);
mail.WriteTo(new FileStream(@"path_to_file\new_mail.eml", FileMode.Create));

Also if you are using MemoryStream and want to get result in string, just change the return type of the extension method and at the end write

return Encoding.ASCII.GetString(stream.ToArray());

Enjoy

Solution 5 - C#

For one reason or another the client.send failed (right after an actual send using that method) so I plugged in good 'ole CDO and ADODB stream. I also had to load CDO.message with a template.eml before setting the .Message values. But it works.

Since the above one is C here is one for VB

    MyMessage.From = New Net.Mail.MailAddress(mEmailAddress)
    MyMessage.To.Add(mToAddress)
    MyMessage.Subject = mSubject
    MyMessage.Body = mBody

    Smtp.Host = "------"
    Smtp.Port = "2525"
    Smtp.Credentials = New NetworkCredential(------)

    Smtp.Send(MyMessage)		' Actual Send

    Dim oldCDO As CDO.Message
    oldCDO = MyLoadEmlFromFile("template.eml")  ' just put from, to, subject blank. leave first line blank
    oldCDO.To = mToAddress
    oldCDO.From = mEmailAddress
    oldCDO.Subject = mSubject
    oldCDO.TextBody = mBody
    oldCDO.HTMLBody = mBody
    oldCDO.GetStream.Flush()
    oldCDO.GetStream.SaveToFile(yourPath)

Solution 6 - C#

try this

please use these 2 reference ( using MailBee;) ( using MailBee.Mime;)

    public static string load(string to,string from,string cc,string bcc,string subject,string body, List<string> reportList,string path, bool HtmlbodyType)
    {
        try
        {
            MailBee.Mime.MailMessage msg = new MailBee.Mime.MailMessage();
            msg.From.AsString = from;
            msg.Subject = subject;
            if (HtmlbodyType == true)
            {
                msg.BodyHtmlText = body;
            }
            else
            {
                msg.BodyPlainText = body;
            }
            
            string[] receptionEmail = to.Split(new string[] { ",", ";" }, StringSplitOptions.RemoveEmptyEntries);
            string[] ccEmail = cc.Split(new string[] { ",", ";" }, StringSplitOptions.RemoveEmptyEntries);
            string[] bccEmail = bcc.Split(new string[] { ",", ";" }, StringSplitOptions.RemoveEmptyEntries);
            string message = "";
            foreach (string To in receptionEmail)
            {
                msg.To.Add(To);
            }
            foreach (string CC in ccEmail)
            {
                    msg.Cc.Add(CC);
            }
            foreach (string Bcc in bccEmail)
            {
                    msg.Bcc.Add(Bcc);

            }
                for (int x = 0; x < reportList.Count; x++)
                {
                    string fileName = reportList[x];
                    msg.Attachments.Add(fileName);
                }

                msg.SaveMessage(path);
                return "Success";
            
        }
        catch (Exception ex)
        {
            return ex.Message;
        }

    }

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionashwnacharyaView Question on Stackoverflow
Solution 1 - C#Ryan VersawView Answer on Stackoverflow
Solution 2 - C#sailleView Answer on Stackoverflow
Solution 3 - C#NaveenView Answer on Stackoverflow
Solution 4 - C#B8ightYView Answer on Stackoverflow
Solution 5 - C#Gregory WayView Answer on Stackoverflow
Solution 6 - C#Mohamed HusamaView Answer on Stackoverflow