What about simply:

    File.rename(f, folder_path + &quot;/&quot; + filename.capitalize + File.extname(f))


Doesn&#39;t the folder_path have to be part of the filename?

    puts &quot;Renaming files...&quot;
    
    folder_path = &quot;/home/papuccino1/Desktop/Test/&quot;
    Dir.glob(folder_path + &quot;*&quot;).sort.each do |f|
      filename = File.basename(f, File.extname(f))
      File.rename(f, folder_path + filename.capitalize + File.extname(f))
    end
    
    puts &quot;Renaming complete.&quot;

edit: it appears Mat is giving the same answer as I, only in a slightly different way.

If you&#39;re running in the same location as the file you want to change

    File.rename(&quot;test.txt&quot;, &quot;hope.txt&quot;)

Though honestly, I sometimes I don&#39;t see the point in using ruby at all...no need probably so long as your filenames are simply interpreted in the shell:

    `mv test.txt hope.txt`


If you are on a linux file system you could try `mv #{filename} newname`

You can also use File.rename(old,new) 

Don&#39;t use this pattern unless you are ready to put proper quoting around filenames:

    `mv test.txt hope.txt`

Indeed, suppose instead of &quot;hope.txt&quot; you have a file called &quot;foo the bar.txt&quot;, the result will not be what you expect.




How do I modify this:

    for /f %%a IN (&#39;dir /b /s build\release\*.dll&#39;) do echo &quot;%%a&quot;

to work when the path contains spaces?

For example, if this is run from

    c:\my folder with spaces

it will echo:

    c:\my

Thanks

batch file for loop with spaces in dir name

When designing an API for our web app, we&#39;ll use the their subdomain as the &#39;username&#39; and generate an API key/shared secret. Firstly, is it ok to use the subdomain as the username? I don&#39;t see the benefit of generating another key.

Different APIs seem to do one of two things:

1. **Use HTTP Basic Authentication with SSL**

In every request the username is set to the subdomain and the password to the API key. Since we&#39;re using SSL then this should be safe from spoofing.

Notable APIs: **[Google Checkout][1], [Freshbooks][2], [GitHub][3], [Zendesk][4]**

2. **Create a Signature of the Request with the Shared Secret**

Normally achieved by ordering the key/value pairs and using HMAC-SHA1 with the shared secret to generate the signature. The signature is then sent with the request and verified at the other end.

Notable APIs: **[Google Checkout][5], [Amazon AWS][6]**

PS: thats no mistake, Google Checkout supports both

**Edit:** Just read that OAuth 2 is dropping signatures in favour of sending a username/password via SSL.

Any opinions from anyone on what to pick: SSL vs Signature?


  [1]: http://checkout.google.com/support/sell/bin/answer.py?hl=en&amp;answer=57519
  [2]: http://developers.freshbooks.com/
  [3]: http://develop.github.com/p/general.html
  [4]: http://www.zendesk.com/api/rest-introduction
  [5]: http://checkout.google.com/support/sell/bin/answer.py?hl=en&amp;answer=57519
  [6]: http://docs.amazonwebservices.com/AmazonS3/latest/dev/index.html?RESTAuthentication.html

Securing an API: SSL &amp; HTTP Basic Authentication vs Signature

Here&#39;s my .rb file:

    puts &quot;Renaming files...&quot;
    
    folder_path = &quot;/home/papuccino1/Desktop/Test&quot;
    Dir.glob(folder_path + &quot;/*&quot;).sort.each do |f|
    	filename = File.basename(f, File.extname(f))
    	File.rename(f, filename.capitalize + File.extname(f))
    end
    
    puts &quot;Renaming complete.&quot;

The files are moved from their initial directory to where the .rb file is located. I&#39;d like to rename the files on the spot, without moving them.

Any suggestions on what to do?



How to rename a file in Ruby?

Here's my .rb file:
<pre><code class="hljs language-arduino">puts "Renaming files..."

folder_path = "/home/papuccino1/Desktop/Test"
Dir.glob(folder_path + "/*").sort.each do |f|
	filename = File.basename(f, File.extname(f))
	File.rename(f, filename.capitalize + File.extname(f))
end

puts "Renaming complete."
</code></pre>
The files are moved from their initial directory to where the .rb file is located. I'd like to rename the files on the spot, without moving them.
Any suggestions on what to do?

Which one is best for streaming and file downloads?

Please provide examples.

