How to pass a vector to a function?
C++FunctionVectorC++ Problem Overview
I'm trying to send a vector as an argument to a function and i can't figure out how to make it work. Tried a bunch of different ways but they all give different error messages. I only include part of the code, since it's only this part that doesn't work. (the vector "random" is filled with random, but sorted, values between 0 and 200)
Updated the code:
#include <iostream>
#include <ctime>
#include <algorithm>
#include <vector>
using namespace std;
int binarySearch(int first, int last, int search4, vector<int>& random);
int main()
{
vector<int> random(100);
int search4, found;
int first = 0;
int last = 99;
found = binarySearch(first, last, search4, random);
system("pause");
return(0);
}
int binarySearch(int first, int last, int search4, vector<int>& random)
{
do
{
int mid = (first + last) / 2;
if (search4 > random[mid])
first = mid + 1;
else if (search4 < random[mid])
last = mid - 1;
else
return mid;
} while (first <= last);
return -(first + 1);
}
C++ Solutions
Solution 1 - C++
It depends on if you want to pass the vector
as a reference or as a pointer (I am disregarding the option of passing it by value as clearly undesirable).
As a reference:
int binarySearch(int first, int last, int search4, vector<int>& random);
vector<int> random(100);
// ...
found = binarySearch(first, last, search4, random);
As a pointer:
int binarySearch(int first, int last, int search4, vector<int>* random);
vector<int> random(100);
// ...
found = binarySearch(first, last, search4, &random);
Inside binarySearch
, you will need to use .
or ->
to access the members of random
correspondingly.
Issues with your current code
binarySearch
expects avector<int>*
, but you pass in avector<int>
(missing a&
beforerandom
)- You do not dereference the pointer inside
binarySearch
before using it (for example,random[mid]
should be(*random)[mid]
- You are missing
using namespace std;
after the<include>
s - The values you assign to
first
andlast
are wrong (should be 0 and 99 instead ofrandom[0]
andrandom[99]
Solution 2 - C++
You'll have to pass the pointer to the vector, not the vector itself. Note the additional '&' here:
found = binarySearch(first, last, search4, &random);
Solution 3 - C++
You're passing in a pointer *random
but you're using it like a reference &random
The pointer (what you have) says "This is the address in memory that contains the address of random"
The reference says "This is the address of random"
Solution 4 - C++
Anytime you're tempted to pass a collection (or pointer or reference to one) to a function, ask yourself whether you couldn't pass a couple of iterators instead. Chances are that by doing so, you'll make your function more versatile (e.g., make it trivial to work with data in another type of container when/if needed).
In this case, of course, there's not much point since the standard library already has perfectly good binary searching, but when/if you write something that's not already there, being able to use it on different types of containers is often quite handy.
Solution 5 - C++
found = binarySearch(first, last, search4, &random);
Notice the &
.
Solution 6 - C++
You're using the argument as a reference but actually it's a pointer. Change vector<int>*
to vector<int>&
. And you should really set search4
to something before using it.
Solution 7 - C++
If you use random
instead of * random
your code not give any error