How to replace a set of tokens in a Java String?
JavaRegexTemplatesJava Problem Overview
I have the following template String: "Hello [Name] Please find attached [Invoice Number] which is due on [Due Date]"
.
I also have String variables for name, invoice number and due date - what's the best way to replace the tokens in the template with the variables?
(Note that if a variable happens to contain a token it should NOT be replaced).
EDIT
With thanks to @laginimaineb and @alan-moore, here's my solution:
public static String replaceTokens(String text,
Map<String, String> replacements) {
Pattern pattern = Pattern.compile("\\[(.+?)\\]");
Matcher matcher = pattern.matcher(text);
StringBuffer buffer = new StringBuffer();
while (matcher.find()) {
String replacement = replacements.get(matcher.group(1));
if (replacement != null) {
// matcher.appendReplacement(buffer, replacement);
// see comment
matcher.appendReplacement(buffer, "");
buffer.append(replacement);
}
}
matcher.appendTail(buffer);
return buffer.toString();
}
Java Solutions
Solution 1 - Java
I really don't think you need to use a templating engine or anything like that for this. You can use the String.format
method, like so:
String template = "Hello %s Please find attached %s which is due on %s";
String message = String.format(template, name, invoiceNumber, dueDate);
Solution 2 - Java
The most efficient way would be using a matcher to continually find the expressions and replace them, then append the text to a string builder:
Pattern pattern = Pattern.compile("\\[(.+?)\\]");
Matcher matcher = pattern.matcher(text);
HashMap<String,String> replacements = new HashMap<String,String>();
//populate the replacements map ...
StringBuilder builder = new StringBuilder();
int i = 0;
while (matcher.find()) {
String replacement = replacements.get(matcher.group(1));
builder.append(text.substring(i, matcher.start()));
if (replacement == null)
builder.append(matcher.group(0));
else
builder.append(replacement);
i = matcher.end();
}
builder.append(text.substring(i, text.length()));
return builder.toString();
Solution 3 - Java
Unfortunately the comfortable method String.format mentioned above is only available starting with Java 1.5 (which should be pretty standard nowadays, but you never know). Instead of that you might also use Java's class MessageFormat for replacing the placeholders.
It supports placeholders in the form '{number}', so your message would look like "Hello {0} Please find attached {1} which is due on {2}". These Strings can easily be externalized using ResourceBundles (e. g. for localization with multiple locales). The replacing would be done using the static'format' method of class MessageFormat:
String msg = "Hello {0} Please find attached {1} which is due on {2}";
String[] values = {
"John Doe", "invoice #123", "2009-06-30"
};
System.out.println(MessageFormat.format(msg, values));
Solution 4 - Java
You could try using a templating library like Apache Velocity.
Here is an example:
import org.apache.velocity.VelocityContext;
import org.apache.velocity.app.Velocity;
import java.io.StringWriter;
public class TemplateExample {
public static void main(String args[]) throws Exception {
Velocity.init();
VelocityContext context = new VelocityContext();
context.put("name", "Mark");
context.put("invoiceNumber", "42123");
context.put("dueDate", "June 6, 2009");
String template = "Hello $name. Please find attached invoice" +
" $invoiceNumber which is due on $dueDate.";
StringWriter writer = new StringWriter();
Velocity.evaluate(context, writer, "TemplateName", template);
System.out.println(writer);
}
}
The output would be:
Hello Mark. Please find attached invoice 42123 which is due on June 6, 2009.
Solution 5 - Java
You can use template library for complex template replacement.
FreeMarker is a very good choice.
http://freemarker.sourceforge.net/
But for simple task, there is a simple utility class can help you.
org.apache.commons.lang3.text.StrSubstitutor
It is very powerful, customizable, and easy to use.
> This class takes a piece of text and substitutes all the variables > within it. The default definition of a variable is ${variableName}. > The prefix and suffix can be changed via constructors and set methods. > > Variable values are typically resolved from a map, but could also be > resolved from system properties, or by supplying a custom variable > resolver.
For example, if you want to substitute system environment variable into a template string, here is the code:
public class SysEnvSubstitutor {
public static final String replace(final String source) {
StrSubstitutor strSubstitutor = new StrSubstitutor(
new StrLookup<Object>() {
@Override
public String lookup(final String key) {
return System.getenv(key);
}
});
return strSubstitutor.replace(source);
}
}
Solution 6 - Java
System.out.println(MessageFormat.format("Hello {0}! You have {1} messages", "Join",10L));
Output: Hello Join! You have 10 messages"
Solution 7 - Java
It depends of where the actual data that you want to replace is located. You might have a Map like this:
Map<String, String> values = new HashMap<String, String>();
containing all the data that can be replaced. Then you can iterate over the map and change everything in the String as follows:
String s = "Your String with [Fields]";
for (Map.Entry<String, String> e : values.entrySet()) {
s = s.replaceAll("\\[" + e.getKey() + "\\]", e.getValue());
}
You could also iterate over the String and find the elements in the map. But that is a little bit more complicated because you need to parse the String searching for the []. You could do it with a regular expression using Pattern and Matcher.