What is the difference between send_data and send_file in Ruby on Rails?

What are all the common ways to read a file in Ruby?

For instance, here is one method:

    fileObj = File.new($fileName, &quot;r&quot;)
    while (line = fileObj.gets)
      puts(line)
    end
    fileObj.close

I know Ruby is extremely flexible. What are the benefits/drawbacks of each approach?

What are all the common ways to read a file in Ruby?

If I&#39;m in a URL such as 

    http://domain.com/mysite/bla

How can I request just the URL with no paths? Such as
    
    http://domain.com 


In Rails, how to get current url (but no paths)

I have a coworker who is actively trying to convince me that I should not use do..end and instead use curly braces for defining multiline blocks in Ruby.

I&#39;m firmly in the camp of only using curly braces for short one-liners and do..end for everything else. But I thought I would reach out to the greater community to get some resolution.

So which is it, and why? (Example of some shoulda code)

    context do
      setup { do_some_setup() }
      should &quot;do somthing&quot; do
        # some more code...
      end
    end

or

    context {
      setup { do_some_setup() }
      should(&quot;do somthing&quot;) {
        # some more code...
      }
    }

Personally, just looking at the above answers the question for me, but I wanted to open this up to the greater community.


do..end vs curly braces for blocks in Ruby

I&#39;m looking for a  way to suppress Ruby warnings when I run my specs.

    spec spec/models/account_spec.rb

I receive warnings such as:

    DEPRECATION WARNING: ActiveSupport::Dependencies.load_paths is deprecated, ...
    warning: already initialized constant SOME_CONSTANT_NAME

Removing the `ActiveSupport` warning is quite easy with `ActiveSupport::Deprecation.silenced = true`.

How do I prevent the already initialized constant warnings as part of my `spec` command? Or through creating another `spec` file that can suppress such warnings. Keep in mind that these warnings are from gem files, therefore I cannot go into those files and surround them with `Kernel.silence_warnings`.


**Note:**
I understand that suppressing warnings are bad. However, when I run a single `spec` from within `vim` it would be nice if the warnings didn&#39;t clutter my screen.

Suppress Ruby warnings when running specs

How do I write a file on iOS? I&#39;m trying to do it with the following code but I&#39;m doing something wrong:

    char *saves = &quot;abcd&quot;;
    NSData *data = [[NSData alloc] initWithBytes:saves length:4]; 
    NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    NSString *documentsDirectory = [paths objectAtIndex:0];
    NSString *appFile = [documentsDirectory stringByAppendingPathComponent:@&quot;MyFile&quot;];
    [data writeToFile:appFile atomically:YES];


I have created MyFile.txt on resources.


Write a file on iOS

In my app the user is to select an audio file which the app then handles. The problem is that in order for the app to do what I want it to do with the audio files, I need the URI to be in file format. When I use Android&#39;s native music player to browse for the audio file in the app, the URI is a content URI, which looks like this:

    content://media/external/audio/media/710

However, using the popular file manager application Astro, I get the following:

    file:///sdcard/media/audio/ringtones/GetupGetOut.mp3

The latter is much more accessible for me to work with, but of course I want the app to have functionality with the audio file the user chooses regardless of the program they use to browse their collection. So my question is, is there a way to convert the `content://` style URI into a `file://` URI? Otherwise, what would you recommend for me to solve this problem? Here is the code which calls up the chooser, for reference:

    Intent ringIntent = new Intent();
    ringIntent.setType(&quot;audio/mp3&quot;);
    ringIntent.setAction(Intent.ACTION_GET_CONTENT);
    ringIntent.addCategory(Intent.CATEGORY_OPENABLE);
    startActivityForResult(Intent.createChooser(ringIntent, &quot;Select Ringtone&quot;), SELECT_RINGTONE);

I do the following with the content URI:

    m_ringerPath = m_ringtoneUri.getPath();
    File file = new File(m_ringerPath);

Then do some FileInputStream stuff with said file.

Android: Getting a file URI from a content URI?

I have a requirement where I need to download a PDF from the website. The PDF needs to be generated within the code, which I thought would be a combination of freemarker and a PDF generation framework like iText. Any better way? 

However, my main problem is how do I allow the user to download a file through a Spring Controller?

Downloading a file from spring controllers

I need to create a list with all names of the files in a folder.

For example, if I have:

    000.jpg
    012.jpg
    013.jpg

I want to store them in a `ArrayList` with `[000,012,013]` as values.

