How to properly add 1 month from now to current date in moment.js
Javascriptnode.jsDateMomentjsJavascript Problem Overview
I read the documentation of moment.js that if you want to add 1 month from the current date time you use this code
var moment = require('moment');
var futureMonth = moment().add(1, 'M').format('DD-MM-YYYY');
But the problem right now, it is not properly add the date correctly, for example let say the current date is 31/10/2015, explain in code
var currentDate = moment().format('DD-MM-YYYY');
var futureMonth = moment().add(1, 'M').format('DD-MM-YYYY');
console.log(currentDate) // Will result --> 31/10/2015
console.log(futureMonth) // Will result --> 30/11/2015
if you take a look at the current calendar time, 1 month from 31/10/2015
supposed to be 1/12/2015
Could anyone give me some opinion on how to fix this problem.
Thank you
Javascript Solutions
Solution 1 - Javascript
var currentDate = moment('2015-10-30');
var futureMonth = moment(currentDate).add(1, 'M');
var futureMonthEnd = moment(futureMonth).endOf('month');
if(currentDate.date() != futureMonth.date() && futureMonth.isSame(futureMonthEnd.format('YYYY-MM-DD'))) {
futureMonth = futureMonth.add(1, 'd');
}
console.log(currentDate);
console.log(futureMonth);
EDIT
moment.addRealMonth = function addRealMonth(d) {
var fm = moment(d).add(1, 'M');
var fmEnd = moment(fm).endOf('month');
return d.date() != fm.date() && fm.isSame(fmEnd.format('YYYY-MM-DD')) ? fm.add(1, 'd') : fm;
}
var nextMonth = moment.addRealMonth(moment());
Solution 2 - Javascript
> According to the latest doc you can do the following-
Add a day
moment().add(1, 'days').calendar();
Add Year
moment().add(1, 'years').calendar();
Add Month
moment().add(1, 'months').calendar();
Solution 3 - Javascript
startDate = "20.03.2020";
var newDate = moment(startDate, "DD-MM-YYYY").add(5, 'days');
console.log(newDate)
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>
Solution 4 - Javascript
You could try
moment().add(1, 'M').subtract(1, 'day').format('DD-MM-YYYY')