Solution 8 - Java
String.format("Hello %s Please find attached %s which is due on %s", name, invoice, date)
Solution 9 - Java
My solution for replacing ${variable} style tokens (inspired by the answers here and by the Spring UriTemplate):
public static String substituteVariables(String template, Map<String, String> variables) {
Pattern pattern = Pattern.compile("\\$\\{(.+?)\\}");
Matcher matcher = pattern.matcher(template);
// StringBuilder cannot be used here because Matcher expects StringBuffer
StringBuffer buffer = new StringBuffer();
while (matcher.find()) {
if (variables.containsKey(matcher.group(1))) {
String replacement = variables.get(matcher.group(1));
// quote to work properly with $ and {,} signs
matcher.appendReplacement(buffer, replacement != null ? Matcher.quoteReplacement(replacement) : "null");
}
}
matcher.appendTail(buffer);
return buffer.toString();
}
Solution 10 - Java
With Apache Commons Library, you can simply use Stringutils.replaceEach:
public static String replaceEach(String text,
String[] searchList,
String[] replacementList)
From the documentation:
> Replaces all occurrences of Strings within another String. > > A null reference passed to this method is a no-op, or if any "search > string" or "string to replace" is null, that replace will be ignored. > This will not repeat. For repeating replaces, call the overloaded > method.
StringUtils.replaceEach(null, *, *) = null
StringUtils.replaceEach("", *, *) = ""
StringUtils.replaceEach("aba", null, null) = "aba"
StringUtils.replaceEach("aba", new String[0], null) = "aba"
StringUtils.replaceEach("aba", null, new String[0]) = "aba"
StringUtils.replaceEach("aba", new String[]{"a"}, null) = "aba"
StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}) = "b"
StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}) = "aba"
StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}) = "wcte"
(example of how it does not repeat)
StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}) = "dcte"
Solution 11 - Java
You can use Apache Commons StringSubstitutor:
For example:
// Build map
Map<String, String> valuesMap = new HashMap<>();
valuesMap.put("animal", "quick brown fox");
valuesMap.put("target", "lazy dog");
String templateString = "The ${animal} jumped over the ${target}.";
// Build StringSubstitutor
StringSubstitutor sub = new StringSubstitutor(valuesMap);
// Replace
String resolvedString = sub.replace(templateString);
yielding:
"The quick brown fox jumped over the lazy dog."
You can also customize the prefix and suffix delimiters (${
and }
respectively in the example above) by using:
You can also specify a default value using syntax like below:
String templateString = "The ${animal:giraffe} jumped over the ${target}.";
which would yield "The giraffe jumped over the lazy dog."
when no animal
parameter was supplied.
Solution 12 - Java
Solution 13 - Java
FYI
In the new language Kotlin, you can use "String Templates" in your source code directly, no 3rd party library or template engine need to do the variable replacement.
It is a feature of the language itself.
See: https://kotlinlang.org/docs/reference/basic-types.html#string-templates
Solution 14 - Java
In the past, I've solved this kind of problem with StringTemplate and Groovy Templates.
Ultimately, the decision of using a templating engine or not should be based on the following factors:
- Will you have many of these templates in the application?
- Do you need the ability to modify the templates without restarting the application?
- Who will be maintaining these templates? A Java programmer or a business analyst involved on the project?
- Will you need to the ability to put logic in your templates, like conditional text based on values in the variables?
- Will you need the ability to include other templates in a template?
If any of the above applies to your project, I would consider using a templating engine, most of which provide this functionality, and more.
Solution 15 - Java
I used
String template = "Hello %s Please find attached %s which is due on %s";
String message = String.format(template, name, invoiceNumber, dueDate);
Solution 16 - Java
The following replaces variables of the form <<VAR>>
, with values looked up from a Map. You can test it online here
For example, with the following input string
BMI=(<<Weight>>/(<<Height>>*<<Height>>)) * 70
Hi there <<Weight>> was here
and the following variable values
Weight, 42
Height, HEIGHT 51
outputs the following
BMI=(42/(HEIGHT 51*HEIGHT 51)) * 70
Hi there 42 was here
Here's the code
static Pattern pattern = Pattern.compile("<<([a-z][a-z0-9]*)>>", Pattern.CASE_INSENSITIVE);
public static String replaceVarsWithValues(String message, Map<String,String> varValues) {
try {
StringBuffer newStr = new StringBuffer(message);
int lenDiff = 0;
Matcher m = pattern.matcher(message);
while (m.find()) {
String fullText = m.group(0);
String keyName = m.group(1);
String newValue = varValues.get(keyName)+"";
String replacementText = newValue;
newStr = newStr.replace(m.start() - lenDiff, m.end() - lenDiff, replacementText);
lenDiff += fullText.length() - replacementText.length();
}
return newStr.toString();
} catch (Exception e) {
return message;
}
}
public static void main(String args[]) throws Exception {
String testString = "BMI=(<<Weight>>/(<<Height>>*<<Height>>)) * 70\n\nHi there <<Weight>> was here";
HashMap<String,String> values = new HashMap<>();
values.put("Weight", "42");
values.put("Height", "HEIGHT 51");
System.out.println(replaceVarsWithValues(testString, values));
}
and although not requested, you can use a similar approach to replace variables in a string with properties from your application.properties file, though this may already be being done:
private static Pattern patternMatchForProperties =
Pattern.compile("[$][{]([.a-z0-9_]*)[}]", Pattern.CASE_INSENSITIVE);
protected String replaceVarsWithProperties(String message) {
try {
StringBuffer newStr = new StringBuffer(message);
int lenDiff = 0;
Matcher m = patternMatchForProperties.matcher(message);
while (m.find()) {
String fullText = m.group(0);
String keyName = m.group(1);
String newValue = System.getProperty(keyName);
String replacementText = newValue;
newStr = newStr.replace(m.start() - lenDiff, m.end() - lenDiff, replacementText);
lenDiff += fullText.length() - replacementText.length();
}
return newStr.toString();
} catch (Exception e) {
return message;
}
}