How to print a linebreak in a python function?
PythonLine BreaksPython Problem Overview
I have a list of strings in my code;
A = ['a1', 'a2', 'a3' ...]
B = ['b1', 'b2', 'b3' ...]
and I want to print them separated by a linebreak, like this:
>a1
b1
>a2
b2
>a3
b3
I've tried:
print '>' + A + '/n' + B
But /n isn't recognized like a line break.
Python Solutions
Solution 1 - Python
You have your slash backwards, it should be "\n"
Solution 2 - Python
The newline character is actually '\n'.
Solution 3 - Python
>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']
>>> for x in A:
for i in B:
print ">" + x + "\n" + i
Outputs:
>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3
Notice that you are using /n which is not correct!
Solution 4 - Python
All three way you can use for newline character :
'\n'
"\n"
"""\n"""
Solution 5 - Python
for pair in zip(A, B):
print ">"+'\n'.join(pair)
Solution 6 - Python
\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.
Solution 7 - Python
You can print a native linebreak using the standard os library
import os
with open('test.txt','w') as f:
f.write(os.linesep)
Solution 8 - Python
Also if you're making it a console program, you can do: print(" ") and continue your program. I've found it the easiest way to separate my text.
Solution 9 - Python
A = ['a1', 'a2', 'a3']
B = ['b1', 'b2', 'b3']
for a,b in zip(A,B):
print(f">{a}\n{b}")
Below python 3.6 instead of print(f">{a}\n{b}") use print(">%s\n%s" % (a, b))