How to print current date on python3?

From what I gather, here (for example), this should print the current year in two digits

print (datetime.strftime("%y"))

However, I get this error

TypeError: descriptor 'strftime' requires a 'datetime.date' object but received a 'str'

So I tried to this

print (datetime.strftime(datetime.date()))

to get

TypeError: descriptor 'date' of 'datetime.datetime' object needs an argument

so I placed "%y" inside of thr date() above to get

TypeError: descriptor 'date' requires a 'datetime.datetime' object but received a 'str'

Which start to seem really loopy and fishy to me.

What am I missing?

import datetime
now = datetime.datetime.now()

print(now.year)

The above code works perfectly fine for me.

The following seems to work:

import datetime
print (datetime.datetime.now().strftime("%y"))

The datetime.data object that it wants is on the "left" of the dot rather than the right. You need an instance of the datetime to call the method on, which you get through now()

I use this which is standard for every time

import datetime
now = datetime.datetime.now()
print ("Current date and time : ")
print (now.strftime("%Y-%m-%d %H:%M:%S"))

This function allows you to get the date and time in lots of formats (see the bottom of this post).

# Get the current date or time
def getdatetime(timedateformat='complete'):
    from datetime import datetime
    timedateformat = timedateformat.lower()
    if timedateformat == 'day':
        return ((str(datetime.now())).split(' ')[0]).split('-')[2]
    elif timedateformat == 'month':
        return ((str(datetime.now())).split(' ')[0]).split('-')[1]
    elif timedateformat == 'year':
        return ((str(datetime.now())).split(' ')[0]).split('-')[0]
    elif timedateformat == 'hour':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[0]
    elif timedateformat == 'minute':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[1]
    elif timedateformat == 'second':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[2]
    elif timedateformat == 'millisecond':
        return (str(datetime.now())).split('.')[1]
    elif timedateformat == 'yearmonthday':
        return (str(datetime.now())).split(' ')[0]
    elif timedateformat == 'daymonthyear':
        return ((str(datetime.now())).split(' ')[0]).split('-')[2] + '-' + ((str(datetime.now())).split(' ')[0]).split('-')[1] + '-' + ((str(datetime.now())).split(' ')[0]).split('-')[0]
    elif timedateformat == 'hourminutesecond':
        return ((str(datetime.now())).split(' ')[1]).split('.')[0]
    elif timedateformat == 'secondminutehour':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[2] + ':' + (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[1] + ':' + (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[0]
    elif timedateformat == 'complete':
        return str(datetime.now())
    elif timedateformat == 'datetime':
        return (str(datetime.now())).split('.')[0]
    elif timedateformat == 'timedate':
        return ((str(datetime.now())).split('.')[0]).split(' ')[1] + ' ' + ((str(datetime.now())).split('.')[0]).split(' ')[0]

To obtain the time or date, just use getdatetime("<TYPE>"), replacing <TYPE> with one of the following arguments:

> All example outputs use this model information: 25-11-2017 03:23:56.477017

Argument	Meaning	Example output
day	Get the current day	25
month	Get the current month	11
year	Get the current year	2017
hour	Get the current hour	03
minute	Get the current minute	23
second	Get the current second	56
millisecond	Get the current millisecond	477017
yearmonthday	Get the year, month and day	2017-11-25
daymonthyear	Get the day, month and year	25-11-2017
hourminutesecond	Get the hour, minute and second	03:23:56
secondminutehour	Get the second, minute and hour	56:23:03
complete	Get the complete date and time	2017-11-25 03:23:56.477017
datetime	Get the date and time	2017-11-25 03:23:56
timedate	Get the time and date	03:23:56 2017-11-25

I always use this code, which print the year to second in a tuple

import datetime

now = datetime.datetime.now()

time_now = (now.year, now.month, now.day, now.hour, now.minute, now.second)

print(time_now)