How to remove new line characters from a string?

I have a string in the following format

string s = "This is a Test String.\n   This is a next line.\t This is a tab.\n'

I want to remove all the occurrences of \n and \r from the string above.

I have tried string s = s.Trim(new char[] {'\n', '\r'}); but it didn't help.

I like to use regular expressions. In this case you could do:

string replacement = Regex.Replace(s, @"\t|\n|\r", "");

Regular expressions aren't as popular in the .NET world as they are in the dynamic languages, but they provide a lot of power to manipulate strings.

You want to use String.Replace to remove a character.

s = s.Replace("\n", String.Empty);
s = s.Replace("\r", String.Empty);
s = s.Replace("\t", String.Empty);

Note that String.Trim(params char[] trimChars) only removes leading and trailing characters in trimChars from the instance invoked on.

You could make an extension method, which avoids the performance problems of the above of making lots of temporary strings:

static string RemoveChars(this string s, params char[] removeChars) {
    Contract.Requires<ArgumentNullException>(s != null);
    Contract.Requires<ArgumentNullException>(removeChars != null);
    var sb = new StringBuilder(s.Length);
    foreach(char c in s) { 
        if(!removeChars.Contains(c)) {
            sb.Append(c);
        }
    }
    return sb.ToString();
}

I know this is an old post, however I thought I'd share the method I use to remove new line characters.

s.Replace(Environment.NewLine, "");

References:

MSDN String.Replace Method and MSDN Environment.NewLine Property

If speed and low memory usage are important, do something like this:

var sb = new StringBuilder(s.Length);

foreach (char i in s)
    if (i != '\n' && i != '\r' && i != '\t')
        sb.Append(i);

s = sb.ToString();

just do that

s = s.Replace("\n", String.Empty).Replace("\t", String.Empty).Replace("\r", String.Empty);

A LINQ approach:

string s = "This is a Test String.\n   This is a next line.\t This is a tab.\n'";

string s1 = String.Join("", s.Where(c => c != '\n' && c != '\r' && c != '\t'));

The right choice really depends on how big the input string is and what the perforce and memory requirement are, but I would use a regular expression like

string result = Regex.Replace(s, @"\r\n?|\n|\t", String.Empty);

Or if we need to apply the same replacement multiple times, it is better to use a compiled version for the Regex like

var regex = new Regex(@"\r\n?|\n|\t", RegexOptions.Compiled); 
string result = regex.Replace(s, String.Empty);

NOTE: different scenarios requite different approaches to achieve the best performance and the minimum memory consumption

Well... I would like you to understand more specific areas of space. \t is actually assorted as a horizontal space, not a vertical space. (test out inserting \t in Notepad)

If you use Java, simply use \v. See the reference below.

> \h - A horizontal whitespace character: > > [\t\xA0\u1680\u180e\u2000-\u200a\u202f\u205f\u3000] > > \v - A vertical whitespace character: > > [\n\x0B\f\r\x85\u2028\u2029]

But I am aware that you use .NET. So my answer to replacing every vertical space is..

string replacement = Regex.Replace(s, @"[\n\u000B\u000C\r\u0085\u2028\u2029]", "");

string remove = Regex.Replace(txtsp.Value).ToUpper(), @"\t|\n|\r", "");

You can use Trim if you want to remove from start and end.

string stringWithoutNewLine = "\n\nHello\n\n".Trim();

FYI,

Trim() does that already.

The following LINQPad sample:

void Main()
{
	var s = " \rsdsdsdsd\nsadasdasd\r\n ";
	s.Length.Dump();
	s.Trim().Length.Dump();
}

Outputs:

23
18