How to push both key and value into an Array in Jquery

JqueryArraysKey Value

Jquery Problem Overview


I am reading RSS feed and pushing both Title and Link into an Array in Jquery.

What i did is

var arr = [];
            
            $.getJSON("displayjson.php",function(data){
                $.each(data.news, function(i,news){
                    var title = news.title;
                    var link = news.link;
                    arr.push({title : link});
                });                      
            });

And i am reading that array again using

$('#show').click(function(){
                $.each(arr, function(index, value){
                    alert( index +' : '+value);
                });
            });

But it Giving me Output as

1:[Object Object]
2:[Object Object]
3:[Object Object]

like this ...

How i can get both tile and link as a pair ( title as key and link as value)

Jquery Solutions


Solution 1 - Jquery

There are no keys in JavaScript arrays. Use objects for that purpose.

var obj = {};

$.getJSON("displayjson.php",function (data) {
    $.each(data.news, function (i, news) {
        obj[news.title] = news.link;
    });                      
});

// later:
$.each(obj, function (index, value) {
    alert( index + ' : ' + value );
});

In JavaScript, objects fulfill the role of associative arrays. Be aware that objects do not have a defined "sort order" when iterating them (see below).

However, In your case it is not really clear to me why you transfer data from the original object (data.news) at all. Why do you not simply pass a reference to that object around?


You can combine objects and arrays to achieve predictable iteration and key/value behavior:

var arr = [];

$.getJSON("displayjson.php",function (data) {
    $.each(data.news, function (i, news) {
        arr.push({
            title: news.title, 
            link:  news.link
        });
    });                      
});

// later:
$.each(arr, function (index, value) {
    alert( value.title + ' : ' + value.link );
});

Solution 2 - Jquery

This code

var title = news.title;
var link = news.link;
arr.push({title : link});

is not doing what you think it does. What gets pushed is a new object with a single member named "title" and with link as the value ... the actual title value is not used. To save an object with two fields you have to do something like

arr.push({title:title, link:link});

or with recent Javascript advances you can use the shortcut

arr.push({title, link}); // Note: comma "," and not colon ":"

If instead you want the key of the object to be the content of the variable title you can use

arr.push({[title]: link}); // Note that title has been wrapped in brackets

Solution 3 - Jquery

I think you need to define an object and then push in array

var obj = {};
obj[name] = val;
ary.push(obj);

Solution 4 - Jquery

arr[title] = link;

You're not pushing into the array, you're setting the element with the key title to the value link. As such your array should be an object.

Solution 5 - Jquery

You might mean this:

var unEnumeratedArray = [];
var wtfObject = {
                 key    : 'val', 
                 0      : (undefined = 'Look, I\'m defined'),
                 'new'  : 'keyword', 
                 '{!}'  : 'use bracket syntax',
                 '        ': '8 spaces'
                };

for(var key in wtfObject){
    unEnumeratedArray[key] = wtfObject[key];
}
console.log('HAS KEYS PER VALUE NOW:', unEnumeratedArray, unEnumeratedArray[0], 
             unEnumeratedArray.key, unEnumeratedArray['new'], 
             unEnumeratedArray['{!}'], unEnumeratedArray['        ']);

You can set an enumerable for an Object like: ({})[0] = 'txt'; and you can set a key for an Array like: ([])['myKey'] = 'myVal';

Hope this helps :)

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionKillerFishView Question on Stackoverflow
Solution 1 - JqueryTomalakView Answer on Stackoverflow
Solution 2 - Jquery6502View Answer on Stackoverflow
Solution 3 - JqueryJaydeep PatelView Answer on Stackoverflow
Solution 4 - JquerydecezeView Answer on Stackoverflow
Solution 5 - JqueryCodyView Answer on Stackoverflow