What&#39;s the best way to do it in Java ?

PS: I&#39;m on Mac OS X

Getting the filenames of all files in a folder

I would like to get a list of files with a specific extension in a directory. In the API (Java 6), I see a method `File.listFiles(FileFilter)` which would do this.

Since I need a specific extension, I created a `FileNameExtensionFilter`. However I get a compilation error when I use `listFiles` with this. I assumed that since `FileNameExtensionFilter implements FileFilter`, I should be able to do this. Code follows:

    FileNameExtensionFilter filter = new FileNameExtensionFilter(&quot;text only&quot;,&quot;txt&quot;);
    String dir  = &quot;/users/blah/dirname&quot;;
    File f[] = (new File(dir)).listFiles(filter);

The last line shows a compilation error:

&gt; method listFiles(FileNameFilter) in type File is not applicable for arguments of type FileNameExtensionFilter

I am trying to use `listFiles(FileFilter)`, not `listFiles(FileNameFilter)`. Why does the compiler not recognize this?

This works if I write my own extension filter extending `FileFilter`. I would rather use `FileNameExtensionFilter` than write my own. What am I doing wrong?

Using File.listFiles with FileNameExtensionFilter

I want to use ls in windows command prompt and make it run the dir command.

How can I do that?

How to create ls in windows command prompt?

I tried searching for a command that could list all the file in a directory as well as subfolders using a command prompt command.
I have read the help for &quot;dir&quot; command but coudn&#39;t find what I was looking for.
Please help me what command could get this.



Command to list all files in a folder as well as sub-folders in windows

I&#39;ve been searching for the accurate answer to this question for a couple of days now but haven&#39;t got anything good. I&#39;m not a complete beginner in programming, but not yet even on the intermediate level.

When I&#39;m in the shell of Python, I type: `dir()` and I can see all the names of all the objects in the current scope (main block), there are 6 of them:

    [&#39;__builtins__&#39;, &#39;__doc__&#39;, &#39;__loader__&#39;, &#39;__name__&#39;, &#39;__package__&#39;, &#39;__spec__&#39;]

Then, when I&#39;m declaring a variable, for example `x = 10`, it automatically adds to that lists of objects under built-in module `dir()`, and when I type `dir()` again, it shows now:

    [&#39;__builtins__&#39;, &#39;__doc__&#39;, &#39;__loader__&#39;, &#39;__name__&#39;, &#39;__package__&#39;, &#39;__spec__&#39;, &#39;x&#39;]

The same goes for functions, classes and so on.  

How do I delete all those new objects without erasing the standard 6 which where available at the beginning?

I&#39;ve read here about &quot;memory cleaning&quot;, &quot;cleaning of the console&quot;, which erases all the text from the command prompt window:  

    &gt;&gt;&gt; import sys
    &gt;&gt;&gt; clear = lambda: os.system(&#39;cls&#39;)
    &gt;&gt;&gt; clear()

But all this has nothing to do with what I&#39;m trying to achieve, it doesn&#39;t clean out all used objects.


Is there a way to delete created variables, functions, etc from the memory of the interpreter?

I want to use `__dir__`.

However, I can&#39;t find any good tutorial on how to set it up. I have my htdocs in Dropbox.

Does it work something like this?
     
     define(__DIR___, &#39;d:documents/dropbox/yolo/swag/htdocs/myproject/test/newtest/
     testphp/test_new/testincludes/1/new_folder/&#39;)

That is the directory where my project is located and it has sub folders. I want to include a file into another file that is in the parent folder.

Should I then just type:
     
     include&#39;__DIR__/warlock.php&#39;; 

Or do I have to type something like this?
     
     include &#39;___DIR__/wow/newb/guidesfornabz/classes/casters/warlock.php&#39;; 

Content Type	Original Author	Original Content on Stackoverflow
Question	delete	View Question on Stackoverflow
Solution 1 - Ruby	Mat	View Answer on Stackoverflow
Solution 2 - Ruby	Preacher	View Answer on Stackoverflow
Solution 3 - Ruby	boulder_ruby	View Answer on Stackoverflow
Solution 4 - Ruby	Steve	View Answer on Stackoverflow
Solution 5 - Ruby	Nicola Mingotti	View Answer on Stackoverflow

How to rename a file in Ruby?

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Securing an API: SSL & HTTP Basic Authentication vs Signature

batch file for loop with spaces in dir name

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